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How long it takes to drive any distance depends on your average speed. Whatever is your average speed, divide that into the distance you have to travel. For instance, if your speed is 100 kilometers per hour and you need to go 400 kilometers, it will take you (400 km/100 kmph=) four hours. Always be sure to use the same units of measurement, English or metric, in your arithmetic.

Posted on Jul 27, 2014

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Posted on Jan 02, 2017

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Fixed distance is D

D=(5h*80 km/h)=T*50 km/h

T=(400 km)/(50 km/h)=8 hours

D=(5h*80 km/h)=T*50 km/h

T=(400 km)/(50 km/h)=8 hours

Jul 02, 2014 | Casio FX-115ES Scientific Calculator

More information please. Where will the cain not engage in the bar sprocket or on the drive sprocket

Mar 25, 2013 | Stihl Hl Ht Km 87 90 95 100 101 110 130...

you need an ide sata converter attached to your hard drive

hope this helps

hope this helps

Sep 12, 2010 | EliteGroup KM400-M2 Motherboard

Download the VIA KM 400 motherboard drivers from here.

Hope that helps.

Regards,

Raspal

For Windows XP Driver Files and How-to Resources, visit XPDrivers.

Hope that helps.

Regards,

Raspal

For Windows XP Driver Files and How-to Resources, visit XPDrivers.

Jun 13, 2010 | Akai MPC-4000 Plus Production Center (w/80...

Let X be the time taken when train is moving in its normal speed.

Y be the normal speed of the train.

Speed = distance/time

that is X = 400 / Y

or Y = 400 / X --------- (1)

When speed is decreased by 5 km/hr time increases by 4 hour

that is X + 4 = 400 / Y -5

= X + 4 = 400 X / 400 - 5X ( substitute Y = 400 /X we get this equation)

on solving we get 5X^2 + 20x - 1600 = 0

we get two solutions X = 16 and -20

-20 is neglected (time cannot be negative)

substitute X in equation (1)

Y = 400 / 16 = 25 km/hr

So normal speed of train is 25 km/hr.

Y be the normal speed of the train.

Speed = distance/time

that is X = 400 / Y

or Y = 400 / X --------- (1)

When speed is decreased by 5 km/hr time increases by 4 hour

that is X + 4 = 400 / Y -5

= X + 4 = 400 X / 400 - 5X ( substitute Y = 400 /X we get this equation)

on solving we get 5X^2 + 20x - 1600 = 0

we get two solutions X = 16 and -20

-20 is neglected (time cannot be negative)

substitute X in equation (1)

Y = 400 / 16 = 25 km/hr

So normal speed of train is 25 km/hr.

Jun 02, 2010 | Vivendi Excel@ Mathematics Study Skills...

bonjour ,j'ai une photocopieuse kyocera km 1505 et me marque le message erreur A400 ,y a t 'il quelqu'un qui pourrait me dire quesque c'est ce message là je vous remercie d'avance

May 02, 2010 | Kyocera KM-1505 Copier

How far away is your other antenna?

2.4 GHz signals may be attenuated by up to 0.05 dB/km (0.08 dB/mile) by torrential rain (4 inches/hr). Thick fog produces up to 0.02 dB/km (0.03 dB/mile) attenuation. At 5.8 GHz, torrential rain may produce up to 0.5 dB/km (0.8 dB/mile) attenuation, and thick fog up to 0.07 dB/km (0.11 dB/mile). Even though rain itself does not cause major propagation problems, rain will collect on the leaves of trees and will produce attenuation until it evaporates.

2.4 GHz signals may be attenuated by up to 0.05 dB/km (0.08 dB/mile) by torrential rain (4 inches/hr). Thick fog produces up to 0.02 dB/km (0.03 dB/mile) attenuation. At 5.8 GHz, torrential rain may produce up to 0.5 dB/km (0.8 dB/mile) attenuation, and thick fog up to 0.07 dB/km (0.11 dB/mile). Even though rain itself does not cause major propagation problems, rain will collect on the leaves of trees and will produce attenuation until it evaporates.

Nov 23, 2009 | Motorola PTP 400 Series Full, 4.9 GHz...

No problem.Japan models have this speed limit light.If it is annoying disconnect it or cut and isolate the wires.No problem at all.Full throttle dude........Forever.

Jun 01, 2009 | 1986 Honda VF 400 F

That is just about what you should get for mileage

Dec 28, 2008 | 1997 GMC Jimmy

http://www.biostar.com.tw/app/en-us/mb/driver.php?S_ID=268

Oct 20, 2007 | Biostar M7VIG-400 (M7VIG 400-COMBO4)...

Apr 29, 2014 | Google Finance

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