# XHOSA BABY NAMES BOYS AND GIRLS - Computers & Internet

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Hi,
A 6ya expert can help you resolve that issue over the phone in a minute or two.
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Posted on Jan 02, 2017

The best way to solve this is to develop one or more equations and then solve for the unknown numbers.

I solved this problem twice using different sets of equations to make sure I was right, and here is what I found:

1) I used the equations x + y = 623, and x = (2/3)y. In these equations, x is the number of girls and y is the number of boys.
Substituting the second equation into the first, I get (2/3)y + y = 623.
Adding the left side together I get : (5/3)y = 623.
Dividing both sides by (5/3) I get 373.8.
This means that x (the number of girls) is 249.2.

2) For the second attempt, I developed the equation: 2x+3x=623. Here 2x is the number of girls, and 3x is the number of boys.
Adding the left side I get: 5x = 623.
Dividing both sides by 5 I get: x = 124.6.
This means that the number of girls (2x) is 249.2. Just like in the first method.

But since you can't have a 1/5 of a girl, the answer must be 249 girls.

Posted on Nov 19, 2009

If there are 25 boy in a class of 40 pupils, there are 40 - 25 = 15 girls. The ratio of boys to girls hence is 25:15, or as reduced fraction 5:3 = 1.6666...

Posted on Jan 16, 2011

If there are 40 total students, and 25 are boys, then (40-25) of them are girls, or 15.
That means the ratio of boys to girls is 25 to 15, or 25/15
This can be simplified by dividing by 5, so the ratio is 5/3

Posted on Jan 16, 2011

SOURCE: If a high school graduating

142.

435 - 151 = 284
This subtracts the inequality between girls and boys.

Then the rest are split in half equally.

284 / 2 = 141

Hope this helps. Got any more ;)

Posted on Feb 16, 2011

SOURCE: 7 letter word _R_K_S_ 7

PREKISS
This is the only solution I guess

Posted on Jul 28, 2011

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