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Either 16+7/x or x+16+8/x depending on whether "3/3x" is interpreted as "3/(3x)" or "(3/3)x", both of which are valid interpretations of the precedence of operators.
5x -2(x-2) = 6 -2(-3x-3) 5x -2x +4 = 6 +6x +6 (use the distributive property) 3x + 4 = 6x + 12 (collect terms) 4 = 3x + 12 (subtract 3x from both sides to get all x on one side) -8 = 3x (subtract 12 from both sides to get only x on one side) -8/3 = x (divide both sides by 3 to get x by itself)
Here you are :
2X2-3x+5=0
=> 4-3x+5=0; (2X2=4)
=> -3x+9=0; (4+5=9)
=> 9 = 3x; (-3x moved to the right-hand side and it became 3x)
=> 9/3=x; (3 moved to the right hand side, so it becomes 1/3, i.e 1/3X9= 9/3)
i.e. x=9/3
=> x=3
Hence x equals to 3.
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