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Eight times three is 24, so this is an example of an incorrect (or false) equation.

Posted on Dec 02, 2014

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Posted on Jan 02, 2017

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SOURCE: how do i solve Exponential

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Posted on Feb 06, 2011

- You have several memory locations you can use to store values in them. The memory locations are A,B,C,D, M, X, and Y. You use [SHIFT][RCL] and one of the variable names above. Example store 78 in C location: 78 [SHIFT] [RCL] [HYP]. To recall that value press [RCL] [HYP]

- If you want to use the EQN (equation solving mode, press [MODE][5:EQN] then select the equation type . For example [3:aX^2+bX+c=0] will display a template wher you input the three coefficients.

- You can also enter any type of equation and solve it with the SOLVE command. In that case you use the keyboard to enter the expression (see above how to enter variable name X). To type in the equal sign (=) use [ALPHA][ CALC]. Once the whole equation is typed in, press [SHIFT[ [SOLVE], and the calculator will prompt SOLVE for X? Confirm and press the main = sign. Press = again to get a second, a third root (if any)

Jun 06, 2012 | Casio FX-115ES Scientific Calculator

1.24274547 miles for 2 km.

8 km equells 5 miles so always multiply or divide accordingly i.e 40 km divide by 8 equells 25 miles (5 x 5) (5 eights into 40) just reverse for miles to Km. ok

8 km equells 5 miles so always multiply or divide accordingly i.e 40 km divide by 8 equells 25 miles (5 x 5) (5 eights into 40) just reverse for miles to Km. ok

Jan 04, 2012 | Motorcycles

"Twelve point zero zero three zero", "point zero zero eight one six", "three million, nine thousand, ten", "seven thousand four hundred seventy-five point eight", "P five point zero zero two five".

These are not unique. The first one, for example, could also be written as "twelve point oh oh three oh".

These are not unique. The first one, for example, could also be written as "twelve point oh oh three oh".

Jul 12, 2011 | Office Equipment & Supplies

n mathematics, an **expression** is a finite combination of symbols that are well-formed according to the rules applicable in the context at hand. Symbols can designate values (constants), variables, operations, relations, or can constitute punctuation or other syntactic entities.

Any "expression" that represents a numeric value. Example: 2+2=4 or x+7=10. Actually the examples above are equations, not expressions. Expressions do not have = signs. 7a and 4x are examples.

it is a mathematical statement e.g 7=**6+1** THE WHOLE THING IS AN EQUATION but the 6+1 is a expression.You can only have expression is there is an = sign

Yes the 6 + 1 part is an expression. Once you have an = sign or any of the other inequality symbols (,...) it is no longer an expression but a full math sentence

Any "expression" that represents a numeric value. Example: 2+2=4 or x+7=10. Actually the examples above are equations, not expressions. Expressions do not have = signs. 7a and 4x are examples.

it is a mathematical statement e.g 7=

Yes the 6 + 1 part is an expression. Once you have an = sign or any of the other inequality symbols (,...) it is no longer an expression but a full math sentence

Jun 22, 2011 | TOPICS Entertainment Elementary School...

Press the right-arrow key when you're done with the exponent to go on with the rest of the expression.

Feb 03, 2011 | Texas Instruments TI-84 Plus Calculator

The site seems to eat the plus signs I enter, so I will use PLUS to symbolize addition.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

Jan 27, 2011 | Texas Instruments TI-84 Plus Calculator

"Is there anything that I can do about this to stop my answers being complex numbers when solving cubic equations?"

You are making an assumption that is unwarranted.Namely that a cubic equation must necessarily have 3 real roots. This is not the case.

Let your equation be

If coefficients are complex you should expect some complex roots. Right?

If the coefficients are REAL then depending on the discriminant

you can have three cases

DELTA positive : three distinct real roots

DELTA=0 , the equation has a multiple root and all roots are REAL

DELTA negative: the equation has ONE real root and 2 complex roots that are complex conjugate of each other.

It suffices to look at the Tartaglia/Cardano expressions of the roots to know that more often than not there is going to be complex roots.

You are making an assumption that is unwarranted.Namely that a cubic equation must necessarily have 3 real roots. This is not the case.

Let your equation be

If coefficients are complex you should expect some complex roots. Right?

If the coefficients are REAL then depending on the discriminant

you can have three cases

DELTA positive : three distinct real roots

DELTA=0 , the equation has a multiple root and all roots are REAL

DELTA negative: the equation has ONE real root and 2 complex roots that are complex conjugate of each other.

It suffices to look at the Tartaglia/Cardano expressions of the roots to know that more often than not there is going to be complex roots.

May 05, 2010 | Casio CFX-9850G Plus Calculator

Hi,

First let us repair the terminology.

Hope it helps.

Thank you for using FixYa and for rating this solution.

First let us repair the terminology.

- You can evaluate any expression (find the value of any expression for a particular value of its variable).Store a value in the variable, say X. Key in the expression and press [EXE].
- You can consider your expression(should not contain a relational operator such as =, greater than, less than, greater than or equal to, less than or equal to) to be a function Y1(x) = expression and graph it, or generate a table for it. You will have several values of the function calculated at various points.
- You can set your expression equal to 0 and find the particular value(s) of the variable (the unknown) that make the equality TRUE. That is called solving an equation.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Nov 05, 2009 | Casio FX-7400G Plus Calculator

Hello there. This is the last time I do this.

6+x=12-x

2x=6

x=3

6+x=12-x

2x=6

x=3

Dec 03, 2008 | Computers & Internet

Since there are twelve months in a year, multiply by twelve. For example, a thirty-year mortgage involves 360 months.

Just be sure to divide the interest rate by twelve to match. For example, 6% annually is 0.5% monthly.

Just be sure to divide the interest rate by twelve to match. For example, 6% annually is 0.5% monthly.

Nov 06, 2007 | Texas Instruments TI-83 Plus Calculator

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