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Posted on Jan 02, 2017

SOURCE: Ralph's garden is in the shape of a square.

The total area of the garden will increase 4 fold.

Posted on May 03, 2011

The hypotenuse length is 5.

Mar 10, 2017 | Homework

Let's break the question down.

Let x be the length of a side of a square - since it is a square, all the sides by definition are all the same length

Perimeter of a square - P = 4x

Area of a square A = x * x

We know the area is 24 square centimeters, so

24 = x * x

Thus, x = sqrt (24)

x is approximately 4.90 centimeters.

Therefore, the perimeter is 4.90 x 4.

Good luck,

Paul

Let x be the length of a side of a square - since it is a square, all the sides by definition are all the same length

Perimeter of a square - P = 4x

Area of a square A = x * x

We know the area is 24 square centimeters, so

24 = x * x

Thus, x = sqrt (24)

x is approximately 4.90 centimeters.

Therefore, the perimeter is 4.90 x 4.

Good luck,

Paul

Mar 01, 2017 | The Office Equipment & Supplies

your measurements are in different units, say **feet** and **inches**, you can first convert those values to **feet**, then multiply them together to get the **square footage** of the area. If you are measuring a **square** or rectangle area, multiply length times width; Length x Width = Area.

Aug 23, 2016 | Office Equipment & Supplies

Find the scaling ratio

Perimeter of first pentagon is 12*5=60 cm

Scale factor (2nd/first)=140/60 =7/3

**Ratio of areas varies as the square of the scale factor for the lengths**

Area of second / area of first =(7/3)^2 =49/9

Area of second pentagon =**248 *(49/9) cm^2**

Finish the calculation.

Perimeter of first pentagon is 12*5=60 cm

Scale factor (2nd/first)=140/60 =7/3

Area of second / area of first =(7/3)^2 =49/9

Area of second pentagon =

Finish the calculation.

Jul 01, 2014 | Texas Instruments TI-83 Plus Calculator

The two pentagons are similar. If k is the scale factor for the lengths, the ratio of the areas is k^2.

Pent 1 side =12 cm

Pent 2 side =140/5 =28 cm

Scale factor (larger over smaller) is k=28/12=7/3

Area of Pent_2= (49/9)*Area of Pent_1

Your answer should be C.

Pent 1 side =12 cm

Pent 2 side =140/5 =28 cm

Scale factor (larger over smaller) is k=28/12=7/3

Area of Pent_2= (49/9)*Area of Pent_1

Your answer should be C.

Jun 29, 2014 | Office Equipment & Supplies

The figure are similar, corresponding sides are proprtional

L1/L'1=L2/L'2= ... =k , the scale factor for lengths.

However, if scale factor for lengths is k, the ratio of area is k^2 find

**Scale factor**

Use the given area to find the proportionality factor then use it the ratio of length to find the missing distance between the parallel sides.

Area of new /Area of old=360/250=36/25=k^2

k=SQRT(36/25)=6/5

**Ratio of lengths =k=6/5**

Distance between parallel sides of new patio/Distance between parallel sides of old patio=6/5

Distance between parallel sides of new patio= (6/5)*12.5=15

**The distance between the parallel sides of the new patio is 15 feet.**

L1/L'1=L2/L'2= ... =k , the scale factor for lengths.

However, if scale factor for lengths is k, the ratio of area is k^2 find

Use the given area to find the proportionality factor then use it the ratio of length to find the missing distance between the parallel sides.

Area of new /Area of old=360/250=36/25=k^2

k=SQRT(36/25)=6/5

Distance between parallel sides of new patio/Distance between parallel sides of old patio=6/5

Distance between parallel sides of new patio= (6/5)*12.5=15

Dec 17, 2013 | Office Equipment & Supplies

The figure are similar, corresponding sides are proprtional

L1/L'1=L2/L'2= ... =k , the scale factor for lengths.

However, if scale factor for lengths is k, the ratio of area is k^2 find

**Scale factor**

Use the given area to find the proportionality factor then use it the ratio of length to find the missing distance between the parallel sides.

Area of new /Area of old=360/250=36/25=k^2

k=SQRT(36/25)=6/5

**Ratio of lengths =k=6/5**

Distance between parallel sides of new patio/Distance between parallel sides of old patio=6/5

Distance between parallel sides of new patio= (6/5)*12.5=15

**The distance between the parallel sides of the new patio is 15 feet.**

L1/L'1=L2/L'2= ... =k , the scale factor for lengths.

However, if scale factor for lengths is k, the ratio of area is k^2 find

Use the given area to find the proportionality factor then use it the ratio of length to find the missing distance between the parallel sides.

Area of new /Area of old=360/250=36/25=k^2

k=SQRT(36/25)=6/5

Distance between parallel sides of new patio/Distance between parallel sides of old patio=6/5

Distance between parallel sides of new patio= (6/5)*12.5=15

Dec 17, 2013 | Office Equipment & Supplies

There are some
limiting factors like the oxygen availability and the
filtration processing. I gave you some examples below they all refer for small
or large freshwater fish.

3 cm of adult fish length per 4 liters of water.1 cm
of adult fish length per 30 square centimeters of surface area. 1 inch of adult
fish length per US gallon of water. 1 inch of adult fish length per 12 square
inches of surface area.

Aug 02, 2012 | Fish

Let the sides of the cubes be a and b,

the length of the diagonal of the cube whose side is b is given as square root(3)*b

according to the given question,

a=square root(3)*b

the volume of the cube with side a is given as

v1=a^3=(square root(3)*b)^3

and the volume of the cube with side b is

v2=b^3

then their ratio of volumes is given as

v1/v2=3*square root(3)*b^3/b^3=3*square root(3)

i.e v1:v2=3*square root(3):1

Next qwasthun pwease :D

the length of the diagonal of the cube whose side is b is given as square root(3)*b

according to the given question,

a=square root(3)*b

the volume of the cube with side a is given as

v1=a^3=(square root(3)*b)^3

and the volume of the cube with side b is

v2=b^3

then their ratio of volumes is given as

v1/v2=3*square root(3)*b^3/b^3=3*square root(3)

i.e v1:v2=3*square root(3):1

Next qwasthun pwease :D

Jan 06, 2011 | Jenn-Air Freezer Jenn Air Clear Cube Ice...

this is a math problem?

the area of the old square was 100, the new one is 225

say the old squares side was X, so the area was X^2

the new square has area 2.25 X^2

take the square root to find the side of the new square: 1.5 X

so we know that the side of the old square plus 5cm is the side of the new square. so X + 5 = 1.5 X

solve that to find X = 10,

so the area of the old square was X ^ 2 = 100

and the area of the new square is 2.25 X ^ 2 = 225 :)

the area of the old square was 100, the new one is 225

say the old squares side was X, so the area was X^2

the new square has area 2.25 X^2

take the square root to find the side of the new square: 1.5 X

so we know that the side of the old square plus 5cm is the side of the new square. so X + 5 = 1.5 X

solve that to find X = 10,

so the area of the old square was X ^ 2 = 100

and the area of the new square is 2.25 X ^ 2 = 225 :)

Aug 10, 2008 | Lenovo ThinkPad R60 with Wireless Wide...

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