Question about Texas Instruments TI-84 Plus Calculator
Posted by Anonymous on
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Posted on Jan 02, 2017
SOURCE: ti-89 titanium SIN!!!!!
The answer that you have received in actuality is correct. However, it is in exact form when the answer that you were looking for was an approximation (decimal form) answer. To achieve this all you have to do is hit the alpha button (the yellow button with a diamond in the center) and then enter which will give you your desired answer :-)
Posted on Jan 15, 2008
SOURCE: error :invalid DIM
This is my first post on this site, but I've had friends at school ask me about this. Apparently I'm like a calculator genius or something...
One solution I know of is clearing the RAM. Sounds strange, doesn't it? But it fixed three different calcs.
Be sure to back up or archive important data before doing this.
Posted on Oct 21, 2008
SOURCE: ERR: No Sign change...
-0.171x+43.43 and -0.146x+39.83
i tried that and i got the same thing, but i noticed that if you change your window so it fits more of the graph on the right, were you can actually see the lines intersect, then you can get the intersection.
oh, and by the way, the intersection is (144, 18.806)
Posted on Mar 01, 2009
SOURCE: Graphing radical functions
I have a TI-89 Titanium and I have experienced the same problem. HERE IS HOW TO FIX IT:
Goto " MODE " and scroll down the options until you get to
" COMPLEX FORMAT " change that option to " RECTANGULAR " and press ENTER until you exit out of the " MODE " screen. (very important that you press ' enter ' until you exit because if you don't, it will not save your changes. )
Posted on Mar 15, 2009
SOURCE: TI-15 square root Function
You should enter it as follows [SQRT]36 ) [ENTER/=].
If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.
Hope it helps.
Posted on Sep 07, 2009
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