Question about Intex 15' X 42" Easy Set Pool Complete Pool Set

1 Answer

I purchased a 15'x42'' easy set pool with no pump

I have a pump model 603 that pumps 530gal/hr, can i use this pump with this 15' pool?

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  • stephanie May 29, 2009

    the pool is 42'' deep, i believe the water turns over fast enough.

  • stephanie May 29, 2009

    it is a self priming pump. i was just wanting to know if this size pump would filter the pool correctly since most 15' pools use a 800 to a 1000 gal/hr pump. mine is only 530 gal/hr. the pool did not come with a pump. i already had this pump from a previous pool.

  • Samuel Charles Spriggs May 11, 2010



    You can certainly use it -- the question would be: "does it turn the water over fast enough?".



    How deep is the pool?

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I would agree on the turnover. Don't know if this is a self-priming pump or not. If not, it has to be installed below the top of the pool -- but I assume that's what you're doing, anyway.

Posted on May 29, 2009

  • Samuel Charles Spriggs May 29, 2009

    The volume of water in the pool is: pi x r squared x h =



    (3.14 x 7.5 squared x 42"/12") x 7.48 gals / cu ft = 4600 gals



    Turnover Time = 4600 gals / 530 gph = 8 hours



    Assuming a 15% head & friction loss, the turnover time would be 10+ hours. The recommendation is 8 hours, but I think this is close enough -- just means you may have to run your pump a little longer than with a bigger pump.

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1 Answer

How much shock n swim for a pool 16 x42


What you appear to be asking is the volume of your Pool in gallons! Here is the formula and resulting answer:

Length X Width X average Depth X 7.5 (for rectangluar) (or 5.9 for a circle or oval)

You need to know 3 values:

The overall length in feet (assuming 42 on your note)
The overall Width in feet (assuming 16 on your note)
The average depth, take a depth measurement at 3-4 locations equally apart along the length from deep to shallow (or vice-versa) (example might 8ft, 6ft, 4ft, 3ft) add these measurements together and then divide the total sum by the number of depth measurements (example 4) this will be the average (example 5.25)

So the resulting formula would read 42 x 16 x 5.25 x 7.5 = 26,460 gallons for the example

So if your pool's average depth is about the same, then your volume is rounded to about 26,500

Your shock product should clearly state how much one bag will treat a given volume (example 10,000 gals) for regular treatment or shocking. Usually shocking involves doubling or even tripling the normal maintenance dosage, but check the product labels and instructions for manufacturer's recommendation.

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If all the chemicals are corrrect ... I suspect copper. Have you used a sequestering agent to remove the metals?

If it is not metal it is algae - increase the CH to at least 20 PPM and run the pump as long as you can (24/7 if your manufacturer will allow it).

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Depends on weather conditions, swim activity and if this is initial setup.
I use one bag per week

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