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What is the length of a rectangle if the area is 12.75 and the with is 1.5

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8.5

Posted on May 06, 2014

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The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?


We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

1 Answer

X(2x+3)=90


Solve the resulting quadratic equation
2X^2+3X-90=0
Discriminant: (3)^2-4(2)(-90)=729=(27)^2
Two roots
X_1=(1/4)*(-3+27)=6
X-2=(1/4)*(-3-27) =-(15/2), negative
Since the width must be positive, reject the negative root and keep X_1=6
Width =6
Length=2(6)+3=15

Check 6*(15)=90. Checks OK

Apr 23, 2014 | Office Equipment & Supplies

1 Answer

Volume of rectangle formula


A rectangle is a two-dimensional figure and doesn't have a volume. It has an area equal to length times width. A rectangular prism has a volume equal to length times width times height.

Feb 06, 2014 | Office Equipment & Supplies

1 Answer

Area of rectangle is 4122cm2 .width of rectangle is 3cm.how do i find the length of it


Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

Mar 02, 2011 | Office Equipment & Supplies

1 Answer

If you know about area formulas of class 8 and 9,please solve my question?there is a circle.in the between of the circle,there is a rectangle of dimension 4cm and 3cm.if the rectangle will cut out what...


The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2


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Jan 31, 2011 | Computers & Internet

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How do i find area of a rectangle that has 1 straight side and the other is a triangle its irregular plz keep it simple / -------------I /-------------I


You shape is a rectangle and a right angled triangle. You need to divide it into the rectangle and the right angled triangle and add the areas.
Area of a rectangle is length * width
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Then just add the two together.

Oct 08, 2009 | The Learning Company Achieve! Math &...

1 Answer

Code for method parseInt() in java


parseInt(java.lang.String, int)

This code takes two arguments, a string constructor from the Java language and an integer. Its purpose is to parse (meaning de-construct or disassemble into component parts) one data type into another.

Here is an example of a Java program to specify and print out the dimensions of a rectangle, taken from the page http://www.roseindia.net/java/beginners/entervaluesfromkeyboard.shtml:

class Rectangle{
int length, breadth;
void show(int x, int y){
length = x;
breadth = y;
}
int calculate(){
return(length * breadth);
}
}
public class EnterValuesFromKeyboard{
public static void main(String[] args) {
Rectangle rectangle = new Rectangle();
int a = Integer.parseInt(args[0]);
int b = Integer.parseInt(args[1]);
rectangle.show(a, b);
System.out.println(" you have entered these values : " + a + " and " + b);
int area = rectangle.calculate();
System.out.println(" area of a rectange is : " + area);
}
}

Apr 09, 2009 | Sun Java Programming Language (cdj-275)

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