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How to adjust

I have just acquired a new Rain Bird 12DSH 1/2 circle nozzle. How do I control the distance and radius of the two sprays?

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The distance is purely based on water pressure 15 PSI gets 9 feet, and 30 psi gets 12 feet. You probably have at least 30 psi so it is going to spray 12 ft. and you can't change that. The 1/2 circle nozzle is going to always spray 180 degrees, you can turn it to point where you want but you can't increase or decrease the pattern from 180 degrees. You can buy 1/4 and full circle nozzles for this sprinkler though. The last letter of the part number signifies that pattern. H=Half, F=Full, Q=Quarter so a 12DSH=half.

Posted on May 20, 2014

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assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2
radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
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Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25



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