Question about Bagatrix Algebra Solved! 2005 (105101) for PC

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8x + 3y = 3 4x + 5y = -23

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This is best written as two separate equations:

8x+3y = -23 and 34x+ 5y = -23
Solving the first one for x:
8x = -23-3y
x = -23/8 - 3/8y
Substituting this value for x into the second equation:
34(-23/8 - 3/8y) + 5y = -23
-97.75 - (34)(.375)y + 5y = -23
-97.75 - 12.75y + 5y = -23
-97.75 -7.75y = -23
-7.75y = 97.75-23=74.75
y = -74.75/7.75 = -9.645161
Substitution back into the equation for x:
x = -23/8 - 3/8(-9.645161)
x = -2.875 + 3.616935
x =.741935

Posted on Dec 13, 2014

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2x plus 5y equals 7 3x plus 6y equals 3


1) 2x + 5y = 7
2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.
Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21
2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15
---- ----
3 3 divide both sides by 3 to get y by itself.
y =5.
Substitute into 1) to calculate x.
2x + 5(5) = 7
2x + 25 = 7
2x + 25 -25 = 7 - 25
2x = -18
---- ----- divide both sides by 2 to get x by itself
2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3
-27 + 30 = 3
3 = 3
We did it correctly and checked to prove that we did it right.

Good luck.

Paul

Mar 12, 2015 | Office Equipment & Supplies

1 Answer

8x +5y=-25 what is the value of x?


There are an infinite number of solutions. The equation is that of a straight line, which has an infinite number of points. At any point on the line there is a unique value of x.

Nov 06, 2014 | Office Equipment & Supplies

1 Answer

What ia the sulution of 3y-6x=-3


To find the solution, first find the value of y for each equation.
Then substitue one equation into the other so that you only the x variable left.
Then just solve for x.
Once you have a value for x, then you can easily solve for y.


So for the first equation:

3y - 6x = -3
3y = 6x - 3

y = 2x - 1


Now for the second equation:

2y + 8x = 10
2y = -8x + 10

y = -4x + 5

Since both equations equal y, they also equal each other, therefore:

2x - 1 = -4x + 5

Now just solve for x:

2x + 4x = 5 + 1
6x = 6

x=1

Now substitute x=1 into either original equation:

y = 2x - 1
y = 2 (1) - 1
y = 2 - 1

y = 1


Therefore the solution is x=1 and y=1



Good luck, I hope that helps.


Joe.

Nov 09, 2011 | Texas Instruments TI-84 Plus Silver...

2 Answers

Tom is 5 times as old as todd.In seven years Tom's age will be 6 years more than 3 times as old as Todd. How old is Todd


Todd is 4 years old.

Let Tom's age = X
Let Todd's age = Y

From the given facts:

X = 5Y

and

X + 7 + 6 = 3 ( Y + 7 )
X+13 = 3Y + 21
X = 3Y + 8

So if:
X=5Y
and
X=3Y+8

Then:
5Y=3Y+8
2Y=8
Y=4

I hope that helps.

Joe.

Sep 14, 2011 | Office Equipment & Supplies

1 Answer

How do i solve for the solutions to the simultaneous linear equations on the fx-115es? I don't know how to set up the calculator to do it. 10x-3y+10z=5 8x-2y+9z=3 8x+y-10z=7


Select the EQN computational mode 5:EQN
6_29_2011_11_01_40_pm.jpg
For system of linear equations in 3 unknowns select 2: in the screen below.
6_29_2011_11_02_20_pm.jpg
Arrange the variables in your equations in the same order (x first, y second, and z third).
The coefficients to enter in the editor are the factors of the variables: In your case a_1=10, b_1=-3, c_1=10, d_1=5, a_2=8, b_2=-2, c_2=9, d_2=3; a_3=8, b_3=1, c_3=-10, d_3=7.
To enter d_1, d_2, and d_3 you will have to scroll to the right to reach the cells where they should go.
6_29_2011_11_04_19_pm.jpg
Once finished entering the coefficients, press EXE to get the solutions. You may have to use the arrow Down to display the y- and z-solutions.
I verified that the matrix is non-singular and the system has a solution. In fraction form
x=27/53, y=-1 and 22/53; finally z=-23/53

Jun 29, 2011 | Casio FX-115ES Scientific Calculator

2 Answers

Heena has only rs 2 and rs 5 coins,in her purse. if in all she has 80 coins in her purse amounting to rs 232. find the number of rs 5 coin.


Is this a maths school problem?
You need to use algebra -
2x + 5y = 232 (heena has a number of 2 and 5 coins in her purse which add up to 232)
x + y = 80 (heena has x number of 2 and y number of 5 coins which tally to 80)
therefore, x = 80 - y
so going back to first equation, 2(80 - y) + 5y = 232
160 - 2y + 5y = 232
3y = 72
y = 24
and going back to x, x = 80 - y
x = 80 - 24
x = 56
so heena has 56 rs 2, and 24 rs 5. So the answer is 24.

Jan 26, 2011 | Computers & Internet

1 Answer

1-2/3y=9/5-1/5y+3/4


if you are looking for the answer, then here it is. Jenny gets 8 inches then Demi gets 4 inches then Drew gets 6 inches.

May 25, 2010 | Texas Instruments TI-30XA Calculator

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Your friend John asks you for advice concerning life insurance. John is 32 years old and graduated from law school last year. he currently earns $48,000 per year as a first year attorney. John is married and has two children, Billy, age 10, and Sarah, age 4. John's wife, Mary, is a professor who currently earns $58,000 per year. Mary is 34 years old. John and Mary pay $1,700 per month for their home mortgage, which will be paid off in 20 years. The interest rate on their mortgage is 4.5%. (Their current equity in the home is $75,000.) The couple owns two cars, both 8 years old, and personal property (such as clothes, electronics, furniture, etc.) values at $45,000. Their investments have been used up paying for John's law school education, so they currently have only $1,000 in savings and checking accounts, and $2,000 in a mutual fund. John has no life insurance. Mary has $100,000 of life insurance provided by her employer. mary's pension plus social security are expected to total $45,000 per year, beginning when she is 67 years old. If John should die, Mary would receive approximately $10,000 per year from social security until Sarah reaches age 18. John and Mary spend most of their current income, although they do try to save about $50 per month. Their investments earn approximately 5% per year. In addition to their home mortgage, John has a student loan of $15,000 that he must start making payments on in 6 months. he plans to pau back the loan in 5 years and the loan's interst rate is 6% per year. Given that Mary enjoys a flexible work schedule, and because Mary's mother lives close by and watches the kids two days per week, the currently are not paying any child care expenses.

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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Your friend John asks you for advice concerning life insurance. John is 32 years old and graduated from law school last year. he currently earns $48,000 per year as a first year attorney. John is married and has two children, Billy, age 10, and Sarah, age 4. John's wife, Mary, is a professor who currently earns $58,000 per year. Mary is 34 years old. John and Mary pay $1,700 per month for their home mortgage, which will be paid off in 20 years. The interest rate on their mortgage is 4.5%. (Their current equity in the home is $75,000.) The couple owns two cars, both 8 years old, and personal property (such as clothes, electronics, furniture, etc.) values at $45,000. Their investments have been used up paying for John's law school education, so they currently have only $1,000 in savings and checking accounts, and $2,000 in a mutual fund. John has no life insurance. Mary has $100,000 of life insurance provided by her employer. mary's pension plus social security are expected to total $45,000 per year, beginning when she is 67 years old. If John should die, Mary would receive approximately $10,000 per year from social security until Sarah reaches age 18. John and Mary spend most of their current income, although they do try to save about $50 per month. Their investments earn approximately 5% per year. In addition to their home mortgage, John has a student loan of $15,000 that he must start making payments on in 6 months. he plans to pau back the loan in 5 years and the loan's interst rate is 6% per year. Given that Mary enjoys a flexible work schedule, and because Mary's mother lives close by and watches the kids two days per week, the currently are not paying any child care expenses.

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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