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What is the sum of 2/5 and 5/2 ? - Computers & Internet

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2/5 + 5/2 = 29/10 (2.9)

Posted on Apr 05, 2015

  • Mike Tellegen Apr 07, 2015

    How did you get 29?

  • terry stevens Apr 08, 2015

    If you had 2/5 of a dollar you would have 40 cents and 5/2 of a dollar is $2.50 add that up gives you $2.90 change that to fractions is 29 ten cent pieces so your answer is 2.9 dollars.

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1/2 + 1/5 = 2/5

Posted on Apr 05, 2015

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1 Answer

What is sum in math


The sum is the result of adding two or more things together. The things don't have to be numbers, they can be vectors, matrices, polynomials, or other things.

For the other part of your question, the sum of 838 and 2 is 840.

Jan 19, 2014 | Computers & Internet

1 Answer

What is the perimeter of a 1 x 3 rectangle?


Rectangle has two pairs of equal sides.
L=length=3 units
w=width =1 unit
Perimeter = sum of the measures of all sides.
2 sides with measure L: sum of lengths=2*L
2 sides with measure w: sum of widths=2*w
Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Mathsoft StudyWorks! Mathematics Deluxe...

1 Answer

Perimeter of a 1 x 3 rectangle


Rectangle has two pairs of equal sides.
L=length=3 units
w=width =1 unit
Perimeter = sum of the measures of all sides.
2 sides with measure L: sum of lengths=2*L
2 sides with measure w: sum of widths=2*w
Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Computers & Internet

1 Answer

How to write formula in excel - up to 5000 10 above 5000 20%


if(sum($D$d:$D$16)<=5000,500,sum($D$5:$D$16)*.2)

Where the cells to be summed are D5 through D16.

Aug 25, 2012 | Computers & Internet

1 Answer

Find the sum of all integer multiples of 8 between 33 and 3051.


This sum is equal to 40+48+56+64+72+...+3024+3032+3040+3048= 40+(48+3048)+(56+3040)+(64+3032)+(72+3024)...
There are (3048-40)/8+1=377 terms in sum. (48+3048)=(56+3040)=(64+3032)=(72+3024)=3096 and there are (377-1)/2=188 pairs whose sum is 3096. Only term that is not in such pair is 40.
Finally sum is 40+188*3096=582088.

Jul 01, 2011 | Computers & Internet

1 Answer

Sum to n terms of the series 1+5+12+22..........


You did not provide a general (n) term. However, I figured it to be something involving n^2. Hence the sum to n terms can be of the form: xn^3 + yn^2 + zn. Using the partial sums: 1, 6 (1+5), and 18 (1+5+12) we can build a linear equations system:
1= x + y +z (n=1)
6 = 8x + 4y +2z (n=2, n^2=4, n^3 = 8)
18 = 27x + 9y + 3z (n=3, n^=9, n^=27)
Solving for x,y,z we get x = 1/2, y= 1/2, z =0
Hence 1+5+12+22+..+ f(n^2)= 1/2(n^3+n^2)

Nov 04, 2010 | Refrigerators

1 Answer

Pls. help me


Q.2#  Dim n, sum as Double
Dim i as Integer
n=100
sum=0

for i=1 to n
sum=sum+1/n
next i

Q.3#  Dim sum as Double
sum=0
for i=1 to 99
if i%2 <> 0 then sum=sum+i end if
next i

Sep 16, 2008 | Microsoft AccRepair DS2 2004 for Fr...

1 Answer

Read n & m, display the sum of all the even and odd numbers between n to m.


#include <stdio.h>

int main()
{
int n1, n2, i;
int sum = 0;
n1 = 3;
n2 = 11;

for (i = n1; i <= n2; i++) {
if (i % 2 == 0) {
printf("Adding %d\n", i);
sum = sum + i;
}
}
printf("sum = %d\n", sum);
return 0;
}

Feb 21, 2008 | Computers & Internet

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