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Algebra give the common factors of the numerator and the denominator of the following rational expressions. 1. 4c/6c 2. 2xy/3x 3. 8a2c/-4ac2 4. -14abc/12ac 5. (-3r)(-4s)/-18r2

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  • ebredy May 11, 2010

    the answer for 1 & 2 is the following:
    1. 2c

    2. x

    However for problem 3 I need to know if the bottom expression -4ac2 is C to the second power. the same question for problem 4 is it 12aC to the 5th power and in problem 5 is it -18r to the second power?



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1.2c 2.x 3.8ac 4 .2ac 5.12r...hope these answers are helpful to you..

Posted on Aug 29, 2009

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Factorise the numerator
Factorise the denominator
What factors you common? It is that simple.
Question 1 4c/6c means 4xc/6xc
4 and c are factors at the top; 6 and c are factors at the bottom.
So, which is the common factor? c of course

Now do the rest
I will give a hand to do Question 5
Factorise the numerator. It gives -3 x r x -2 x 2 x s
factorise the denominator -3 x 3 x 2 x r x 2
Now, carefully pick up the common factors which are -3 and 2 and r
So, the answer is -6r
Hope you understand the process
Good luck
luciana44


Posted on Mar 03, 2010

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How can I simplify a fraction after adding two fractions?


Factor both the numerator and denominator, and then divide both the numerator and denominator by the greatest common factor.

For example, 1/3 + 1/6 = 2/6 + 1/6 = 3/6. We have to simplify 3/6. The factors of 3 are 3 and 1. The factors of 6 and 1, 2, 3, and 6. The greatest common factor is 3. Dividing the numerator and denominator by 3 results in 1/2.

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What is a mixed number or in a fraction in simplest form 0.15%


A mixed number is a number composed of an integer (whole) number and a proper fraction, one that has a numerator less than the denominator. Example 2 1/3 =2+ 1/3. 2 is the integer part, and 1/3 is the proper fraction part.
Certain fractions can be simplified further because the numerator and denominator share a (common) factor. By cancelling the common factor in the numerator with the factor in the denominator,
one gets a fraction with smaller numerator and denominator.
For example the percentage you provide 0.15% can be converted to 15/10000.
Since 15 and 1000 are both multiples of 5, the number 5 is a common factor in both. 15=5*3, and 10000=5*2000
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3sqroot6 + 5sqroot2 over 4sqroot6 - 3sqroot2


Do you have a question? Rationalize the denominator, rationalize the numerator, evaluate the expression?

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Mathematics sign in


It is not possible to give a general answer to such a question. If you have a fraction, simplifying it entails dividing by factors that are common to the denominator and the numerator. If you have an algebraic expression such as a polynomial you simplify it by combining like terms until you have only one term of each type. A trigonometric expression can be compacted, etc.

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How do I convert square roots (for example square root of 147) into a number like 7 over square root 3. is it possible to do that? Or can the TI-130Xa only convert perfect squares (like square root o


Unfortunately this calculator does not display results in radical form. If you enter SQRT(147) you get 12.12435565...
What you are asking for is called rationalizing an irrational expression. Usually one tries to get rid of radicals that appear in the denominators. Here is an example.
Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?
Recall the identity (a-b)*(a+b)= a^2-b^2. It is true for any a and b

Rationalizing a denominator (usual case)
Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))
[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=c^2-d
You see that there is no radical.
Now take 1/(c+SQRT(d)). To get rid of the radical from the denominator multiply it by (c-SQRT(d)). But to leave the value of your expression 1/(c+SQRT(d)) unchanged, you must multiply both numerator and denominator by (c-SQRT(d)).
The numerator becomes 1*(c-SQRT(d))=c-SQRT(d), and the denominator (c^2-d).
Finally, the rationalized form of the expression 1/(c+SQRT(d)) is
[c-SQRT(d)]/[c^2-d].

Rationalizing a numerator
Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same
Example:(c+SQRT(d)), the denominator here is 1
(c+SQRT(d))=(c+SQRT(d))*[c-SQRT(d)]/[c-SQRT(d)]. This gives
[c^2-d]/[c-SQRT(d)]
You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.
Your case is a lot simpler
SQRT(147)=7*SQRT(3)
Multiply it by SQRT(3)/SQRT(3) which is 1. This gives
SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

SQRT(147)= 21/SQRT(3)

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If your calculator is SetUp for Math Input/Output (MATHIO), a result that gives a radical will remain in radical form. If a radical appears in a denominator the whole expression is rationalized: Any radical left is put in the numerator. 1/Sqr(3) is displayed as Sqr(3)/3.

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hi maybe the formula below will help you

A rational number is a number that can be expressed as a fraction with an integer numerator and a non-zero natural number denominator. Fractions are written as two numbers, the numerator and the denominator, with a dividing bar between them. In the fraction written mn or
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