Question about Texas Instruments TI-84 Plus Calculator

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Posted on Jan 02, 2017

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SOURCE: the smallest of 3 consecutive odd integers is

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24

=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Posted on Jan 17, 2011

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24

=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24

=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Jan 17, 2011 | Texas Instruments TI-84 Plus Calculator

X + ( X + 2 ) + ( X + 4 ) = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

Let X be the lowest of the 3 integers

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

Hi,

Let's say your 3 numbers are a, b and c. Because they are consecutive and odd, you can write them like this:

a = 2x-1, b = 2x+1, c = 2x+3

Now, your problem looks like this:

2(2x-1)(2x+1) = (2x+1)(2x+3) + 7

2(4x^2-1) = 4x^2+6x+2x+3 + 7

8x^2-2 = 4x^2+8x+10

4x^2-8x-12 = 0

4(x^2-2x-3) = 0

x^2-2x-3 = 0

The solutions for this quadratic equation ( see more about this kind of equations here: http://en.wikipedia.org/wiki/Quadratic_equation ) are x=3 or x=-1. So, you've got two sets of solutions:

[1] a = 5, b = 7, c = 9

[2] a = -3, b = -1, c = 1

Take care,

Alex

Let's say your 3 numbers are a, b and c. Because they are consecutive and odd, you can write them like this:

a = 2x-1, b = 2x+1, c = 2x+3

Now, your problem looks like this:

2(2x-1)(2x+1) = (2x+1)(2x+3) + 7

2(4x^2-1) = 4x^2+6x+2x+3 + 7

8x^2-2 = 4x^2+8x+10

4x^2-8x-12 = 0

4(x^2-2x-3) = 0

x^2-2x-3 = 0

The solutions for this quadratic equation ( see more about this kind of equations here: http://en.wikipedia.org/wiki/Quadratic_equation ) are x=3 or x=-1. So, you've got two sets of solutions:

[1] a = 5, b = 7, c = 9

[2] a = -3, b = -1, c = 1

Take care,

Alex

Oct 15, 2009 | Google Computers & Internet

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