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A rectangle has verticles at (0,-2),(0,3),(3,-2)and (3,3). What are the coordinates of the verticles of the image after the translation (x,y) (x-6,y-3) describe the translation
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Translate the English into Mathematics. W=L-5 (in inches) P=2(L+W)=2(L+L-5)=2(2L-5) Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets) P=4L-10. Set P= 50 (inches), to get 4L-10=50 Solve for L: Do it'! Find W= L (the one you just found) -5 =
Now, with W the value you just calculated the new length is L'=-4+3W and the new perimeter is P'=2(L'+W)
When using the ADF if the glass has dirt on it, as the paper moves over the glass the image is written to the moving paper.
The paper is also moving over the dirt specs on the glass causing verticle black lines.
It is hard to explain without actually showing you.
To fix the problem, lift up the top to expose the glass.
Look to the left of the big rectangle glass. There will be a 3/4 inch glass strip. CLEAN IT.
Use the definition of the rate of change (or slope). Let two points be given by the coordinates P_1(x_1, y_1), and P_2(x_2,y_2). The rate of change between the two points is given by a=(y_2-y_1)/(x_2-x_1) In MathIO, press the fraction button. Enter y_2-y_1 in the upper rectangle (numerator) the enter x_2-x_1 in the lower rectangle. When finished press [=]
Whenever talking about coordinates, the first number is the x-axis (left to right --> move right for a positive number, left for a negative number). The second number is the y-axis (up & down: --> up for positive numbers, down for negative numbers). All coordinates start from zero, so for your parallelogram:
W is 2 left then 2 up X is 2 right then 3 up Y is 2 right then stop Z is 2 left then 1 down
Translating your parallelogram, just means (in this case) to move the whole thing 3 to the left and 2 down.
X starts at (2,3), so moving it 3 to the left will leave it at (-1, 3). Then we move it 2 down, so it's final position is at (-1, 1)
Simply just manualy adjust the bottom of the screen by adjusting the distance by an inch or so.
Depending on what screen you have adjust it from behind or vith a thin thread
It would be "cheating" for anybody to do your "homework" from your computer-mathematics class, unless you submit your answer, saying that an EXPERT on FIXYA did all the work on your behalf.
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