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Mean median mode

  1. here are the ages of 5 children:11years6months,10years4m,months10years6months,11years4months,10years11months.a sixth child joins the group and the mean age becomes 11years1month.what is the age of the sixth child?





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11 years 11 months

[Lack of spacing in the above problem hindered the word wrap algorithm. A raw view of this page shows that the 5th child is actually 10years11months.]

Posted on Dec 06, 2007

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Math mean median mode


The question is incomplete.
The mean, also called the average is defined as
mean= (sum of the data values)/(number of data elements)
Mode = the most frequent data value (the one that is most repeated)
To find the median:
  1. Order the data values in ascending order (sort them from the smallestr to the largest), and
  2. Locate the data value that is in the middle.
  3. If the number of data values id ODD (not a multiple of 2) there is only one middle element. That is the median.
  4. If the number of data elements is EVEN (multiple of 2), there is not one middle element but two.
  5. The median is the average of the two middle element values

    1. Median =( left of middle value +right of middle value)/2
    2. Imagine this median value to be inserted between the two middle elements
Example 1
Data values 12.5, 13, 13., 13, 13.5, 14, 19.5, 19.5, 20
Mean =(12.5+13+13+13+13.5 +14+19.5+19.5+20)/9=?
Mode= most frequent value. Here it is 13 (repeated 3 times)
There are 9 values, an odd number. Middle element is the 5th ( 13.5)
Median=13.5

Example 2
Data values 12.5, 13, 13., 13, 13.5, 14, 19.5, 19.5, 20, 25
Mean =(12.5+13+13+13+13.5 +14+19.5+19.5+20 + 25)/10=?
Mode= most frequent value. Here it is 13 (repeated 3 times)
There are 10 values, an even number. Middle element is not among the values. There are two middle elements (the 5th and the 6th) or
The value of the median is the average of the 5th and 6th elements or
Value of Median =(13.5+14)/2=?


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