5x1 + 6x2 - 2x3 + 7x4 +4x5 = 0, 2x1 + 3x2 - x3 + 4x4 + 2x5=0, 7x1 + 9x2 -3x3 + 5x4 + 6x5=0, 5x1 +9x2 - 3x3 + x4 + 6x5 =0

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Posted on Jan 02, 2017

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SOURCE: algebra college

Consider the following system of **3 equations in 3 unknowns**:

*x + y = *2**2 x + 3y + z = 4**

- Subtract 2*(Row1) from Row2 and place the result in the second row; subtract Row1 from Row2 and place in the third row. Leave Row1 as is.

- Subtract Row2 from Row3, and place the result in row3. Leave Row1 and Row2 as they are.

Posted on Sep 17, 2008

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Sorry, I don't have that calculator, but let's see if we can work this out. "Linear Interpolation" means find the value of y for a given value of x from a line of best fit, within the range of values that you are given.

Hopefully, this helps. If not, let me know and we will explore more.

Good luck,

Paul

Hopefully, this helps. If not, let me know and we will explore more.

Good luck,

Paul

Apr 22, 2015 | Casio Algebra FX 2.0 Calculator

The Toyota Matrix.

Apr 16, 2013 | Office Equipment & Supplies

You should consult a Linear Algebra book. Besides, these calculator cannot handle matrices of dimensions 4x4 or higher . With matrices of dimension 3x3 and less it is probably easier to use the Cramer rules directly.

Nov 06, 2012 | Texas Instruments TI-30 XIIS Calculator

Thhe Casio FX-9860G SD can solve a polynomial equation
of degree 2 or 3 with REAL coefficients. If the complex MODE is set to
REAL it will find the real roots. If the complex mode is set to** a+ib**, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Alternatively, after you create the system of 4 linear equations you can use the matrix utility to find Real(x), Im(x), Real(y) and Im(y) and recompose the x and y.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Alternatively, after you create the system of 4 linear equations you can use the matrix utility to find Real(x), Im(x), Real(y) and Im(y) and recompose the x and y.

Mar 17, 2012 | Casio FX-9860G Graphic Calculator

The Casio FX-9860G SD can solve a polynomial equation
of degree 2 or 3 with REAL coefficients. If the complex MODE is set to
REAL it will find the real roots. If the complex mode is set to** a+ib**, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Mar 17, 2012 | Casio Office Equipment & Supplies

Sorry, but you cannot calculate limits of functions with this calculator. It does not have a Computer `Algebra System (CAS). For that you need a graphing calculator with CAS: Casio ClassPad 300, 300PLUS, 330, HP 48 GII, HP49 G/ G+, HP 50G, TI-NSPIRE CAS, TI89 Titanium, TI 92/92PLUS, TI Voyage 200 PLT. It is still a very good scientific (non graphing) calculator

However, you can calculate numerical derivatives, and numerical integrals, solve linear and non-linear equations.

Even though this post does meet your expectations, do not let that prevent you from rating it.

However, you can calculate numerical derivatives, and numerical integrals, solve linear and non-linear equations.

Even though this post does meet your expectations, do not let that prevent you from rating it.

Jan 21, 2010 | Casio FX-115ES Scientific Calculator

Assuming that band A charges a flat price, their price would simply be

A = 600

Band B's price would be

B = 350 + 1.25X

where X = number of tickets sold.

Set them equal and solve for X to figure the break-even point:

600 = 350 + 1.25X

250/1.25 = X

X = 200

If you have fewer than 200 people, Band B is the better deal; more than 200, you're better off with Band A.

A = 600

Band B's price would be

B = 350 + 1.25X

where X = number of tickets sold.

Set them equal and solve for X to figure the break-even point:

600 = 350 + 1.25X

250/1.25 = X

X = 200

If you have fewer than 200 people, Band B is the better deal; more than 200, you're better off with Band A.

Dec 18, 2009 | SoftMath Algebrator - Algebra Homework...

if you x and y concepts in problem then try to form one equation such as in linear or quadratic or your choice and make sure of x and y concepts in algrebra as x and y co -ordinate directions in graph

Oct 04, 2009 | SoftMath Algebrator - Algebra Homework...

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Find general solution of the given system of liner equation. Write general solution in terms of fundamental set of solution. What are the dimension and basis of Null space for a given system? 5x1 + 6x2 - 2x3 + 7x4 +4x5 = 0, 2x1 + 3x2 - x3 + 4x4 + 2x5=0, 7x1 + 9x2 -3x3 + 5x4 + 6x5=0, 5x1 +9x2 - 3x3 + x4 + 6x5 =0

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