Question about Adobe Photoshop 7.0 (321115627)

Re: math problem

This sounds like someones homework. I'm risking my reputation here but here goes.

Previous Area was Pi x R x R. = Pi X 10 X 10 = 100 X Pi

Previous Perimeter is 2 X Pi X R = 2 X Pi X 10 = 20 X Pi

New shape is a rectangle with a semicircle at each end and width of 10 cm.

New Perimeter is circular bits + straight edges between them.

We know the circular bits but not how long the straight bits are so ...

Perimeter = 20 X Pi = (2 X Pi X 5) + L X 2 = 10 X Pi + (L X 2)

So L = (20 - 10) X Pi / 2 = 5 X Pi.

So the new Area is ... (Pi X 5 X 5) + (10 X 5 X Pi)

= 75 X Pi.

= 75 X 3.14 = 235.5

Posted on Nov 10, 2007

It varies by the shape. Anything sort of circular usually involves equations with Pi, but objects with corners are different. Since Fixya will not allow me to type equations very well here, I'll refer you to

http://www.cliffsnotes.com/math/geometry/perimeter-and-area/formulas-perimeter-circumference-area

http://www.coolmath.com/reference/perimeters.html

http://www.mathsisfun.com/geometry/ellipse-perimeter.html

http://math2.org/math/geometry/areasvols.htm

http://www.cliffsnotes.com/math/geometry/perimeter-and-area/formulas-perimeter-circumference-area

http://www.coolmath.com/reference/perimeters.html

http://www.mathsisfun.com/geometry/ellipse-perimeter.html

http://math2.org/math/geometry/areasvols.htm

Oct 12, 2014 | Mathsoft StudyWorks! Middle School Deluxe...

Well, if you know the side 'a' of each hexagon it is just a*(30 - 4) = 26a

If you know the diameter of the circle enclosing the hexagon then

a = D/2 as radius = a

If you know the diameter of the circle enclosing the hexagon then

a = D/2 as radius = a

Sep 23, 2014 | Educational & Reference Software

You add the measure of all the sides for a polygon. For a circle of radius r, the perimeter is 2*Pi*r

Aug 24, 2014 | Educational & Reference Software

Since the area of a whole circle is pi times the radius squared, the area of half the circle is one half times pi times the radius squared.

Apr 30, 2014 | Educational & Reference Software

The area of a circle is pi * r^^2.

For the first pond, the area is pi *14^^2. Let's say that is A

For the second pond the area is pi * r^^2. Let's say that is a.

But a = A/4 or, conversely 4a = A.

But A = pi*14^^2 = 4a = 4(pi * r^^2) or

pi*14^^2 = 4(pi*r^^2) or

pi*14^^2 = 4pi*r^^2 or

14^^2 = 4*r^^2

196 = 4*r^^2

196/4 = r^^2

49=r^^2

7=r

So a pond of radius 7m has an area a quarter of a circular pond of 14m.

For the first pond, the area is pi *14^^2. Let's say that is A

For the second pond the area is pi * r^^2. Let's say that is a.

But a = A/4 or, conversely 4a = A.

But A = pi*14^^2 = 4a = 4(pi * r^^2) or

pi*14^^2 = 4(pi*r^^2) or

pi*14^^2 = 4pi*r^^2 or

14^^2 = 4*r^^2

196 = 4*r^^2

196/4 = r^^2

49=r^^2

7=r

So a pond of radius 7m has an area a quarter of a circular pond of 14m.

Jan 26, 2014 | Mathsoft Educational & Reference Software

You cannot. There is technique that can be used to locate a fraction on a line segment. It involves the drawing of parallel lines passing through equidistant points drawn on an intersecting line. The procedure is based on Thales' theorem.

Draw a real line (passing through 0 of course) Mark the limits of segment [0,1]

From the point 0 draw a line. Choose an arbitrary length measured by the opening of a compass. Starting from O, mark three equal segments along the second line. From the end of the 3rd segment draw a line that joins that end with the end of the point 1 on the real line.

From each of the two other points on the secant draw segments parallel to the one you just drew.

Here is how it looks on a picture.

If you have another fraction (5/7) draw 7 equal length segments on the second line (secant to the real axis). The parallel line from the 5th point will cut the real axis at the point 5/7

Draw a real line (passing through 0 of course) Mark the limits of segment [0,1]

From the point 0 draw a line. Choose an arbitrary length measured by the opening of a compass. Starting from O, mark three equal segments along the second line. From the end of the 3rd segment draw a line that joins that end with the end of the point 1 on the real line.

From each of the two other points on the secant draw segments parallel to the one you just drew.

Here is how it looks on a picture.

If you have another fraction (5/7) draw 7 equal length segments on the second line (secant to the real axis). The parallel line from the 5th point will cut the real axis at the point 5/7

Dec 06, 2013 | The Learning Company Achieve! Math &...

Draw two chords of the circle (any two chords will do, as long as they aren't parallel). Construct perpendicular bisectors of each chord. The center of the circle will be where the two bisectors intersect.

May 10, 2013 | Educational & Reference Software

This must be the area of a circle with a radius of 4 in.. The formula for this is Pi (3.14) X radius X radius.

3.14 X 4in X 4in = 50.24 inches squared

3.14 X 4in X 4in = 50.24 inches squared

Jan 28, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

Hello,

You must have been taught the relation between the circumference (perimeter) of a circle, the radius and pi. Use it to calculate the perimeter. It is true for all circular figure.

Depending on what is really asked (the perimeter of the actual pool where you find the water, or the general pool area where no shoes are allowed)

**1st case:** use the radius that was given.

**2nd case: **the total radius is the radius given plus the width of the path.

If you do not have a formula for the perimeter that involves the radius, but have one that involves the diameter you can use it too, knowing that the diameter is twice the radius or the radius is one half of the diameter.

As you might have guessed I was not going to make things too easy for you by providing a ready-made answer, but I gave you** all the hints that will help you solve the problem**.

You must have been taught the relation between the circumference (perimeter) of a circle, the radius and pi. Use it to calculate the perimeter. It is true for all circular figure.

Depending on what is really asked (the perimeter of the actual pool where you find the water, or the general pool area where no shoes are allowed)

If you do not have a formula for the perimeter that involves the radius, but have one that involves the diameter you can use it too, knowing that the diameter is twice the radius or the radius is one half of the diameter.

As you might have guessed I was not going to make things too easy for you by providing a ready-made answer, but I gave you

Oct 11, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Hello,

Sorry to say it but the question does not make sense. A circle is a figure that is perfectly defined by the knowledge of its center (or centre depending of the English you use) and its radius.

An ellipse is perfectly defined if you know its two foci (plural of focus) and the length each of its two axes (major and minor).

Is it the perimeter, the area, the parameter p of the ellipse you are lookong for.

Hope it will help you focus on your real the question.(The pun is intended)

Sorry to say it but the question does not make sense. A circle is a figure that is perfectly defined by the knowledge of its center (or centre depending of the English you use) and its radius.

An ellipse is perfectly defined if you know its two foci (plural of focus) and the length each of its two axes (major and minor).

Is it the perimeter, the area, the parameter p of the ellipse you are lookong for.

Hope it will help you focus on your real the question.(The pun is intended)

Feb 19, 2009 | The Learning Company Achieve! Math &...

Apr 04, 2014 | Adobe Photoshop 7.0 (321115627)

302 people viewed this question

Usually answered in minutes!

×