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I am Crocheting a Blanket, and was told to make 7 by 12 inch rectangles, I want the blanket to be about 100 inches by 66 inches, I am trying to figure out if the rectangles are about the correct size.

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You want the blanket to be 6600 square inches using 84 square inch rectangles. Dividing 6600 by 84 gives about 78 and a half.

Posted on Nov 07, 2014

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Posted on Jan 02, 2017

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We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Hi Jacqueline:

A rectangle has four sides, the lengths of the opposite sides are equal, and the corners are right angles.

The perimeter is the distance around the outside edge, so it would be twice the length plus twice the width.

2 times 5 = 10 feet

2 times 6 = 12 feet

10 plus 12 = 22 feet

What is important is to understand the question.

If you need help with the course, get back to me.

Cheerfuls!

A rectangle has four sides, the lengths of the opposite sides are equal, and the corners are right angles.

The perimeter is the distance around the outside edge, so it would be twice the length plus twice the width.

2 times 5 = 10 feet

2 times 6 = 12 feet

10 plus 12 = 22 feet

What is important is to understand the question.

If you need help with the course, get back to me.

Cheerfuls!

May 13, 2015 | Computers & Internet

Ok

2L + 2W = 50 (i)

W = L/4 + 5 (ii)

So 4W = L + 20 from (ii) and

4W = 100 - 4L from (i)

L + 20 = 100 - 4L

5L = 80

L = 16

W = 9 from (ii)

check

(i) 2*16 + 2*9 = 50

(ii) 16/4 + 5 = 9 = W

2L + 2W = 50 (i)

W = L/4 + 5 (ii)

So 4W = L + 20 from (ii) and

4W = 100 - 4L from (i)

L + 20 = 100 - 4L

5L = 80

L = 16

W = 9 from (ii)

check

(i) 2*16 + 2*9 = 50

(ii) 16/4 + 5 = 9 = W

Oct 10, 2014 | Computers & Internet

That depends on what the 1110 and 220 are.

The area of a rectangle 1110 inches by 220 inches is 244200 square inches. The area of a rectangle 1110 feet by 220 feet is 35,164,800 square inches.

The area of a rectangle 1110 inches by 220 inches is 244200 square inches. The area of a rectangle 1110 feet by 220 feet is 35,164,800 square inches.

May 02, 2014 | Office Equipment & Supplies

Perimeter means 'how far round is it?' So if you walked round this rectangle, you would walk along 12 + 7 + 12 + 7 units = 38

It is quicker to say 2 x [12+7] = 2 x 19 = 38 ie walk half way round and double it

It is quicker to say 2 x [12+7] = 2 x 19 = 38 ie walk half way round and double it

Jan 17, 2014 | Computers & Internet

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

Translate the English into Mathematics.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

**Solve for L: Do it'! **

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is** L'=-4+3W**

and the new perimeter is** P'=2(L'+W)**

Now your turn to do some work.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is

and the new perimeter is

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2

SIMPLES brought to you by SpideRaY @ http://www.windowstipsclub.com

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2

SIMPLES brought to you by SpideRaY @ http://www.windowstipsclub.com

Jan 31, 2011 | Computers & Internet

It would be "cheating" for anybody to do your "homework" from your computer-mathematics class, unless you submit your answer, saying that an EXPERT on FIXYA did all the work on your behalf.

Apr 14, 2009 | Microsoft Windows XP Professional With...

Go into the customer menu and find the "closed captions" heading. Within the closed caption you will find "TEXT". If you turn off closed captions or the text, whichever you menu lets you do, your rectangle will go away. Hope this helps

Dec 21, 2008 | SVA-USA HD4208TIII-PDP 42 in. EDTV-Ready...

Nov 17, 2017 | Home

Nov 17, 2017 | Home

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