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Facebook sin up - Computers & Internet

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Point your web browser at http://www.facebook.com

If another account comes up, log out of it by clicking the little down arrow in the upper-right then clicking "Log Out."

Posted on May 16, 2014

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6ya6ya
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Posted on Jan 02, 2017

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Facebook is not going sin in


You will need to contact Facebook support for that.. Here is a link to their live chat:
http://www.facebook.com/note.php?note_id=410099297768

Phone: 650-543-4800
Fax: 650-543-4801

Sep 06, 2012 | Facebook Social Network

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Sins the weakend my farmville game on facebook does,t want to open


i bought the gingerbread house i finished it but now is disappeared, i can see only a shadow!!

Nov 29, 2010 | Zynga Farmville

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Differentiate each of the following w.r.t.x; 29.sin2xsinx


Use the rule for differentiating products of functions: ()' signifies derivative
(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'
But
  1. (29)'=0 derivative of a constant is zero
  2. (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
  3. (sin(X))'=cos(X)
Result is
(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form
sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]
then calculated the derivative of
29/2*[cos(X)-cos(3X)]
which is
29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent
29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

Jun 21, 2010 | Vivendi Excel@ Mathematics Study Skills...

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Trig Identities


Change csc to 1/sin. Find a common denominator and add the two left terms.
1/sin - sin = (1 -sin^2)/sin. Rewrite formula
(1 - sin^2)/sin = cos^2/sin Divide out the /sin.
1 - sin^2 = cos^2 Rearange.
1 = cos^2 + sin^2 Yes, that's true. It's like the Pythagorean formula.

May 22, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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