Question about Office Equipment & Supplies
A HEXAGONAL AQUARIUM. 6 SIDES ARE EACH 16 INCHES BY 23 INCHES. HOW MANY GALLONS OF WATER WILL THIS AQUARIUM HOLD?
That depends. If the sides are 16 inches wide by 23 inches high then the aquarium will hold about 66.2 US gallons or about 55.1 Imperial gallons. If the sides are 23 inches wide by 16 inches high then the capacity is about 95.2 US gallons or about 79.3 Imperial gallons.
Posted on May 12, 2014
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Posted on Jan 02, 2017
SOURCE: calculate gallons of a tank
I assume the length of a side is 16 in, and the height of the prism is 23 inches.
Volume of a prism is V_prism=(Area of base)*(height of prism)
Area of base is made up of the area of the 6 equilateral triangles with sides =16 inches. The height of such triangles is given by 8*SQRT(3).
Use the Pythagorean theorem or the trigonometric ratios to find the height of each of the 6 traingles.
Area of base =6*16*(8*SQRT(3))/2 sq in
Volume =6*8*8*23*SQRT(3) cubic inches
Calculate the value in cubic inches and convert to gallons: I leave that task to you.
Posted on May 12, 2014
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There are some
limiting factors like the oxygen availability and the
filtration processing. I gave you some examples below they all refer for small
or large freshwater fish.
3 cm of adult fish length per 4 liters of water.1 cm
of adult fish length per 30 square centimeters of surface area. 1 inch of adult
fish length per US gallon of water. 1 inch of adult fish length per 12 square
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