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Posted on Jun 05, 2009
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When i try to log on my page pops up and freeze and i can't x it out and i end up stacking three three or more pages before i can log on. also when i'm on a web site and it has numbers at the bottom to go to next page it always shut down talking about it shut down to protect my computer

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  • Expert 202 Answers
  • Posted on Jun 07, 2009
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Joined: May 05, 2008
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It seems you recently downloaded an incompatible files form the computer. click on START-PROGRAMS-ACCESSORIES-SYSTEM TOOLS-SYSTEM RESTORE, here take the system back to a better date that it works perfectly, don't worry you won't loose any recent files saved but your system will be back to normal. good luck

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1answer

[email protected]

1. Open the old gmail account.
2. On the top, far left corner, click on the icon that looks like a stack of three horizontal lines.
3. On the next page, click on the down arrow at the top of the page.
4. On the next page, click on "Manage accounts".
5. The next page, takes you to "Accounts". Click on "Add another account".
5. From here you can add your preferred gmail account. This one will now be your default gmail account.

If you want to delete a gmail account, follow steps 1-4. Then click on "Edit" on the top right corner. Then you can delete unwanted gmail accounts.

Hope this helps you.
John
0helpful
1answer

I can not log out the page seems frozen

if this is your pc HIT on your key board Ctrl + Alt + Del at the same time holding all down in the end. A screen will pop up will show you what is not responding click on it to end process. If this does not work do a reboot of your PC just kill the power then turn it back on.
0helpful
1answer

The calculator we made in visual basic can't function all four operations consecutively

You really have to give a lot more information in order to enable me to help you. However, by wild guessing, I am trying to nudge you into the right direction.

I assume you are trying to program a simple + - * / = infix calculator with or without a graphical user interface.

To get operators and operator precedence right, it is a good idea to create to a data structure of type stack. Stacks are abstract containers with operations push(), pop() and isempty().
  • Push() puts a new object to the stack,
  • Pop() removes one object from the stack and returns it, unless the stack is empty, in which case an error is generated,
  • isempty() is a boolean function that checks if the stack is empty.
A nice-to-have convenience extra is an operation top(). It returns the topmost stack element without removing it (you can emulate by a pop(); push() sequence at some performance costs, so its not a strict requirement for a stack).
only
Stacks are LIFO memories, Last In, First Out, so what you push most recently will get returned by pop first. Just like a stack of cards where you can put a new card only to the top and take away from the top, too.

Processing of the input is done according to the "Shunting-Yard Algorithm", invented by Edsger Wybe Dijkstra. The link directs you to the Wikipedia page of the algorithm, which does an extensive discussion, much nicer than what I could do here on FixYa.
0helpful
2answers

SOMETIMES FEEDS UP TWO OR MORE SHEETS WHEN IT SHOULD ONLY BE ONE

many printers have a rubber or cork pad under the feed wheels to hold back all the sheets, except the top one. This one doesn't have that, so we'll try a couple other things.

Pull the tray out and remove all the paper. If you're reusing old paper, that might be your problem. Assuming you have fresh, clean paper, take the whole stack, pinching it at one end, and bow the stack up in the middle. Now pinch the other end of the stack, relax the grip on the end you pinched before, and bend the stack the other way. Repeat.

With every bend, the stack gets more slanted. Now hold one end of the stack and fan the other end to get air between all the sheets. Fan the other end the same way. The tiny layer of air you're creating between pages goes a long way in lubricating them, so they feed separately.

Straighten the stack and put it back in the cassette. The blue "fences" at the sides should be touching both sides of the stack to provide a little friction and keep the feed straight. The back fence should hold the stack against the opposite end of the tray. (Your tray is slanted at the feed end. On models where that wall is vertical, you should have a 1 to 2 mm gap so the paper doesn't bind when it tries to lift.)

Reinsert the tray and try it out.
0helpful
1answer

Pay pal log in page freezing

Try switching whatever browser you are using right now to either FireFox or Google Chrome, if it still doesn't work contact me back.
0helpful
1answer

How to convert infix to postfix using stacks in java programming?

u can try the follwing coding
import java.io.*;
import java.util.*;
//begin coding for the stack interface
interface Stack<E>
{
public boolean isEmpty();//tests is current stack is empty. Returns true if so, and false if not.
public E top() throws StackException;//retrieves value at the top of the stack. Stack cannot be empty.
public void push(E value) throws StackException;//pushes a value on the top of the stack.
public void pop() throws StackException;//removes a value from the top of the stack. Stack cannot be empty.
}//terminates coding of Stack interface

//begin coding for the objArrayStack class
class objArrayStack<E> implements Stack<E>
{
//constructor
public objArrayStack()
{
topValue=-1;
}//terminates constructor
public void push(E value)throws StackException
{
if(topValue<ArraySize-1)//currrent stack is not full
{
++topValue;
Info[topValue]=value;
}//terminates if
else //current stack is full
throw new StackException("Error: Overflow");
}//terminates push method
public void pop() throws StackException
{
if(!isEmpty())//current stack is not empty
--topValue;
else //stack is empty
throw new StackException("Error: Underflow");
}//terminates pop method
public boolean isEmpty()
{
return topValue==-1;
}//terminates isEmpty method
public E top() throws StackException
{
if(!isEmpty())//stack is not empty
return (E)Info[topValue];
else //stack is empty
throw new StackException("Error: Underflow");
}//terminates top method
//declare instance variables
final int ArraySize=10;
private Object Info[]=new Object[ArraySize];
private int topValue;

//begins coding for the StackException class
class StackException extends RuntimeException
{
//constructor
public StackException(String str)
{
super(str);
}//terminates text of constructor
}//terminates text of StackException class

//method to convert from infix to postfix notation
public static String InToPost(String infixString)
{
//operator stack initialized
objArrayStack<Character> operatorStack = new objArrayStack<Character>();
//postfix string initialized as empty
String postfixString = " ";
//scan infix string and take appropriate action
for(int index = 0; index < infixString.length(); ++index)
{
char chValue = infixString.charAt(index);
if(chValue == '(')
operatorStack.push('(');
else if(chValue == ')')
{
Character oper = operatorStack.top();
while(!(oper.equals('(')) && !(operatorStack.isEmpty()))
{
postfixString += oper.charValue();
operatorStack.pop();
oper = operatorStack.top();
}//end while loop
operatorStack.pop();
}//end else if
else if(chValue == '+' || chValue == '-')
{
if(operatorStack.isEmpty()) //operatorStack is empty
operatorStack.push(chValue);
else //current operatorStack is not empty
{
Character oper = operatorStack.top();
while(!(operatorStack.isEmpty() || oper.equals(new Character('(')) || oper.equals(new Character(')'))))
{
operatorStack.pop();
postfixString += oper.charValue();
}//ends while loop
operatorStack.push(chValue);
}//end else
}//end else if
else if(chValue == '*' || chValue == '/')
{
if(operatorStack.isEmpty())
operatorStack.push(chValue);
else
{
Character oper = operatorStack.top();
while(!oper.equals(new Character('+')) && !oper.equals(new Character('-')) && !operatorStack.isEmpty())
{
operatorStack.pop();
postfixString += oper.charValue();
}//end while loop
operatorStack.push(chValue);
}//end else
}//end else if
else
postfixString += chValue;
}//end for loop
while(!operatorStack.isEmpty())
{
Character oper = operatorStack.top();
if(!oper.equals(new Character('(')))
{
operatorStack.pop();
postfixString += oper.charValue();
}//end if
}//end while
return postfixString ;
}//terminates text of InToPost method

public static void main(String[]args)
{
objArrayStack mystack = new objArrayStack();
System.out.println("Enter a string");
Scanner scan = new Scanner(System.in);
scan.nextLine();
String str = scan.nextLine();
InToPost(str);
}//terminates text of main method
}//terminates text of objArrayStack class
2helpful
1answer

Won't allow me to log into facebook, login page keeps refreshing

if your ie updated to ie8 then you have to run in compatibility mode. Looks like a broken page next to the go arrow at end of address bar
0helpful
1answer

Every time i try to go to you tube but instead of the you tube page popping up an error page pops up that says 400 bad request please help me!!!!!!!!

Delete cookies by going to Internet options and try to re-log in the browser. Also try another browser if deleting cookies doesn't work. Some virus prevent you from logging into particular sites. Install a good anti virus software and scan for virus. I use kaspersky anti virus and haven't had any trouble in a long time.


Peace,
B
0helpful
1answer

Yahoo email is freezing up when I try to log in and my page looks different if I get in

delete your temporary files and try it again. You can find this under Tools, Internet Options.
Oct 18, 2008 • Yahoo Mail
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