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Posted on Jan 02, 2017

that is normal. if you want use the seek or scan buttons.

Apr 30, 2015 | BMW X7 Series Cars & Trucks

To display an even number when an odd number is entered you can add 1.

n= val(text1.text) 'Take the value of n from the textbox.

If n mod 2 =1 then 'If n is an odd number n=n+1 'You make it an even number end if

text2.text = n 'Display it in another textbox.

Please give a good rating to this answer so that I will be encouraged to support people like you having problems with VB6.

n= val(text1.text) 'Take the value of n from the textbox.

If n mod 2 =1 then 'If n is an odd number n=n+1 'You make it an even number end if

text2.text = n 'Display it in another textbox.

Please give a good rating to this answer so that I will be encouraged to support people like you having problems with VB6.

Sep 22, 2011 | Computers & Internet

Yes it is.

Because if x+2 = even number, then x is certainly an even number.

So, 3x+1 = odd number.

x = any even number (replace x by any even number)

Because if x+2 = even number, then x is certainly an even number.

So, 3x+1 = odd number.

x = any even number (replace x by any even number)

Jun 19, 2011 | Computers & Internet

Several ways to do this. **1, 5, 13, 15 17** is one of them.

(1 x 5) + 13 + 15 + 17

**Workings:**

(1 x 5) = 5

5 + 13 + 15 + 17 = 50.

- You cannot add five odd numbers together to make 50. Five odd numbers added together will always be an odd number.

- You cannot add four odd and take an odd number away as this will also total an odd number.

Therefore 2 of the numbers must be multiplied as this enables you to effectively add four odd numbers together to total an even number.

Hope this helps. Got any more?

(1 x 5) + 13 + 15 + 17

(1 x 5) = 5

5 + 13 + 15 + 17 = 50.

- You cannot add five odd numbers together to make 50. Five odd numbers added together will always be an odd number.

- You cannot add four odd and take an odd number away as this will also total an odd number.

Therefore 2 of the numbers must be multiplied as this enables you to effectively add four odd numbers together to total an even number.

Hope this helps. Got any more?

Jan 13, 2011 | Vacuums

this would be explained on the basis of two FACTS below.......

sum of two odd numbers are always even and

sum of to even numbers are also always even

then how 6 odd numbers (consider 3 pairs, 9 5 3 1 being odd numbers) can make an odd number 21..!!

SO SIMPLE

Make your basics strong...

sum of two odd numbers are always even and

sum of to even numbers are also always even

then how 6 odd numbers (consider 3 pairs, 9 5 3 1 being odd numbers) can make an odd number 21..!!

SO SIMPLE

Make your basics strong...

Aug 14, 2010 | Computers & Internet

5 + 5 + 5 + 5 + 1 = 21

That's a 5-number solution and that -I'm afraid- is the closest you're going to get. The numbers are all odd numbers. Add ANY 6 odd numbers together and you'll end up with an even number. 21 is an odd number so:

Answer: There is no possible 6-number solution to this problem.

That's a 5-number solution and that -I'm afraid- is the closest you're going to get. The numbers are all odd numbers. Add ANY 6 odd numbers together and you'll end up with an even number. 21 is an odd number so:

Answer: There is no possible 6-number solution to this problem.

Mar 24, 2010 | Core Learning Calculation Skills: Volume 2...

It can't be done, Nine is an odd number. An odd number of groups, each with an odd number of people, totals an odd number of people. Forty is an even number, so at least one group must have an even number of people.

Mar 06, 2010 | Logitech QuickCam Connect Webcam

factory radios only tune into odd numbers... radios stations broadcast on odd numbers to avoid some frequency interference... ive only see a few aftermarket radios that tune to even numbers also

Nov 03, 2009 | 2004 Chevrolet Blazer

hmm here is a psuedo to consider

input number n

while

n = n / 2

if n = 0 then print n = even , break loop

if n < 0 then print n is odd

loop

input number n

while

n = n / 2

if n = 0 then print n = even , break loop

if n < 0 then print n is odd

loop

Jul 12, 2008 | Computers & Internet

int number = 10 //Insert the number here

if ((number % 2) == 0) { System.out.println(number+" is a even number); } else { System.out.println(number+" is a odd number);

{

Let me know if you need a complete java class for this

if ((number % 2) == 0) { System.out.println(number+" is a even number); } else { System.out.println(number+" is a odd number);

{

Let me know if you need a complete java class for this

Apr 15, 2008 | Computers & Internet

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