Question about Texas Instruments TI-30XA Calculator

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How do I convert square roots (for example square root of 147) into a number like 7 over square root 3. is it possible to do that? Or can the TI-130Xa only convert perfect squares (like square root o

How to convert square roots?

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Unfortunately this calculator does not display results in radical form. If you enter SQRT(147) you get 12.12435565...
What you are asking for is called rationalizing an irrational expression. Usually one tries to get rid of radicals that appear in the denominators. Here is an example.
Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?
Recall the identity (a-b)*(a+b)= a^2-b^2. It is true for any a and b

Rationalizing a denominator (usual case)
Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))
[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=c^2-d
You see that there is no radical.
Now take 1/(c+SQRT(d)). To get rid of the radical from the denominator multiply it by (c-SQRT(d)). But to leave the value of your expression 1/(c+SQRT(d)) unchanged, you must multiply both numerator and denominator by (c-SQRT(d)).
The numerator becomes 1*(c-SQRT(d))=c-SQRT(d), and the denominator (c^2-d).
Finally, the rationalized form of the expression 1/(c+SQRT(d)) is
[c-SQRT(d)]/[c^2-d].

Rationalizing a numerator
Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same
Example:(c+SQRT(d)), the denominator here is 1
(c+SQRT(d))=(c+SQRT(d))*[c-SQRT(d)]/[c-SQRT(d)]. This gives
[c^2-d]/[c-SQRT(d)]
You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.
Your case is a lot simpler
SQRT(147)=7*SQRT(3)
Multiply it by SQRT(3)/SQRT(3) which is 1. This gives
SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

SQRT(147)= 21/SQRT(3)

Posted on Feb 09, 2014

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SOURCE: Trig Problem

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SOURCE: square roots

One way is you get square root by raising to the (1/2) power. For example square root of 16 is
16^(1/2).
You can use this method to get the other "roots" as well e.g. 1/3, 1/4, etc.

Posted on Apr 18, 2009

  • 7993 Answers

SOURCE: TI-15 square root Function

Hello,
You should enter it as follows [SQRT]36 ) [ENTER/=].
If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.
Hope it helps.

Posted on Sep 07, 2009

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SOURCE: how do you tak the square root of 64 or the 4 root of any other #

Hi shiny_diamon
Here is a picture of the powers and root functions of your calculator.
1.To calculate the cubic root of a number you use the key combination shown on line 5
Ex: Cubic root of 27
27 [2nd] [3 root x] [EXE]; Should get 3
2. You can use the general root key on line 7 [2nd][x Root y]
Ex: Cubic root of 125
125 [2nd][ x Root y] 3 [EXE] Should get 5
(-125) [2nd][x Root y] 3 [EXE]; Should get -5

3. You can also yse the general power key on line 6: [Y to x], but the degree of the root is entered as a fraction 1/3
Ex: cubic root of -125.
(-125) [Y to x]( 1/3) [EXE]; You should get -5

4. The [Y to x[ key is the one you use to obtain all other roots fourth, fift, tenth, n-th.
Ex: Fourth root of 256
256 [Y to x] (1/4) [EXE]: You should get 4

5. To extract the squqre root of a number you can use the key on the 3rd line [root x] or the general power key on line 6 with exponent 1/2
Exemple square root of 256
256 [Root x] [EXE] should give you 16
256 [Y to x] (1/2) [EXE] should give you 16 also

Hope that helps.
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Posted on Nov 08, 2009

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SOURCE: How do you use the imaginary number with the TI-84 calculator?

If you want the answer in rectangular form, set MODE a+bi and tap ENTER and QUIT. Tap square root sign, tap (-)4 and close the parenthesis and tap ENTER. The answer is shown as 2i.
If you want the answer in polar form, set MODE to re^xi and and DEGREE. Tap ENTER and QUIT. Tap the square root sign, tap (-)4, close the parenthesis, and tap ENTER. The answer shown is 2e^90i. (2 at ninety degrees). If you selected RADIAN mode, the answer would be 2e^1.57i (2 at 1.57 radians; or 2 at pi/2 radians)

Posted on Dec 20, 2009

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