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The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

0 is an integer number in math, where integer numbers are the infinite set: .

Depending on circumstances, the "natural numbers" and "natural numbers with zero" are also sometimes referred to as integers, quietly dropping the "positive" or "non-negative" property of the set.

Note, the former does *not* include 0.

Depending on circumstances, the "natural numbers" and "natural numbers with zero" are also sometimes referred to as integers, quietly dropping the "positive" or "non-negative" property of the set.

Note, the former does *not* include 0.

Mar 22, 2014 | Office Equipment & Supplies

3 times integer(x/20)

where integer(x) is the integer portion of x, discarding any fractional portion.

where integer(x) is the integer portion of x, discarding any fractional portion.

May 05, 2013 | Office Equipment & Supplies

Are you looking to unlock a protected sheet or actually recover the password? I can help you with the former.

Note this will only work to unlock a worksheet. It will not recover the VBA editor password (however this is possible by very hard to explain.)

1) Open the excel sheet you want to unlock,

2) Open VBA editor, (Alt+F11 while in excel)

3) add a module (insert > module)

4) and paste in this code into the main window (big window on the right)

Sub PasswordBreaker()

Dim i As Integer, j As Integer, k As Integer

Dim l As Integer, m As Integer, n As Integer

Dim i1 As Integer, i2 As Integer, i3 As Integer

Dim i4 As Integer, i5 As Integer, i6 As Integer

On Error Resume Next

For i = 65 To 66: For j = 65 To 66: For k = 65 To 66

For l = 65 To 66: For m = 65 To 66: For i1 = 65 To 66

For i2 = 65 To 66: For i3 = 65 To 66: For i4 = 65 To 66

For i5 = 65 To 66: For i6 = 65 To 66: For n = 32 To 126

ActiveSheet.Unprotect Chr(i) & Chr(j) & Chr(k) & _

Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & Chr(i3) & _

Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

If ActiveSheet.ProtectContents = False Then

MsgBox "One usable password is " & Chr(i) & Chr(j) & _

Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _

Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

ActiveWorkbook.Sheets(1).Select

Range("a1").FormulaR1C1 = Chr(i) & Chr(j) & _

Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _

Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

Exit Sub

End If

Next: Next: Next: Next: Next: Next

Next: Next: Next: Next: Next: Next

End Sub

5) Then either:

5a) go back to the excel window, click Developer > Macros > select PasswordBreaker

6) Or just hit the play icon (green triangle) in the top of the VBA editor

This will unlock the sheet, and give you a password which will unlock it in the future.

Note: Due to the encryption method used in excel, there are many possible passwords which will unlock the sheet. This will give you "a" password which will work but it will not be the one that you originally set up. Both the original and this one will still work.

Note this will only work to unlock a worksheet. It will not recover the VBA editor password (however this is possible by very hard to explain.)

1) Open the excel sheet you want to unlock,

2) Open VBA editor, (Alt+F11 while in excel)

3) add a module (insert > module)

4) and paste in this code into the main window (big window on the right)

Sub PasswordBreaker()

Dim i As Integer, j As Integer, k As Integer

Dim l As Integer, m As Integer, n As Integer

Dim i1 As Integer, i2 As Integer, i3 As Integer

Dim i4 As Integer, i5 As Integer, i6 As Integer

On Error Resume Next

For i = 65 To 66: For j = 65 To 66: For k = 65 To 66

For l = 65 To 66: For m = 65 To 66: For i1 = 65 To 66

For i2 = 65 To 66: For i3 = 65 To 66: For i4 = 65 To 66

For i5 = 65 To 66: For i6 = 65 To 66: For n = 32 To 126

ActiveSheet.Unprotect Chr(i) & Chr(j) & Chr(k) & _

Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & Chr(i3) & _

Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

If ActiveSheet.ProtectContents = False Then

MsgBox "One usable password is " & Chr(i) & Chr(j) & _

Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _

Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

ActiveWorkbook.Sheets(1).Select

Range("a1").FormulaR1C1 = Chr(i) & Chr(j) & _

Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _

Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)

Exit Sub

End If

Next: Next: Next: Next: Next: Next

Next: Next: Next: Next: Next: Next

End Sub

5) Then either:

5a) go back to the excel window, click Developer > Macros > select PasswordBreaker

6) Or just hit the play icon (green triangle) in the top of the VBA editor

This will unlock the sheet, and give you a password which will unlock it in the future.

Note: Due to the encryption method used in excel, there are many possible passwords which will unlock the sheet. This will give you "a" password which will work but it will not be the one that you originally set up. Both the original and this one will still work.

Jan 20, 2013 | Excel-Tool Excel Tool VBA Password...

For integer powers of 10 you can use the EE shortcut. [2nd][,] displays E.

For non-integer values of the exponent (such as -5.34) you must use the key sequence [2nd][LOG] (10^x) then enter your negative non-integer exponent.

For non-integer values of the exponent (such as -5.34) you must use the key sequence [2nd][LOG] (10^x) then enter your negative non-integer exponent.

Jan 16, 2012 | Texas Instruments TI-84 Plus Silver...

Actually, the answer is 79.

The fx-115ES does not have a key for the modulus operation. Nor does it have an integer-part or fractional-part operation. However, it is possible to calculate the remainder using integer arithmetic.

Press MODE 4 to shift into integer mode. Then type in 3 5 2 - 9 1 * ( 3 5 2 / 9 1 ) = and see the answer 79. It's a pain as both numbers have to be entered twice, but it does get the job done.

To get back to working with real numbers again, press MODE 1 ( or MODE 2 for complex).

The fx-115ES does not have a key for the modulus operation. Nor does it have an integer-part or fractional-part operation. However, it is possible to calculate the remainder using integer arithmetic.

Press MODE 4 to shift into integer mode. Then type in 3 5 2 - 9 1 * ( 3 5 2 / 9 1 ) = and see the answer 79. It's a pain as both numbers have to be entered twice, but it does get the job done.

To get back to working with real numbers again, press MODE 1 ( or MODE 2 for complex).

Feb 26, 2011 | Casio FX-115ES Scientific Calculator

Use the rand() function. If you give it a positive integer argument *n*, it will return a random integer in the range in the interval [1, *n*]. You'll find rand() in the MATH/PROBABILITY menu.

Dec 08, 2010 | Texas Instruments TI-89 Calculator

According to the TI-89 Guidebook:

This notation indicates an “arbitrary integer” that represents any integer. When an arbitrary integer occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @n0.

Hope this helps. If you need any more info just ask away! :)

This notation indicates an “arbitrary integer” that represents any integer. When an arbitrary integer occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @n0.

Hope this helps. If you need any more info just ask away! :)

Jan 21, 2009 | Texas Instruments TI-89 Calculator

The picture link didn't work for me... and seeing as you asked in August of 2008, I'm certain you don't need this answer, but here you go...

According to the TI-89 Guidebook:

This notation indicates an “arbitrary integer” that represents any integer. When an arbitrary integer occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @n0.

This notation indicates an “arbitrary constant” that represents any integer. When an arbitrary constant occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @0.

So it's the same concept, just a little different. It all depends if it is shown as @n1 or @1 where 1 can be any integer to 255

Hope this helps

According to the TI-89 Guidebook:

This notation indicates an “arbitrary integer” that represents any integer. When an arbitrary integer occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @n0.

This notation indicates an “arbitrary constant” that represents any integer. When an arbitrary constant occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @0.

So it's the same concept, just a little different. It all depends if it is shown as @n1 or @1 where 1 can be any integer to 255

Hope this helps

Aug 28, 2008 | Texas Instruments TI-89 Calculator

The greatest integer function (also called a step function) is actually a piecewise defined function with a special definition. The function has the notation f(x)=||x|| or f(x)=[[x]] when it is written, but the TI-83 and the TI-84 designate this function by using f(x)=int(x) and is found in the MATH NUM menu. This function is the greatest integer less than or equal to x. So, f(1)=1 and f(1.4)=1. Since this is a piece-wise function you should use DOT mode.

Mar 21, 2008 | Texas Instruments TI-84 Plus Calculator

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