Question about phoneflips PreCalculus Guide

Y^2-4x+4y-4=0

x + y = 84

x = 4y + 9

so 4y + 9 +y = 84

5y = 75

y = 15

x = 60 + 9 = 69

Check

69 + 15 = 84

x = 4y + 9

so 4y + 9 +y = 84

5y = 75

y = 15

x = 60 + 9 = 69

Check

69 + 15 = 84

Apr 21, 2014 | Computers & Internet

x-intercept: set y=0, and find x=4

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

Jan 12, 2012 | Mcgraw-Hill Glencoe Algebra 1 Florida...

what is the value of x?

if x = 1 in the equation then,

1 = 4y+5

1 - 5 = 4y

-4 = 4y

y = -4/4

y = -1

if x = 1 in the equation then,

1 = 4y+5

1 - 5 = 4y

-4 = 4y

y = -4/4

y = -1

Jun 30, 2011 | Computers & Internet

2x + 4y = -8 ; divide each side by 2

x + 2y = -4 ; subtract x from both sides

2y = -4 - x ; rearrange

2y = -1x -4 ; divide each side by 2

y = -1/2x - 2 ; relate to slope/intercept form of line (y=mx+b)

implies there are multiple solutions that fall along a line with slope -1/2 and y intercept of -2

'

\ '

++++++++++

\ '

\ '

Sample points on this line are (-4,0), (-2,-1), (0,-2), (2,-3)

x + 2y = -4 ; subtract x from both sides

2y = -4 - x ; rearrange

2y = -1x -4 ; divide each side by 2

y = -1/2x - 2 ; relate to slope/intercept form of line (y=mx+b)

implies there are multiple solutions that fall along a line with slope -1/2 and y intercept of -2

'

\ '

++++++++++

\ '

\ '

Sample points on this line are (-4,0), (-2,-1), (0,-2), (2,-3)

Nov 04, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

the area of the rectangle is infinite because the length of the sides is undefined.

Aug 26, 2010 | Dryers

Use the DRAW program.

Press [2nd][PRGM] (DRAW)

Select [9:Circle (]

Command echoes on main screen

Complete the command with coordinates of the center and the radiius

Close parenthesis and press [ENTER]

The circle is displayed.

Ex: Circle(0,3,2) draw a circle with cntere at (0,3) and radius equal to 2.

Alternatively: If the conics application is on the calculator run it.

Press [APPS]

Select [Conics]

Select [1:CIRCLE]

Choose the canonical form (X-H)^2 + (Y-K)^2=R^2 where H, and K are the coordinates of the center and R is the radius.

You will be prompted to enter the values for H,K, and R

You can also use the general equation for a circle aX^2 +aY^2+BX+CY +D=0

Enter the values of a, B, C and D.Change the values to get what you want.

Press [2nd][PRGM] (DRAW)

Select [9:Circle (]

Command echoes on main screen

Complete the command with coordinates of the center and the radiius

Close parenthesis and press [ENTER]

The circle is displayed.

Ex: Circle(0,3,2) draw a circle with cntere at (0,3) and radius equal to 2.

Alternatively: If the conics application is on the calculator run it.

Press [APPS]

Select [Conics]

Select [1:CIRCLE]

Choose the canonical form (X-H)^2 + (Y-K)^2=R^2 where H, and K are the coordinates of the center and R is the radius.

You will be prompted to enter the values for H,K, and R

You can also use the general equation for a circle aX^2 +aY^2+BX+CY +D=0

Enter the values of a, B, C and D.Change the values to get what you want.

Apr 01, 2010 | Texas Instruments TI-83 Plus Calculator

You can solve it with following method.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

Mar 03, 2010 | Office Equipment & Supplies

2x-4y=8

=> 2[x-2y]=8

=> x-2y=8/2

=>** x-2y=4**

=> 2[x-2y]=8

=> x-2y=8/2

=>

Feb 07, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

This is an equation of a straight line, and we can easily find the the coordinates where this line intersects the axis in following ways:-

**for x-axis:-**

put y=0, 4x+2*0=8

4x =8

x =8/4

x =2

so intersection coordinates ate (2, 0)

**for y-axis:-**

put x=0, 4*0+2y=8

2y =8

y =8/2

y =4

so intersection coordinates ate (0, 4)

Thanks

Zulfikar ali

ali_zulfikar@yahoo.com

9899780221

put y=0, 4x+2*0=8

4x =8

x =8/4

x =2

so intersection coordinates ate (2, 0)

put x=0, 4*0+2y=8

2y =8

y =8/2

y =4

so intersection coordinates ate (0, 4)

Thanks

Zulfikar ali

ali_zulfikar@yahoo.com

9899780221

Jan 26, 2009 | SoftMath Algebrator - Algebra Homework...

See this solution http://www.fixya.com/support/t663157-calculate_equation,

also in the case of your example:

4y=2x4 (4 times y = 2 times x times 4, moving the 4 over makes it divide by 4)

y=__2x4__ (the 4's cancel out, 4 divided by 4 = 1, 1 times anything is the same)

4

so y=2x (if we move x over it becomes divide by)

so__y__=2 (y diveided by x = 2 is as far as you can go)

x

also in the case of your example:

4y=2x4 (4 times y = 2 times x times 4, moving the 4 over makes it divide by 4)

y=

4

so y=2x (if we move x over it becomes divide by)

so

x

Jun 26, 2008 | Casio FX-300MS Calculator

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