Question about Office Equipment & Supplies

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Posted on Jan 02, 2017

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SOURCE: The following unadjusted trial balance

please clarify what the question is here?

Posted on Jul 15, 2010

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SOURCE: The following six-column table for

this is an accounting problem, u have the wrong wweb site

Posted on Jul 15, 2010

SOURCE: Expected returns: You have chosen biology as your

So expected returns are just a little more advanced version of probability - without getting too in detail it uses weighted averages so you do not have to add the same number 17 times.

Let's first define our variables:

E(X) = Expected Return
X1 = Variable 1
P1 = Probability 1 (in decimal format so 55% would be .55)
X2 = Variable 2
P2 = Probability 2 (P2 is also equal to 1 - P1)

So the expected return formula is as follows:

E(X) = (X1)*(P1) + (X2)*(P2)

Plugging in our given numbers we get
E(X) = Expected Return
X1 = 300,000
P1 = 10% or .1
X2 = 40,000
P2 = 1 - P1 = 1 - .1 = .9

E(X) = (300,000)*(.1) + (40,000)*(.9)
E(X) = 66,000

Now remember this does not include the opportunity cost of spending your four years in college studying biology instead of another degree.

Posted on Mar 01, 2011

SOURCE: On the Sharp EL-738 calculator,

Hi,

Jane starts with 1200$ at the beginning of the first year, and at the end of the fourth year she has 1200$+300$=1500$

Use x for her annual interest rate, that means at the end of the first year she will have 1200$*[(100+x)/100]. At the end of the second year her first-year money earns at the same rate, so she will have 1200$*[(100+x)/100]*[(100+x)/100]=1200$*[(100+x)/100]^2 at the end of the second year.

At the end of the third year she will have 1200$*[(100+x)/100]^2 *[(100+x)/100]=1200$*[(100+x)/100]^3

At the end of the fourth year she will have

1200$*[(100+x)/100]^3 *[(100+x)/100]=1200$*[(100+x)/100]^4 which is equals to 1500$

1200$*[(100+x)/100]^4=1500$ divide both sides by 1200$

[(100+x)/100]^4=1,25 take the fourth root of both sides

(100+x)/100=1,05737 both sides*100

100+x = 105,737 both sides -100

x=5,737

So Jane's annaual interest rate was 5,737%.

Hope it helps you.

Posted on Mar 15, 2011

SOURCE: How can i earn at least 10$ online without wasting

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Posted on Aug 17, 2011

annual salary $40,000

annual bonus 3,600

11.1%

annual bonus 3,600

11.1%

Dec 16, 2015 | Office Equipment & Supplies

i think teachers need to be payed a good wage .. after all they single handed look after 30 kids for like 4 or 5 hrs...

how the fek do they do it my home is a reck after an hour with three..?

how the fek do they do it my home is a reck after an hour with three..?

Mar 26, 2015 | Encore Math Advantage Algebra II and...

Your 'investment' consists 2 years loss of 45k and a further 30k = 75k

if you work for the next 5 years you would need to earn 75k more than whatever your wages were without the qualification. That's an extra 15k a year.

None of this allows for tax or inflation, and is a gross over-simplification of events.

if you work for the next 5 years you would need to earn 75k more than whatever your wages were without the qualification. That's an extra 15k a year.

None of this allows for tax or inflation, and is a gross over-simplification of events.

May 12, 2014 | Office Equipment & Supplies

45k - 37 k = 8k. 4.5 x 8k = 36k answer is a

May 09, 2014 | Office Equipment & Supplies

The easiest way to do this is to use Excel spreadsheet.

This is what you need to do.

Create a label at the top of each column as detailed.

Add a employee to each row under Name of employee

Then against each employee add the data and the formula in the relevant cell under each column.

The first column - Name of the employee

2nd column - salary rate per hour

3rd column - hours worked

4th column - gross pay (formula = salary rate X hours worked)

5th column - tax deduction

6th column - other deductions

7th column - total deductions (formula = tax deduction + other deduction)

8th column - net pay (formula = gross pay - tax - total deductions)

At the last row you can include a total for Gross salary paid, total Tax collected etc.

Once you have setup this spread sheet make a copy of it and save it as a template.

You can then copy this template for each new financial year so you do not have to create a new one each year, you only need to make minor changes for new employees, rates of pay etc.

Another way to make a salary program is to use Access Database. You need more skills to do this, but it can provide greater reporting capabilities.

This is what you need to do.

Create a label at the top of each column as detailed.

Add a employee to each row under Name of employee

Then against each employee add the data and the formula in the relevant cell under each column.

The first column - Name of the employee

2nd column - salary rate per hour

3rd column - hours worked

4th column - gross pay (formula = salary rate X hours worked)

5th column - tax deduction

6th column - other deductions

7th column - total deductions (formula = tax deduction + other deduction)

8th column - net pay (formula = gross pay - tax - total deductions)

At the last row you can include a total for Gross salary paid, total Tax collected etc.

Once you have setup this spread sheet make a copy of it and save it as a template.

You can then copy this template for each new financial year so you do not have to create a new one each year, you only need to make minor changes for new employees, rates of pay etc.

Another way to make a salary program is to use Access Database. You need more skills to do this, but it can provide greater reporting capabilities.

Mar 24, 2011 | Computers & Internet

So expected returns are just a little more advanced version of probability - without getting too in detail it uses weighted averages so you do not have to add the same number 17 times.

Let's first define our variables:

E(X) = Expected Return X1 = Variable 1 P1 = Probability 1 (in decimal format so 55% would be .55) X2 = Variable 2 P2 = Probability 2 (P2 is also equal to 1 - P1)

So the expected return formula is as follows:

E(X) = (X1)*(P1) + (X2)*(P2)

Plugging in our given numbers we get E(X) = Expected Return X1 = 300,000 P1 = 10% or .1 X2 = 40,000 P2 = 1 - P1 = 1 - .1 = .9

E(X) = (300,000)*(.1) + (40,000)*(.9) E(X) = 66,000

Now remember this does not include the opportunity cost of spending your four years in college studying biology instead of another degree.

Let's first define our variables:

E(X) = Expected Return X1 = Variable 1 P1 = Probability 1 (in decimal format so 55% would be .55) X2 = Variable 2 P2 = Probability 2 (P2 is also equal to 1 - P1)

So the expected return formula is as follows:

E(X) = (X1)*(P1) + (X2)*(P2)

Plugging in our given numbers we get E(X) = Expected Return X1 = 300,000 P1 = 10% or .1 X2 = 40,000 P2 = 1 - P1 = 1 - .1 = .9

E(X) = (300,000)*(.1) + (40,000)*(.9) E(X) = 66,000

Now remember this does not include the opportunity cost of spending your four years in college studying biology instead of another degree.

Feb 27, 2011 | Texas Instruments BA-II Plus Calculator

I don't see any numbers in your question, so let's assume the number of inches in the first year is x and the number of inches in the second year is y. The percentage change is the difference between the number of inches in the second year and the number of inches in the first year, divided by the total number of inches in the first year. This number (which is a fraction) needs to be expressed as a percentage. Algebraically:

y-x is the difference between year 2 and year 1 (can be positive or negative)

x is the total number of inches in year 1

so:

(y-x)/x is the change fraction

(y-x)/x * 100 is the change percentage.

For example, if x = 50 and y = 40 then:

(40-50)/50 * 100 = (-10)/50 * 100 = (-.2) * 100 = -20% = a 20% reduction in snowfall in yr 2 over yr 1.

y-x is the difference between year 2 and year 1 (can be positive or negative)

x is the total number of inches in year 1

so:

(y-x)/x is the change fraction

(y-x)/x * 100 is the change percentage.

For example, if x = 50 and y = 40 then:

(40-50)/50 * 100 = (-10)/50 * 100 = (-.2) * 100 = -20% = a 20% reduction in snowfall in yr 2 over yr 1.

Feb 09, 2011 | The Learning Company Middle School...

please clarify what the question is here?

Jul 15, 2010 | Computers & Internet

The formula that would have been used to increase his salary each year probably was: Original Salary * (100% + inflation) = New Salary

Rearranging this, we get: Original Salary = New Salary / (100% + inflation)

So...

Last Year: 42000 / 102% = 41176.47 = 41176 (rounded)

2 Years Ago: 41176.47 / 103% = 39977.16 = 39977 (rounded)

Rearranging this, we get: Original Salary = New Salary / (100% + inflation)

So...

Last Year: 42000 / 102% = 41176.47 = 41176 (rounded)

2 Years Ago: 41176.47 / 103% = 39977.16 = 39977 (rounded)

Oct 31, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Hi,
First of all please check the conditions but as far as i understand the conditions the program would be like this-

#include<stdio.h> #include<conio.h> void main() { int salary,bonus,totalsalary,hours; printf("enter salary"); scanf("%d",&salary); printf("enter hours"); scanf("%d",&hours); if(hours<45 && hours>=40) { bonus=500; } else { if(hours<40 && hours>=35) { bonus=300; } else { if(hours<=30 && hours>20) { bonus=150; } else { bonus=0; } } } totalsalary=salary+bonus; printf("Salary=%d",salary); printf("Bonus=%d",bonus); printf("Total Salary=%d",totalsalary); getch(); }

But the conditiosn given by you are not seems to be correct.Just correct the conditions value if wrong and run the program Thanks! mannu_rakesh

#include<stdio.h> #include<conio.h> void main() { int salary,bonus,totalsalary,hours; printf("enter salary"); scanf("%d",&salary); printf("enter hours"); scanf("%d",&hours); if(hours<45 && hours>=40) { bonus=500; } else { if(hours<40 && hours>=35) { bonus=300; } else { if(hours<=30 && hours>20) { bonus=150; } else { bonus=0; } } } totalsalary=salary+bonus; printf("Salary=%d",salary); printf("Bonus=%d",bonus); printf("Total Salary=%d",totalsalary); getch(); }

But the conditiosn given by you are not seems to be correct.Just correct the conditions value if wrong and run the program Thanks! mannu_rakesh

Aug 04, 2009 | Computers & Internet

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