Ad

There are an infinite number of points on this line.

Assuming you mean 5x=(1/2)y-3, two of the points are (0, 6) and (-3/5, 0).

Posted on Apr 01, 2014

Ad

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

Ad

Let's break this down into a few parts first.

Slope intercept form is otherwise known as y = mx + b, where m is the slope and b is the y-intercept.

Parallel means that the two lines will never meet. They are parallel to each other. In math terms, their slopes are the same, so the m values must be the same.

Starting with y = -5x + 1, putting into slope intercept form, y = mx + b, m = -5 and b=1.

Since it is parallel, it must have the same slope and the m values are the same.

So, y = -5x + b, but we don't know what the value of b is. To determine this, we know the point (-4,-6) is on the line that we are trying to find, so we can substitute it into the equation and calculate b to make it work.

Every time we see an x we put in -4 and every time we see a y, we put in -6.

-6 = -5(-4) + b

-6 = 20 + b

subtract 20 from both sides

-6 - 20 = 20 + b - 20

-26 = b

Now substitute this into the equation.

y = -5x + -26

Putting it into correct form, we get y = -5x - 26.

Let's check it to see if it is correct.

It has a slope of -5, so it is parallel to y=-5x + 1

Is the point (-4,-6) on the line? Let's substitute it in to see if it is on the line.

Again, everywhere we see an x, we put in -4 and everywhere we see a y we put in -6.

-6 = -5(-4) - 26

-6 = 20 - 26

-6 = -6

Sorry for the very long explanation, but after you do a few of them, you will be able to knock them off in minutes.

Good luck,

Paul

Slope intercept form is otherwise known as y = mx + b, where m is the slope and b is the y-intercept.

Parallel means that the two lines will never meet. They are parallel to each other. In math terms, their slopes are the same, so the m values must be the same.

Starting with y = -5x + 1, putting into slope intercept form, y = mx + b, m = -5 and b=1.

Since it is parallel, it must have the same slope and the m values are the same.

So, y = -5x + b, but we don't know what the value of b is. To determine this, we know the point (-4,-6) is on the line that we are trying to find, so we can substitute it into the equation and calculate b to make it work.

Every time we see an x we put in -4 and every time we see a y, we put in -6.

-6 = -5(-4) + b

-6 = 20 + b

subtract 20 from both sides

-6 - 20 = 20 + b - 20

-26 = b

Now substitute this into the equation.

y = -5x + -26

Putting it into correct form, we get y = -5x - 26.

Let's check it to see if it is correct.

It has a slope of -5, so it is parallel to y=-5x + 1

Is the point (-4,-6) on the line? Let's substitute it in to see if it is on the line.

Again, everywhere we see an x, we put in -4 and everywhere we see a y we put in -6.

-6 = -5(-4) - 26

-6 = 20 - 26

-6 = -6

Sorry for the very long explanation, but after you do a few of them, you will be able to knock them off in minutes.

Good luck,

Paul

Apr 03, 2016 | Office Equipment & Supplies

Their slopes are negative reciprocals, that is, they multiply to -1, thus the two lines are perpendicular.

Jun 30, 2014 | Office Equipment & Supplies

To evaluate the expression you need the value of x.

To solve you do as follows

ln(5x)=12/4=3

Take the exponential of both sides of ln(5x)=3

e^(ln(5x))=5x=e^(3)

This gives**x=(1/5) e^(3)**

To solve you do as follows

ln(5x)=12/4=3

Take the exponential of both sides of ln(5x)=3

e^(ln(5x))=5x=e^(3)

This gives

Apr 23, 2014 | Texas Instruments TI 30XIIS Scientific...

If you plot this, it is approximately a straight line (with a y error or +/-.2). An ideal straight line would have y points of 7,8,9,10,11,12 for the given x's. The formula for this line is y=.5x + 6 . The gradient (slope) is .5 and the intercept is 6.

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

Mar 01, 2014 | Office Equipment & Supplies

Press the Menu key. Use arrows to highlight the Graph utility. The function input screen opens so that you can type in the function

Y1=-X^2+5X-3You can play with the line style, or other features.

Press ENTER EXE to validate. Then Press the Function key to activate the Draw tab.

Y1=-X^2+5X-3You can play with the line style, or other features.

Press ENTER EXE to validate. Then Press the Function key to activate the Draw tab.

Oct 15, 2012 | Casio FX-9750GPlus Calculator

Write the equality in the form y=(5X+3)/(4X-5). Insert parentheses to ensure a correct result.

- Multiply both sides of the equality by (4X-5). This gives (4X-5)y=(5X+3).
- Open the parentheses as 4Xy-5y=5X+3
- Subtract 5X from both sides 4Xy-5y-5X=5X-5X+3
- Add 5y to both sides 4Xy-5X-5y+5y=5y+3 or 4Xy-5X=5y+3
- Factor the X on the left side X(4y-5)=5y+3
- If 4y-5 does not vanish, you can isolate X by dividing both members of the equality by (4y-5).
- You get X=(5y+3)/(4y-5)=f(y)

Jun 24, 2012 | Mathsoft StudyWorks! Mathematics Deluxe...

If I'm understanding you correctly, you want to graph something like

5x+3=9

If this is correct, graph 5x+3 in the y1 line and 9 in the y2 line. To find the solution, you will press 2nd, then trace the intersection and hit enter 3 times. This will get the solution you need for the equation.

If this is not what you are wanting to do, you need to be try again and elaborate more.

5x+3=9

If this is correct, graph 5x+3 in the y1 line and 9 in the y2 line. To find the solution, you will press 2nd, then trace the intersection and hit enter 3 times. This will get the solution you need for the equation.

If this is not what you are wanting to do, you need to be try again and elaborate more.

Jun 28, 2011 | Texas Instruments TI-84 Plus Calculator

Standard calculators can not really understand abstract notation. So 5x3/5x to the calculator is not being read as 5x (times) 3 (divided by) 5x, it is actually trying to understand x as a number. and if x isn't assigned as a number you'll get an error. SO no x's or y's or any letters. Anything with letters you have to do on your own. So 5x*3 / 5x cross out the two 5x's and you're left with 3/1 so your answer is 3.

Hope that helps! -Joe

Hope that helps! -Joe

Jun 07, 2011 | Sharp EL-531VB Calculator

i think there are programs but with something as simple as that you should be able to work it out manually....

3x+25-5x=5x-5x

-2x+25-25=0-25

-2x=-25

x=25/2 or 12.5

3x+25-5x=5x-5x

-2x+25-25=0-25

-2x=-25

x=25/2 or 12.5

Jul 05, 2009 | Texas Instruments TI-84 Plus Calculator

the exact equation is

15x^2 - 21x - 18

=3(5x^2 - 7x - 6)

=3{5x^2 -(10-3)x -6 }

=3{5x^2 - 10x + 3x -6}

=3{5x(x - 2) + 3(x-2)}

=3(x-2)(5x+3) these are the factors

Thanks

Zulfikar Ali

ali_zulfikar@yahoo.com

9899780221

15x^2 - 21x - 18

=3(5x^2 - 7x - 6)

=3{5x^2 -(10-3)x -6 }

=3{5x^2 - 10x + 3x -6}

=3{5x(x - 2) + 3(x-2)}

=3(x-2)(5x+3) these are the factors

Thanks

Zulfikar Ali

ali_zulfikar@yahoo.com

9899780221

Oct 16, 2008 | SoftMath Algebrator - Algebra Homework...

24 people viewed this question

Usually answered in minutes!

×