Question about Texas Instruments TI-84 Plus Calculator

# Name the set of 4 consecutive odd integers starting with -3.

I need help its hard

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-3, -1, 1, 3

Posted on May 28, 2014

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Posted on Jan 02, 2017

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24
=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Posted on Jan 17, 2011

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## Related Questions:

### The numbers on three raffle tickets are consecutive integers whose sum is 7530. find the integers

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

### Consecutive odd integers

-2 and -4.
Hope this helps.
Bob

Dec 09, 2013 | Plumbing

### Two consecutive even integers such that the smaller added to three times the larger gives a sum of 22

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:
x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

### The smallest of 3 consecutive odd integers is added to twice the largest, giving a result 24 less than 5 times the middle. Find the integers

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24
=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Jan 17, 2011 | Texas Instruments TI-84 Plus Calculator

### Find three consecutive odd integers whose sum is 105

X + ( X + 2 ) + ( X + 4 ) = 105
3X + 6 = 105
3X = 105 - 6
3X = 99
X = 99/3
X = 33
So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

### What are the three consecutive integers whose sum is 378?

Let X be the lowest of the 3 integers
The sum of the 3 integers can be represented as X + (X+1) + (X+2).
Set this sum equal to 378 and solve for X.
X + (X+1) + (X+2) = 378
3X + 3 = 378
3X = 375
X = 125
Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

### Find three consecutive odd integers such that twice the product of the first two is 7 more than the product of last two

Hi,

Let's say your 3 numbers are a, b and c. Because they are consecutive and odd, you can write them like this:

a = 2x-1, b = 2x+1, c = 2x+3

Now, your problem looks like this:

2(2x-1)(2x+1) = (2x+1)(2x+3) + 7
2(4x^2-1) = 4x^2+6x+2x+3 + 7
8x^2-2 = 4x^2+8x+10
4x^2-8x-12 = 0
4(x^2-2x-3) = 0
x^2-2x-3 = 0

The solutions for this quadratic equation ( see more about this kind of equations here: http://en.wikipedia.org/wiki/Quadratic_equation ) are x=3 or x=-1. So, you've got two sets of solutions:

[1] a = 5, b = 7, c = 9
[2] a = -3, b = -1, c = 1

Take care,
Alex

Oct 15, 2009 | Google Computers & Internet

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