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What's the standard form of 2x-8y=16 - Office Equipment & Supplies

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2x-8y-16

Posted on Nov 13, 2014

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Find the radius of the equation x^2+y^2-2x-2y=14


Try casting the equation of the circle into the form (x-h)^2+(y-k)^2=R^2. Here (h,k) would be the center and R the radius.
To do that complete the two squares.
x^2-2x=x^2-2x+1-1=(x^2-2x+1)-1=(x-1)^2 -1.
Do the same for the y terms.
y^2-2y=(y-1)^2 -1.
Substitute these two expressions in your original equation.
(x-1)^2+(y-1)^2 -1-1=14 or (x-1)^2+(y-1)^2=14+2=16
The radius is square root of 16 or 4, and the center is C(1,1).

Sep 20, 2011 | SoftMath Algebrator - Algebra Homework...

1 Answer

What the solution for 2x - 8y - 6 = 0?


It's going to be a line on which every point represents values of x and y where 2*x is 6 more than 8*y.

Aug 18, 2011 | Computers & Internet

1 Answer

2x+3y=16


  • This equation is in standard form. For more information, watch this:


Jul 07, 2011 | Computers & Internet

2 Answers

How to use texas instruments ti-84 plus to plot inequality 4x+8y<40?


First step is to find inequality in the form y<f(x), in this case y<5-0.5x. Then graphing it. See captured image


3_3_2012_6_59_43_pm.jpg

Feb 18, 2011 | Texas Instruments TI-84 Plus Silver...

1 Answer

Differentiate each of the following w.r.t.x; 29.sin2xsinx


Use the rule for differentiating products of functions: ()' signifies derivative
(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'
But
  1. (29)'=0 derivative of a constant is zero
  2. (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
  3. (sin(X))'=cos(X)
Result is
(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form
sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]
then calculated the derivative of
29/2*[cos(X)-cos(3X)]
which is
29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent
29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

Jun 21, 2010 | Vivendi Excel@ Mathematics Study Skills...

2 Answers

8y-4(5-6y)+20 distributive property


Hello,
You are talking of the distributivity of multiplication with respect to the addition or subtraction. The only term where you have multiplication and addition/subtraction is the one with parentheses because
4(5-6y) = 4*(5-6y). * means multiply by

Distributing the product consists in removing CORRECTLY the parentheses.
I consider the term alone
4*(5-6y) = 4*5 +4*(-6y)= 20 -4*6*y = 20 -24*y
You put this result in a package and replace it where it was it the original expression.
So
8*y -(package) +20= Replace package
8*y -(20-24*y)+20 = 8*y -20 -(-24y) + 20 Remember -*(-) = +
8*y -20 +24*y +20= Remember -20+20 =0
8*y -20 +20 +24*y= Addition is commutative
8*y +24*y = 32*y
Let y be an orange 8 oranges + 24 oranges =32 oranges.Coclusion
8y-4(5-8y)+20 = 32y

Sep 10, 2009 | The Learning Company Achieve! Math &...

1 Answer

4x+8y=20 -4x+2y=-30


4x+8y=20 || /4
x+2y=5
x=5-2y

-4x+2y=-30 || /2
-2x+y=-15
-2(5-2y)+y=-15
-10+4y+y=-15
5y=-5
y=-1

x=5-2y || y=-1
x=5-2(-1)
x=5+2
x=7

Mar 10, 2009 | Bagatrix Algebra Solved! 2005 (105101) for...

3 Answers

IF I HAVE TWO equations 5x+8y=54, AND -9x+y=26 how do i solve


use the simultaneous equation solver software available on ur ti-89 and enter the equation in the form of augmented matrix and you will get ur answer.

Dec 03, 2008 | Texas Instruments TI-89 Calculator

1 Answer

Determining the equation of the parabola


V (2,0) and Focus (2,2)
since the focus is 2 units above the vertex, the parabola opens upward

vertex (h,k)
a is the focal length (distance between the vertex and the focus)
a = 2
(2 units above the vertex)

(x-h)^2 = 4a (y-k)
(x-2)^2 = 4(2) (y-0)
x^2 - 4x + 4 = 8 (y)
x^2 - 4x + 4 = 8y
x^2 - 4x - 8y + 4 = 0

**Answer: "(x-2)^2 = 8 (y)" or in expanded form "x^2 - 4x - 8y +4"

Nov 18, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

2 Answers

Algebra college


Consider the following system of 3 equations in 3 unknowns:
x + y = 2
2x + 3y + z = 4
x + 2y + 2z = 6Our goal is to transform this system into an equivalent system from which it is easy to find the solutions. We now do this step by step.
  • Subtract 2*(Row1) from Row2 and place the result in the second row; subtract Row1 from Row2 and place in the third row. Leave Row1 as is.
x + y = 2
y + z = 0
y + 2z = 4
  • Subtract Row2 from Row3, and place the result in row3. Leave Row1 and Row2 as they are.
    x + y = 2
    y + z = 0
    z = 4 From the last form of the system we can deduce the following unique solution to the system:
z = 4, y = -4, and x = 2-(-4) = 6Equivalently, we say that the unique solution to this system is (x, y, z) = (6, -4, 4).

Sep 17, 2008 | Belkin (F5D7230-4) Router (587009)

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