Logarithms etc

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Like the guy said in the above they use binary or base 2 notation . but some early computer like the Eniac could use decimal counting ( using binary coded decimal or BCD formatting ) but it was a pain to work woth it. today all computers use binary notation and have built in program to display in decimal for us.

I hope this helps.

Posted on Dec 05, 2014

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Hi John, a computer work with a binary system, bits and bytes. With electricity, it can only be on or off, charged or discharged.

All maths functions that is used in software have to be converted to the base binary system for the processor to do calculations. Does this answer your question?

If not, please elaborate on your question.

Posted on Nov 14, 2014

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Posted on Jan 02, 2017

I am not sure what model you are referring to. In general, to calculate natural logarithms you use the** ln** key. To calculate the exponential (e^x) you use [2nd] [LN] (e^x)

For decimal logarithms (logarithms in base 10) Use the [**log] **key. The inverse of the log(x) function is the power function **10^x.** To access this function , use **[2nd][log]** (10^x).

For decimal logarithms (logarithms in base 10) Use the [

Dec 25, 2013 | Texas Instruments Office Equipment &...

Using logarithms. For example, if A ^ X = 2; then X = logA(2);

This calculator only works in base-10 logarithms or natural logarithms, you should use the base conversion formula.

logA(X) = logC(X) / logC(A).

Good luck!

This calculator only works in base-10 logarithms or natural logarithms, you should use the base conversion formula.

logA(X) = logC(X) / logC(A).

Good luck!

May 02, 2011 | Texas Instruments TI-30XA Calculator

For natural logarithms, you can use the ln
function (2ND shift of the X key). For example, the natural logarithm of 3 is
2ND [LN] 3 ) ENTER.

For logarithms to other bases, use the log function (diamond shift of the 7 key). For example, the base-2 logarithm of 16 is diamond 7 1 6 , 2 ) ENTER. If the base is 10 (common logarithms), you can omit the comma and the second argument.

For logarithms to other bases, use the log function (diamond shift of the 7 key). For example, the base-2 logarithm of 16 is diamond 7 1 6 , 2 ) ENTER. If the base is 10 (common logarithms), you can omit the comma and the second argument.

Mar 09, 2011 | Texas Instruments TI-89 Calculator

That's the base for the logarithm. Logarithms are usually taken with base 10 (common logarithms, LOG on the calculator) or with base e (natural logarithms, LN on the calculator), but sometimes other bases are used.

Feb 22, 2011 | Texas Instruments TI-83 Plus Calculator

The 30XIIS does not have the capability of solving equations. It can, however, calculate expressions using logarithms. Use the LOG key for common logarithms and the LN key for natural logarithms. In both cases, press the function key, enter the value or expression, and then ) to match the ( the function automatically enters.

The LOG and LN keys are the second and third keys from the top in the leftmost column of the keyboard.

The LOG and LN keys are the second and third keys from the top in the leftmost column of the keyboard.

Nov 13, 2010 | Office Equipment & Supplies

Your calculator knows only the decimal logarithms log or log_10 and the natural logarithms (ln or log in base e).

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

Jul 18, 2010 | Casio FX-115ES Scientific Calculator

For natural logarithms, you can use the ln function (2ND shift of the X key). For example, the natural logarithm of 3 is 2ND [LN] 3 ) ENTER.

For logarithms to other bases, use the log function (diamond shift of the 7 key). For example, the base-2 logarithm of 16 is diamond 7 1 6 , 2 ) ENTER. If the base is 10 (common logarithms), you can omit the comma and the second argument.

For logarithms to other bases, use the log function (diamond shift of the 7 key). For example, the base-2 logarithm of 16 is diamond 7 1 6 , 2 ) ENTER. If the base is 10 (common logarithms), you can omit the comma and the second argument.

Apr 28, 2010 | Texas Instruments TI-89 Calculator

Hi,

Sorry to contradict you but there are many types of logarithms, the most important ones are

**[LOG]**, and the natural logarithms are labeled** [LN]**.

The inverse function of the natural log function is the exponential (e^(x)), and the inverse of the log in base ten function is the function ten to the power of. It is called (sometimes) the antilog

Ex:

Question What is the antilog of 3.5678?

Answer The antilog of 3.5678 is 10^(3.5678) = 3696.579068

Verification: log(3696.57908) =3.5678

Hope it helps.

Sorry to contradict you but there are many types of logarithms, the most important ones are

- the common logarithms (log in base 10),
- the natural logarithms (logarithms in base e)
- the binary logarithms (logarithms in base 2)

The inverse function of the natural log function is the exponential (e^(x)), and the inverse of the log in base ten function is the function ten to the power of. It is called (sometimes) the antilog

Ex:

Question What is the antilog of 3.5678?

Answer The antilog of 3.5678 is 10^(3.5678) = 3696.579068

Verification: log(3696.57908) =3.5678

Hope it helps.

Nov 29, 2009 | Texas Instruments TI-30XA Calculator

Hi,

**Logarithms in base 10 :Common logarithms**

**Logarithms in base e : Natural logarithms**

Don't forget to rate the solution and don't be stingy: 4 thumbs up won't leave you any the poorer.

- The calculator has a key labeled [LOG]. It allows you to calculate the common logarithms (logarithms in base 10).
- To calculate the common logarithm of a (positive) number you type in the number, press the [LOG] key .
- Ex: 15.32 [LOG][=] gives 1.1852558765

- The calculator has a key labeled [LN]. It allows you to calculate the natural logarithms of positive numbers.
- Ex: natural log of 15.32 is entered as
- 15.32 [LN] gives 2.729159164

Don't forget to rate the solution and don't be stingy: 4 thumbs up won't leave you any the poorer.

Nov 23, 2009 | Texas Instruments TI-36 X Solar Calculator

Hello,

You are victim of a confusion between terms. Base-n calculations are calculations using various numeration systems (bases) : binary (2), octal(8) hexadecimal (16) and decimal (10). What you want is how to calculate powers, logarithms, exponentials and these have also the notion of base; Log in base 10 is the common log, whereas natural logarithms, are logarithms in base e.

Back to your exemple: 5 times 5 and raise the whole to power 3?

In that case [(] 5 [x] 5 [)] [^] 3 or [X to the 3] if you have such key or

25 [^] 3, because 5x5 = 25

5 times (5 raised to power 3)

5[x] [( ] 5 [^] 3 [)] or 5 [^] 4 because of the rules about products of powers with the same base.

Hope it helps.

You are victim of a confusion between terms. Base-n calculations are calculations using various numeration systems (bases) : binary (2), octal(8) hexadecimal (16) and decimal (10). What you want is how to calculate powers, logarithms, exponentials and these have also the notion of base; Log in base 10 is the common log, whereas natural logarithms, are logarithms in base e.

Back to your exemple: 5 times 5 and raise the whole to power 3?

In that case [(] 5 [x] 5 [)] [^] 3 or [X to the 3] if you have such key or

25 [^] 3, because 5x5 = 25

5 times (5 raised to power 3)

5[x] [( ] 5 [^] 3 [)] or 5 [^] 4 because of the rules about products of powers with the same base.

Hope it helps.

Feb 17, 2009 | Casio FX-115MS Plus Calculator

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