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It depends on how complex the function is; there are different techniques. For a straight line of the standard form, usually shown as y=mx+b; this is a simple function of y in terms of x. So, determining the function in this case means finding values for m and b. --- m is the slope of the line, commonly called rise over run. Since your question asks in terms of coordinates, I would assume that you are looking at a problem giving you 2 points.

Probably something like p1 = (3,4); p2 = (5,8); the general form of this is p1=(x1,y1); p2=(x2,y2). The slope in this case is rise over run, in other words, the change in y divided by the change in x. This can be calculate between these two points as (y2-y1)/(x2-x1). In my sample above, this would be (8-4)/(5-3) = 4/2 = 2 giving the value of m.

To find the value of b (the y intercept) you need the value of y when x = 0. Since you already know that m, the slope is 2, consider a new point, call it p3 (x3,y3), pick either of the known points and solve the slope equation again, this time for y3. [m=(y3-y1)/(x3-x1)]. We know that x3 is 0, since we are trying to solve for y where that is true, so the equation becomes:

m=(y3-y1)/(-x1)

-x1*m=y3-y1

y3=y1-x1*m

y3 is really b in the standard form, since it is, by definition the intercept, or the value when x=0,

so

b=y1-x1*m -- this gives you the y intercept anytime you know the slope and one point on the line.

In the example, y1 = 4, x1=3 and we've already calculated m to be 2, so

b=4-3*2 = -2

So, the function would be

y = 2x -2

To check, plug in the values of the other point, p2, and see if they work

y2 = 2*x2 - 2

8=2*5-2

It's easier than it looks. It can help you to understand if you get some old fashioned graph paper and plot it so you can see what is happening.

Posted on Jun 18, 2009

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Posted on Jan 02, 2017

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Hi there,

To get the coefficient of determination you need to be in STAT mode (press MODE and choose 1 for stat) and then choose 1 for line (it only works for linear data). Type in your coordinate points (type in the x value then press the button next to ENT that says (x,y) and then type in your y value and press ENT. Your screen should then say DATA SET = 1.00.

Enter a few more coordinates.

Then to get your coefficient of determination press ALPHA (the blue green button under 2nd F) and press the ( button (above it in blue you will see r). Press = and there is your coefficient of determination.

To get the coefficient of determination you need to be in STAT mode (press MODE and choose 1 for stat) and then choose 1 for line (it only works for linear data). Type in your coordinate points (type in the x value then press the button next to ENT that says (x,y) and then type in your y value and press ENT. Your screen should then say DATA SET = 1.00.

Enter a few more coordinates.

Then to get your coefficient of determination press ALPHA (the blue green button under 2nd F) and press the ( button (above it in blue you will see r). Press = and there is your coefficient of determination.

Apr 14, 2014 | Sharp EL-738 Scientific Calculator

if by theta function you mean the change to polar coordinates function, type in your x and y coordinate for example (3; 4) to do this press 3 (x,y) key 4 then 2nd F (the orange button) and then 8 (the theta function) and then r will be 5 and theta will be 53.13010235. If you have the polar coordinates and want to change to rectangular coordinates type in the hypotenuse (x,y) button and then the angle and then press 2nd F and 9 and it will give you the x and y coordinates.

If you have any more questions there is a dedicated website http://www.mathsatsharp.co.za/ where you can leave questions about the SHARP calculators on the student page and they will be answered within a week maximum.

If you have any more questions there is a dedicated website http://www.mathsatsharp.co.za/ where you can leave questions about the SHARP calculators on the student page and they will be answered within a week maximum.

Sep 08, 2013 | Sharp EL-506 Calculator

Given your limited description, PQ can be any length (though equal to QR) and the point R can be anywhere in the coordinate space. Would you care to provide some additional details? Perhaps a diagram?

Aug 26, 2013 | McGraw Hill Higher Education Calculus and...

Draw the graphs
of the functions you are interested in. While the graphs are displayed
Press the Menu key. In the drop down window locate the sub menu Settings
(number 8 or 9) depending on your calculator

The following screen is displayed with at the top the setting Float.

Follow the right pointing arrow on the same line as float and select Float 3 or 4 as on the screen capture that follows

Point to the graph of one of the functions select it then press the menu select option Analyze graph then intersection.

You will be asked to select the second function, then the lower bound and upper bound. As you see on the previous screen capture, the coordinates of the intersection point are given with 3 decimal digits.

The following screen is displayed with at the top the setting Float.

Follow the right pointing arrow on the same line as float and select Float 3 or 4 as on the screen capture that follows

Point to the graph of one of the functions select it then press the menu select option Analyze graph then intersection.

You will be asked to select the second function, then the lower bound and upper bound. As you see on the previous screen capture, the coordinates of the intersection point are given with 3 decimal digits.

Apr 27, 2013 | Office Equipment & Supplies

Assuming -31 to be the first term and not the zeroth term, the nth term is 3n-34. This makes 92 the 42nd term.

Mar 07, 2013 | Cars & Trucks

The Pol function converts coordinates from rectangular to polar. Pol(x,y) converts the rectangular coordinates (x,y) to polar coordinates (r, theta).

For examples and instructions, see page E-37 of the manual and example #036 in the Appendix.

For examples and instructions, see page E-37 of the manual and example #036 in the Appendix.

Dec 07, 2012 | Casio FX-115ES Scientific Calculator

Use a piece of graph paper. Easy.

Nov 19, 2012 | Computers & Internet

Just return to the Y= function editor and type your function again. Press Graph or 2nd GRAPH and you will find your table.

Sep 09, 2011 | Texas Instruments TI-84 Plus Silver...

Let us start by setting the terminology right: To locate a point on a plane you need two coordinates ( an X-value and a Y-value). If the point is in space, you need a third coordinate which may be called z, but let's us not complicate things unecessarily.

With just two coordinates, we will be able to locate at best one point.

Let us rephrase the problem: When given two sets of coordinates, how to calculate the distance between the two points.

Let (x1,y1) and (x2,y2) be the coordinates of two points in a plane. To calculate the distance between the points, one uses the formula

d (distance)= square root of ( (x2-x1)^2+(y2-y1)^2)

When you calculate the distance you must substitute actual coordinates for X1, Y1, X2 and Y2.

As regards the bearing, I am afraid that I am no expert in maritime nor in aircraft navigation and I will not venture stray out of my area of competence. However, I know that you need an axis that defines the direction with respect to which angles are measured.

If your reference axis is the horizontal axis on a cartesian plane you can determine the angle that the line joining the points makes with that horizontal axis by calculating its cosine, then extract the arcosine.

If (X2-X1) and (Y2-Y1) are both positive then cos(theta)=(X2-X1)/d, where d is the distance (positive value) calculated above.

With just two coordinates, we will be able to locate at best one point.

Let us rephrase the problem: When given two sets of coordinates, how to calculate the distance between the two points.

Let (x1,y1) and (x2,y2) be the coordinates of two points in a plane. To calculate the distance between the points, one uses the formula

d (distance)= square root of ( (x2-x1)^2+(y2-y1)^2)

When you calculate the distance you must substitute actual coordinates for X1, Y1, X2 and Y2.

As regards the bearing, I am afraid that I am no expert in maritime nor in aircraft navigation and I will not venture stray out of my area of competence. However, I know that you need an axis that defines the direction with respect to which angles are measured.

If your reference axis is the horizontal axis on a cartesian plane you can determine the angle that the line joining the points makes with that horizontal axis by calculating its cosine, then extract the arcosine.

If (X2-X1) and (Y2-Y1) are both positive then cos(theta)=(X2-X1)/d, where d is the distance (positive value) calculated above.

Feb 27, 2010 | Casio FX-7400G Plus Calculator

Mark a waypoint, then edit the waypoint, entering the new co-ordinates.

Oct 04, 2008 | Garmin eTrex GPS Receiver

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