Question about The Learning Company Achieve! Math & Science Grades 1-3 (381933) for PC, Mac

Please show me how to set up the solution to this problem... I couldn't figure it out.

Let m represent the subscription rate for a man, and w the subscription rate for a woman.

m/w=4/3, or** m=(4/3)w**.

2 men and 5 women paid 460. Thus

**2m+5w=460.**

Substitute **(4/3)w** for **m**, in **2m+5w=460**.

This gives an equation in the unknown w. Solve for w

2(4/3)w +5w=460 or (23/3)w=460. **Answer is w=60**

Use this value in the relation m=(4/3)w to get m=80.

**Check m/w=80/60=4/3**

Posted on May 09, 2014

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Posted on Jan 02, 2017

m = men

w = women

equation 1

m/w = 4/5

w(m/w) = w(4/5)

m = 4/5w

5(m) = 5(4/5w)

5m = 4w

w = 5/4m

equation 2

m/(w + 18) = 1/2

(w + 18)(m/w + 18) = (w + 18)(1/2)

m = w/2 + 9

2m = w + 18

w = 2m - 18

Substitute equation in equation 2

w = 5/4m

5/4m = 2m -18

4(5/4m) = 4(2m-18)

5m = 8m - 72 multiply by -1

3m = 72

m = 24

solve for w

w = 5/4m

w = 5(24)/4

w = 5 * 6

w = 30 m = 24

w = women

equation 1

m/w = 4/5

w(m/w) = w(4/5)

m = 4/5w

5(m) = 5(4/5w)

5m = 4w

w = 5/4m

equation 2

m/(w + 18) = 1/2

(w + 18)(m/w + 18) = (w + 18)(1/2)

m = w/2 + 9

2m = w + 18

w = 2m - 18

Substitute equation in equation 2

w = 5/4m

5/4m = 2m -18

4(5/4m) = 4(2m-18)

5m = 8m - 72 multiply by -1

3m = 72

m = 24

solve for w

w = 5/4m

w = 5(24)/4

w = 5 * 6

w = 30 m = 24

Jun 05, 2017 | The Computers & Internet

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Sep 14, 2016 | Computers & Internet

Female Ideal Weight - Above Average Height
The average height of a woman in the US is 5-foot-4. When considering the weight and height ratio, a 5-foot-5 woman should weigh between 113 and 138, 5-foot-6 between 117 and 143 **and 5-foot-7 between 122 and 149. **The weight and height ratios continue to increase at approximately 4.5 pounds at the low end and 5.5 pounds at the high end of the range, per inch of height. A 6-foot-tall woman's ideal weight range is 144 to 176 pounds and a 7-foot-tall woman's range is 198 to 242 pounds.
Male Ideal Weight -- Under 6 Feet Tall
Men have an ideal weight range similar to that of women, but their weights are higher per inch. A man who is 5 feet 11 inches tall has an ideal weight range of 155 to 189 pounds, which is significantly higher than the 140- to 171-pound range for women. Men under 6 feet tall can determine their ideal weight without consulting a height-to-weight ratio table by starting at 5-foot-11 and a weight of 155 to 189 pounds. **Simply subtract 5 to 6 pounds per inch from the low of 155 pounds, and 6 to 7 pounds per inch from the high of 189 pounds. Thus, a 5-foot-5 man has a range of 122 to 150 pounds **and a 5-foot-tall man has an ideal weight range between 95 and 117 pounds. Are There Ideal Weight and Height Ratios LIVESTRONG COM

Jul 09, 2014 | Health & Beauty

how to stop the enterfactory from my mobile phone

May 20, 2011 | Cell Phones

The average is 20, it means the total is 60. The sum of ratio is 15 (3+5+7)

Therefore the age of a girl is calculated by multiplying the respective ration with total and dividing by sum of ratio

Age of Eldest girl = 7 x 60 /15 = 28

Hope it helps! Good Luck!

CreativeTECH

Therefore the age of a girl is calculated by multiplying the respective ration with total and dividing by sum of ratio

Age of Eldest girl = 7 x 60 /15 = 28

Hope it helps! Good Luck!

CreativeTECH

Feb 15, 2011 | Computers & Internet

use simultaneous equations, with x = # of men and y = # of women:

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

Jul 09, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

Let x = the width of the women's court. Then 2x is the length of the women's court.

the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4

The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4

The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

Oct 03, 2008 | Computers & Internet

15 men earns 525

1 man raens 525/15

equals to 35

7 women earns 525

1 women earns 75

so 7 men and 13 women earns 7 *35+13*75=245+975=1220

1 man raens 525/15

equals to 35

7 women earns 525

1 women earns 75

so 7 men and 13 women earns 7 *35+13*75=245+975=1220

Dec 11, 2007 | Bagatrix Algebra Solved! 2005 (105101) for...

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