Find the coefficient

Do the operation 3*2=6. Put the 6 in front of x. **6 is the coefficient**

The result, in simplified form, is 6x

Posted on Mar 28, 2014

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Posted on Jan 02, 2017

1.2(1.5x) + 1.2(-2.2y) + -4.5(2x) + -4.5(1.5y)

Figure out the products (multiplication), then simplify by adding or subtracting the coefficients of the same variable ( the X and the Y).

coefficients Google Search

Figure out the products (multiplication), then simplify by adding or subtracting the coefficients of the same variable ( the X and the Y).

coefficients Google Search

May 30, 2016 | Office Equipment & Supplies

Step 1 - replace each x with a y and replace each y with an x

x=6y+24

Step 2 - Solve for y to get the equation in the slope intercept form y=mx+b

Step 3 - get the 24 to the other side by subtracting 24 for both sides

x-24=6y + 24 - 24

Simplify

x - 24 = 6y

Divide by the coefficient in front of the y to get y by itself.

x/6 - 24/6 = y

x/6 -4 = y

Write in the normal format by switching the sides.

y = x/6 - 4

Good luck.

Paul

x=6y+24

Step 2 - Solve for y to get the equation in the slope intercept form y=mx+b

Step 3 - get the 24 to the other side by subtracting 24 for both sides

x-24=6y + 24 - 24

Simplify

x - 24 = 6y

Divide by the coefficient in front of the y to get y by itself.

x/6 - 24/6 = y

x/6 -4 = y

Write in the normal format by switching the sides.

y = x/6 - 4

Good luck.

Paul

May 07, 2016 | Office Equipment & Supplies

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | Computers & Internet

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | SoftMath Algebrator - Algebra Homework...

There is no DiagnosticsOn command in the TI 89 Titanium. The command exists on the TI83/84PLUS where it displays the r and r^2 coefficients. On the TI89 , the correlation coefficient and the determination coefficient (r, r^2) are displayed by default among the statistics if THE REGRESSION MODEL includes them. If they are not defined by the regression model they will not be displayed. In short, you do not have to turn diagnostics ON.

Apr 17, 2012 | Texas Instruments TI-89 Calculator

Your question (?) is not clear so I will not try to guess what you really mean.

Be it as it may, the Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to** a+ib**, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Be it as it may, the Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Mar 16, 2012 | Casio Office Equipment & Supplies

Using elementary algebria in the **binomial theorem, **I expanded the power **(***x* + *y*)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of *x* and *y* in each term is **n**. This is known as binomial coefficients and are none other than combinatorial numbers.

**Combinatorial interpretation:**

Using** binomial coefficient (n over k)** allowed me to choose** ***k* elements from an **n**-element set. This you will see in my calculations on my Ti 89. This also allowed me to use **(x+y)^n** to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**This also follows Newton's generalized binomial theorem:**

**Now to solve using the Ti 89.**

Using

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:**

**The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n. **

Jan 04, 2011 | Texas Instruments TI-89 Calculator

Hi,

I don't know if you still need help with this problem but in case you do follow this link:

http://www.mathstore.net/graphing-calculators/TI-calculators/how-to-calculate-the-correlation-coefficient.php

Good luck!

I don't know if you still need help with this problem but in case you do follow this link:

http://www.mathstore.net/graphing-calculators/TI-calculators/how-to-calculate-the-correlation-coefficient.php

Good luck!

May 07, 2009 | Texas Instruments TI-30XA Calculator

Mode>choose "5"

choose equation format "4"

input the coefficient for a which is "1" and hit "="

input the coefficient for b which is "4" and hit "="

input the coefficient for c which is "3" and hit "="

input the coefficient for d which is "12" and hit "="

Hit "=" for X1

Hit "=" again for X2

Hit "=" again for X3

choose equation format "4"

input the coefficient for a which is "1" and hit "="

input the coefficient for b which is "4" and hit "="

input the coefficient for c which is "3" and hit "="

input the coefficient for d which is "12" and hit "="

Hit "=" for X1

Hit "=" again for X2

Hit "=" again for X3

Nov 18, 2007 | Casio Office Equipment & Supplies

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