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# Whats the sum of three consecutive integers is -621. find all three integers

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Posted on Feb 17, 2014

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Posted on Jan 02, 2017

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:
x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Posted on Sep 15, 2011

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## Related Questions:

### The Sum of 2 integers from 1 to 9 that are four consecutive numbers. Show that either one or three of the numbers on the counters were even

I need some help here. If we take the sum of 2 integers from 1 to 9, and they can be the same number, the maximum number is 18. I don't know how you are supposed to get four consecutive digits, unless you pad the number with zeros. Am I missing something?

Good luck,

Paul

May 29, 2016 | Office Equipment & Supplies

### The numbers on three raffle tickets are consecutive integers whose sum is 7530. find the integers

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

### Find the smallest two consecutive even integers such that three times the smaller is at least 19 more than the sum of the two integers

Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

### Find three consecutive odd integers whose sum is 105

X + ( X + 2 ) + ( X + 4 ) = 105
3X + 6 = 105
3X = 105 - 6
3X = 99
X = 99/3
X = 33
So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

### What are the three consecutive integers whose sum is 378?

Let X be the lowest of the 3 integers
The sum of the 3 integers can be represented as X + (X+1) + (X+2).
Set this sum equal to 378 and solve for X.
X + (X+1) + (X+2) = 378
3X + 3 = 378
3X = 375
X = 125
Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

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