Question about Mathsoft StudyWorks! Mathematics Deluxe 5.0 (11513) for PC

0=1/2x+y find x intercept and y intercept

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Have you graphed the equation? Are you asking someone to solve and give you the answer or tell you how to use your software?

Posted on Jun 19, 2009

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Rewrite the equation in the form y=mx + b, where m is the slop and b is the y intercept. To find the x intercept just solve for x with y being 0. when you rewrite the equation you get 0=1/2(x) + Y, bring the y to the other side and now you have -y=1/2(x) now divide off the neg sign and you will end up with y= -1/2(x), notice there is no b in this equation so the y intercept is at 0, if you set x to zero (which is where the y intercept would be you get y=0) now set y =0 and you get 0=-1/2x divide off the -1/2 and you get x=0. So this line goes through the origin and the x and y intercepts are both zero. The slope of the line is -1/2 so it decrease going from left to right.

Posted on Jun 26, 2009

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1) A car has a value of $25,000 when purchased. It depreciates at a rate of $1,500 per year for the first five years.

a) Write a function ff to approximate the value of the car for the years .

b) Use that function to find the value of the car at the end of three years.

a)the function is f(t)

Posted on Jul 20, 2010

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Posted on Jan 02, 2017

First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul

Desmos Beautiful Free Math

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul

Desmos Beautiful Free Math

Jun 09, 2014 | Office Equipment & Supplies

Use the definitions of the intercepts.

x-intercepts (or zeros or roots) are the values of the independent variables that make the function equal to zero. To obtain an intercept set y=0 in equation : 5x=-10, mean x=-10/5=-2

y-intercept: value of y when x=0.

Just set x=0 in equaltion and solve for y

-4y=-10, gives y=5/2

And Sorry, I cannot enter the answer in the drop box.

x-intercepts (or zeros or roots) are the values of the independent variables that make the function equal to zero. To obtain an intercept set y=0 in equation : 5x=-10, mean x=-10/5=-2

y-intercept: value of y when x=0.

Just set x=0 in equaltion and solve for y

-4y=-10, gives y=5/2

And Sorry, I cannot enter the answer in the drop box.

May 10, 2012 | SoftMath Algebrator - Algebra Homework...

x-intercept: set y=0, and find x=4

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

Jan 12, 2012 | Mcgraw-Hill Glencoe Algebra 1 Florida...

x-intercept (or zero of the function)

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Aug 27, 2011 | Texas Instruments TI-84 Plus Calculator

This should start wit X=something and Y=something, sorry I'm not an human algebra calculator....

Jul 29, 2011 | Computers & Internet

That is an equation describing a straight line. The "slope-intercept" form of a line is

y = mx + b

where m is the slope (change in y-value / change in x-value)

and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

y = mx + b

where m is the slope (change in y-value / change in x-value)

and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

Jul 12, 2011 | Sewing Machines

2x + 4y = -8 ; divide each side by 2

x + 2y = -4 ; subtract x from both sides

2y = -4 - x ; rearrange

2y = -1x -4 ; divide each side by 2

y = -1/2x - 2 ; relate to slope/intercept form of line (y=mx+b)

implies there are multiple solutions that fall along a line with slope -1/2 and y intercept of -2

'

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++++++++++

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Sample points on this line are (-4,0), (-2,-1), (0,-2), (2,-3)

x + 2y = -4 ; subtract x from both sides

2y = -4 - x ; rearrange

2y = -1x -4 ; divide each side by 2

y = -1/2x - 2 ; relate to slope/intercept form of line (y=mx+b)

implies there are multiple solutions that fall along a line with slope -1/2 and y intercept of -2

'

\ '

++++++++++

\ '

\ '

Sample points on this line are (-4,0), (-2,-1), (0,-2), (2,-3)

Nov 04, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

use the slope-intercept form to graph y=2/3x+4

Mar 31, 2010 | Computers & Internet

You can solve it with following method.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

Mar 03, 2010 | Office Equipment & Supplies

2x-4y=8

=> 2[x-2y]=8

=> x-2y=8/2

=>** x-2y=4**

=> 2[x-2y]=8

=> x-2y=8/2

=>

Feb 07, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

Nov 08, 2011 | Mathsoft StudyWorks! Mathematics Deluxe...

Jul 26, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

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how do I get the y intercept from -2x+y=8

y-intercept form

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