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Numbers dim Numbers are to dim

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1 Answer

Dim display


If you have the 12C Platinum, turn the calculator on. Press and hold the f key, then press the + key to increase the contrast.

Mar 09, 2013 | Office Equipment & Supplies

2 Answers

Numbers not complete on display


If the numbers are faded, dimmed or not even showing, the display control will have to be replaced. Thats the only repair for that issue.

Apr 25, 2012 | LG Dryers

1 Answer

Numbers not completed on display?


If the numbers are faded, dimmed or not even showing, the display control will have to be replaced. Thats the only repair for that issue.

Apr 25, 2012 | LG Dryers

1 Answer

LED readout is getting very dim. I reset the computer but it's still dim, and only about half the numbers are visable.


Hi

The issue is with the display panel that is bad or the connection to the control is loose. TO check what is causing this issue you will have to take it apart and check the board, if bad then it should be replaced. Hope this helps...

Daniel

Jan 07, 2011 | Microwave Ovens

1 Answer

Need help in Special Formatting Number


Here is one solution. You might consider adding more robust error handling.
if the decimal numbers passed to the div function are multiples i will be a non-zero number of that multiple otherwise i will be zero.

Dim i As Integer
i = div(12, 0)
If i = 0 Then
'not multiple
' do this
Else
' is multiple
' do something else
End If


Function div(ByVal numerator As Object, ByVal denominator As Object) As Integer
dim n , d decimal
Dim result As Decimal
Dim remainder As Decimal

If IsNumber(numerator) Is True _
And IsNumber(denominator) Is True Then
If numerator <> 0 Then
n = numerator
d = denominator
Else
GoTo error1
End If
Else
GoTo error1
End If
result = Decimal.divide(n, d)
remainder = Decimal.remainder(n, d)
If remainder = 0 Then
div = result
Else
div = 0
End If

Exit Function
error1:
msgbox("Numbers must be non-zero numerics", , "Multiple check error")
div = 0
End Function

End Function

Aug 06, 2008 | Computers & Internet

2 Answers

Help me


this the code for your problem. by the way this for vb6.0

Sub CountCharacters(Text As String)
Dim iVowel As Integer
Dim iCons As Integer
Dim iNum As Integer
Dim iSpace As Integer
Dim iOther As Integer

Dim cnt As Integer
Dim sChar As String

For cnt = 1 To Len(Text)
sChar = LCase(Mid(Text, cnt, 1))

Select Case sChar
Case "a", "e", "i", "o", "u" ' And sometimes "y"?
' Vowel
iVowel = iVowel + 1
Case "a" To "z"
' Includes the first case, but VB matches the first case and stops
iCons = iCons + 1
Case "0" To "9"
' Numbers
iNum = iNum + 1
Case " ", vbTab, vbLf
' Space characters
' Not including vbCr as this will likely be dealing with Windows text
' and I only want to match one character for a newline
iSpace = iSpace + 1
Case Else
If sChar <> vbCr Then iOther = iOther + 1
End Select
Next cnt

Debug.Print "Text: " & Text
Debug.Print "Vowels: " & CStr(iVowel)
Debug.Print "Consonants: " & CStr(iCons)
Debug.Print "Numbers: " & CStr(iNum)
Debug.Print "Space characters: " & CStr(iSpace)
Debug.Print "Other: " & CStr(iOther)
End Sub

Feb 21, 2008 | Computers & Internet

1 Answer

Help me


Sub CountCharacters(Text As String)
Dim iVowel As Integer
Dim iCons As Integer
Dim iNum As Integer
Dim iSpace As Integer
Dim iOther As Integer

Dim cnt As Integer
Dim sChar As String

For cnt = 1 To Len(Text)
sChar = LCase(Mid(Text, cnt, 1))

Select Case sChar
Case "a", "e", "i", "o", "u" ' And sometimes "y"?
' Vowel
iVowel = iVowel + 1
Case "a" To "z"
' Includes the first case, but VB matches the first case and stops
iCons = iCons + 1
Case "0" To "9"
' Numbers
iNum = iNum + 1
Case " ", vbTab, vbLf
' Space characters
' Not including vbCr as this will likely be dealing with Windows text
' and I only want to match one character for a newline
iSpace = iSpace + 1
Case Else
If sChar <> vbCr Then iOther = iOther + 1
End Select
Next cnt

Debug.Print "Text: " & Text
Debug.Print "Vowels: " & CStr(iVowel)
Debug.Print "Consonants: " & CStr(iCons)
Debug.Print "Numbers: " & CStr(iNum)
Debug.Print "Space characters: " & CStr(iSpace)
Debug.Print "Other: " & CStr(iOther)
End Sub

Feb 21, 2008 | Computers & Internet

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