X(2x+3)=90 The length of a rectangle is 3 cm longer than twice the width. The area of the rectangle is 90 sq cm. Find the length and the width of the rectangle.

Width is 10 metres
Length is 12 metres
Derive an equation for area in the form of x
Area= length x width
120sqm = x(x-2)
120sqm = xsquared - 2x
Then apply to formula for solving a quadratic equation.
Hope that helps.

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15cm by 6cm

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Since the 'base' and 'top' of any prism have the same shape, the surface area can be found by

• surface area of prism = 2 * area of base + perimeter of base * H

So for the rectangular prism in your example..

• surface area = 2LW + 2(L+W)H
• = 2 * 7 * 4 + 2*(7+4)*5
• = 56 + 2 * 11 * 5
• = 56 +110
• = 166 sq cm

Hope this helps

Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.
to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.



2. let the length of rectangle be x cm
and breadth = 20 cm
now original perimeter = 2(x+20) cm


new length = x-30 cm
breadth remains same = 20 cm
new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2
2(x-10) = 2(x+20) /2
2x -20 = x + 20
x = 40 cm


hence length of longer side 40 cm.

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The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2


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Hi amita_mediai

Do this:
1*3*20
Explanation
Multiply the length and the width. This gives the area in sq ft. Multiply this with 20. This will be the cost in rs.
Good luck
luciana44

The length of a rectangle is twice its width w. a second rectangle, which is 8 cm longer and 3 cm narrower than the first rectangle, has perimeter 154 cm. Make a sketch of the rectangles expressing all dimensions of w. Then find the dimensions of each rectangle.

Let x = the width of the women's court. Then 2x is the length of the women's court.
the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4
The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh