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morgan fisher Posted on Sep 25, 2014
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How should I set the v-window when I enter my distance equation?

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k24674

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  • Casio Master 8,093 Answers
  • Posted on Jul 29, 2015
k24674
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The Window parameters control the width and length of the graphing screen. The distance equation is a formula to use to calculate the distance between two points known by their coordinates. The window dimensions have nothing to do with calculations. Or maybe I don't understand the question.

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0helpful
1answer

So I got this H.W question, can you see if you can put it into an equation, and solve it? How fast is each boat traveling in knots? The tall ships speed multiplied by 10 hours equals the distan

First translate the various statements of the problem into equations. then try to solve the equations. It won't do much good if I just gave you the answers.
0helpful
1answer

How do I set up graph lines

in order to give the calculator a function to graph, you will want to enter the y= window by pressing the top left most button on the calculator. nintenman1.gif a menu similar to the one above will open, wherein you can enter an equation for the calculator to graph, such as (x^2-2). On the ti-83 itself, you can enter up to 9 equations to be graphed at once. after that, you may want to go to the window menu, where you can set the dimensions of the graphing plane in both the x row and y column. to view the graph, press the top right most button on the device.
hope that helps :)
0helpful
1answer

4/7-1/2x=1+1/x

Assuming you want the solution graphically.
You press the Y= button (top left)
Enter the first side of the equation after Y1=
Press the down arrow
Enter the other side of the equation after Y2=
Set the setting by pressing the window button (set xmin to -10; xmax to 10; ymin to -10; ymax to 10 )
Press the graph button
You will see now the two functions potted.
Now press Calc ( 2nd and after that Trace)
Select the correspondant number for intersect.
Set min to -10
Press enter
Set max to 10
Press enter
Guess something between -10 and 10 (eg. 0)
The answer will come out quickly (x=-3,5)

Hope it helps.
1helpful
1answer

When I try to graph, say y = x, I get an error message that says "invalid dim." The window settings are identical to another TI-73, so I'm not sure what the problem is. Can you help?

"invalid dim" could also mean that a list or, lists don't have the same dimensions or lengths. To fix this press [2nd][MEM][6][ENTER] -To clear out all the lists. Ti's instructions normally just has the user delete all memory instead of finding the exact problem. This can be done by being at the home screen and, by pressing [2nd] [Convert] [1][2][ENTER]. But, because I don't like starting all over everytime I preform a math process and, I like storing things into memory so I have to find the problem and fix it as I go a long.

To find such a problem as your's, I would look at x in the y= equation. It may be claiming that x is a list too. So you may want to [2nd][MEM][4] and then use the press [1] and find and highlight x and, press [ENTER] to delete it. It also might be a good idea before you start in the y= editor to press from the Home screen [2nd][MEM][4] and then press [4] and highlight the y= have equations and are not empty and, press [ENTER] to delete them. Then I would continue deleting all the y= equations too. Sure you can just make sure their off but, I'm not sure how advance of a user you are. On your calculator for the window settings to be a problem, you would have probably received a window range error.
0helpful
1answer

How to set up mode for graphing

To draw a graph, it helps if you know approximately where it is going to show up so that you can set up a window.
Try this:
Press the [Y=] button
Enter the following equation: 5*x^2-5*x (five x-squared minus five times x) by pressing the following calculator keys:
5 X (times) x^2 (x squared key) - (minus) 5 X (times) x (key labled x,t,n) in between the ALPHA and STAT keys
now press the zoom key and select #6 - ZStandard (this will give you a standard zoom)
You should see a parabola drawn on the screen.
If you enter in some equation and do not see it on the screen, you can try zooming out (zoom key) or setting up your display window, using the window key.
This is where it helps to know where your x and / or y intercepts are.
From there, you can use trace to move around the graph, 2nd+graph (table) to see your x and y intercepts.

0helpful
1answer

A train increases its normal speed by 12.5 % and reaches its destination 20 minutes earlier. What is the actual time taken? My email id is [email protected]

You have two variables on the question. That is the Speed of the Train and the actual Time taken.
So you shouold be have two equations to resolve the two variables.
Lets assume the speed to be x and the actual time in minutes to be y.
So the 1st equation,
If the train goes with the actual or the normal speed x the train reaches within the time y.
we know that speed = distance X Time
so X = Distance x Y or
Distance = X/Y ------- 1
Next the 2nd equation.
[{(12.5/100) x X} + X] = Distance x (y-20) or
Distnace = [{(12.5/100) x X} + X] / (y-20) ------ 2
Now you can equate 1 and 2 to get the results.
0helpful
1answer

Graphing an equation

Press the Y= key to invoke the Y= editor. Enter in your equation.

Press the WINDOW key to set the window parameters.

Press the GRAPH key to have the calculator graph the equation.

For more details and options, see the "Function Graphing" chapter in the Guidebook.
1helpful
1answer

I cant highlight both equations in Y= to graph

Hello,

First thing to do before any new type of problem
1. Turn StatPlots OFF : press [2nd][STATPLOT][4:PlotsOff] [ENTER]

Second thing: Clear the statistical lists
2. Press [2nd][0][PGRM] DownArrow to point to ClrAllLists.
3.Press [ENTER][ENTER]

Third thing : Configure the graph type to be FUNCTION graph
4. Press [MODE]. If FUNC (on fourth line) is highlighted. Press [Y=] and start entering the functions.
5. If FUNC is not highlighted, use Down arrow till 4th line, highlight FUNC and press [ENTER]. Press Press [Y=] and start entering the functions.

Fourth thing: Enter function and select them for graphing
1. As you start entering the function Y1=, notice that the = sign becomes highlighted. Press [ENTER] when Y1 is typed in. Make sure the = sign for Y1 remains highlighted as cursor moves to Y2=.
2. Keep entering the functions and verifying that their = signs remain highlighted as cursor moves to another equation.
3. When finished press [ENTER]
4. Look at the graph style for each function: it is a bit of line to the left of each Y. Here is a picture of all the 7 styles.

5d53e23.jpg

To set a graph style, highlight the style to the left of the Y, and press [ENTER]. Each time you press [ENTER] you see a new style, in the order shown on picture.
Avoid the style of Y6, it is bubble, and as such will burst and disappear once graph is finished. Avoid also the triangular ones (for Y3 and Y4) they will shade areas of the graph, and may hide other functions.

Fifth thing: Graph Functions.
1. You can press [GRAPH] to see your graphs.
2. If one curve is missing (and you have not set its style to be rhe bubble), it may be due to the Window dimensions.

Sixth Thing: Set Window dimensions and Zoom.
1. Press [ZOOM][6:ZStandard] to use standard window dimensions.
2. If curve still missing, Press [ZOOM][3:Zoom Out] to zoom out so that you may be able to see a bigger range for the functions.
3. If necessary press [WINDOW] and set the Xmin, Xmax, Ymin,Ymax to values of your own.

d44f2dd.jpg

Dimensions must obey the conditions: Xmin < Xmax, and Ymin < Ymax.

Hope that helps.
0helpful
1answer

Analytic geometry

assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2
radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25



12helpful
2answers

Graphing multiply equations

When you go to Y=, you should get a list that says:
Y1=
Y2=
Y3=
etc. You just enter the first equation into the Y1= space then hit ENTER and it will go to Y2=. Enter the second equation there. After you have entered all of your equations, push GRAPH and they should come up in order but they will all appear.

Also, make sure your window is set appropriately so that you are able to see all of the graphs.

Lastly, when you look at your Y= screen, are there funny looking arrows before the Y=? If so, do this:

  • Press [APPS] key
  • Select Transfrm from the menu
  • Press 1:Uninstall


  • Hope one of these are helpful!!

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