Question about Sport & Outdoor - Others

Good question, and I cannot answer it... but my first thought is, it is not a perfect pyramid. But, if it were, and I wanted to figure it out, I would do a Google search for volume of a pyramid. I'm sure there is a formula out there. I got V=(l*w*h)/3. I'm too lazy to get out my calculator and there is no pencil and paper handy. Good question though.

Posted on Mar 27, 2014

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Posted on Jan 02, 2017

The volume is one third the product of the area of the base times the height or (1/3)B*h

Feb 22, 2016 | Pyramid Computers & Internet

In two similar triangles, the ratio of their areas is the square of the ratio of their sides. Let's assume LMN and FGH are similar triangles. The ratio of the areas of LMN to FGH is 18 to 24, or 3 to 4 or 0.75. We would then take the square root of 0.75 to get the ratio of the sides. I get 0.866. The reason it is the square is the area of a triangle is base times height divided by 2, and the base and height and sides of similar triangles are proportional.

Good luck.

Paul

Similar Triangles ratio of areas

Good luck.

Paul

Similar Triangles ratio of areas

Mar 12, 2015 | Office Equipment & Supplies

A pyramid has 5 sides including the base. If the base is a rectangle L long and W wide, its area is L*W.

The other sides are triangles. If the height of the pyramid is H, the triangles that are L wide at the base will have a height of the square root of half of W squared plus H squared, or SQRT((.5*W)^2+H^2) and the two that are W wide at the base will have a height of SQRT((.5*L)^2+H^2). The area of a triangle is .5*height*base, so the total surface two triangles with the same height and base is 2*.5*height*base = height*base.

So, the total surface area of a pyramid L long by W wide by H tall would be:

L*W (the area of the base)

+ L*SQRT((.5*W)^2+H^2) (the area of the 2 triangles with base L)

+ W*SQRT((.5*L)^2+H^2) (the area of the 2 triangles with base W)

Hope this is helpful!

The other sides are triangles. If the height of the pyramid is H, the triangles that are L wide at the base will have a height of the square root of half of W squared plus H squared, or SQRT((.5*W)^2+H^2) and the two that are W wide at the base will have a height of SQRT((.5*L)^2+H^2). The area of a triangle is .5*height*base, so the total surface two triangles with the same height and base is 2*.5*height*base = height*base.

So, the total surface area of a pyramid L long by W wide by H tall would be:

L*W (the area of the base)

+ L*SQRT((.5*W)^2+H^2) (the area of the 2 triangles with base L)

+ W*SQRT((.5*L)^2+H^2) (the area of the 2 triangles with base W)

Hope this is helpful!

May 23, 2014 | Encore Math Advantage Algebra II and...

Here is to get you started. To increase the size of the image do a CTRL Plus (+) in your browser.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of** (1/2)*SQRT(203) **or about 7.1239 cm

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),**the measure of the second leg is (1/3) the altitude** **of the equilateral triangle** that forms the base. You should find (1/3) m MH= (1/3)* **(11/2)*SQRT(3)**

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

Mar 29, 2014 | Office Equipment & Supplies

Look at the problem set up on the screen capture below.

If the pyramid is made of homogenous material you need not worry about the mass (what you call weight) since the ratio of the masses is equal to the ratio of the volumes.

Setting the ratio of volume to be 1/2, and using the ratio of the base areas of the pyramids to be (x/h)^2, you end up with

**(1/2)=(x/h)^3**

Solving for x, you get**x=h/(cubic root of 2)**

If the pyramid is made of homogenous material you need not worry about the mass (what you call weight) since the ratio of the masses is equal to the ratio of the volumes.

Setting the ratio of volume to be 1/2, and using the ratio of the base areas of the pyramids to be (x/h)^2, you end up with

Solving for x, you get

Mar 02, 2014 | Office Equipment & Supplies

I assume you mean a square base.

2.0833 litres.

If this is homework, be sure to show your work.

2.0833 litres.

If this is homework, be sure to show your work.

Feb 27, 2014 | Office Equipment & Supplies

2.0833 litres.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Feb 27, 2014 | Office Equipment & Supplies

You need 5 isosceles triangles with a base of 30 mm. To get the height of the triangles (perpendicular to the 30 mm bases) you need to calculate the apothem of the pentagon (assumed to be regular).

If you cut the pyramid by a plane passing through its apex, the center of the base-pentagon,and the midpoint of one side, the plane figure created by the three points (apex, center, and midpoint) is a right triangle. The legs are the apothem, and the altitude of the pyramid. The hypotenuse is the slant height of the pyramid, and is thus the height of the triangles in the development. pyramid (60 mm) form.

Use the Pythagorean Theorem to find that slant height.

**s^2=a^2+h^2**.

If you cut the pyramid by a plane passing through its apex, the center of the base-pentagon,and the midpoint of one side, the plane figure created by the three points (apex, center, and midpoint) is a right triangle. The legs are the apothem, and the altitude of the pyramid. The hypotenuse is the slant height of the pyramid, and is thus the height of the triangles in the development. pyramid (60 mm) form.

Use the Pythagorean Theorem to find that slant height.

Nov 11, 2013 | Computers & Internet

3 3rd pie * the radius cubed for a sphere

3 3rd pie * the radius squared x the height squared for a cone

3 3rd pie * the perimeter squared x the peak squared for a pyramid

3 3rd pie * the radius squared x the height squared for a cone

3 3rd pie * the perimeter squared x the peak squared for a pyramid

Oct 04, 2012 | Dell Inspiron Zino HD Formula Red Desktop...

The first Egyptian pyramid was 204 feet or 62 meters high, built at the direction on Pharoah Djoser in around 2630 B.C. The tallest was the Great Pyramid at Giza, standing at an impressive 481 feet or 147 meters. The smallest was the Pyramid of Pepi II, which stood at a paltry 172 feet or 52 meters. Just based on Egyptian pyramids, the average height is about 316.5 feet or 96.375 meters. Considering the technology of the day, the pyramid builders were quite impressive to say the least. Hope this helped and best wishes.

Sep 24, 2009 | Sport & Outdoor - Others

Sep 20, 2017 | Sport & Outdoor - Others

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