Question about Associated Toys
Posted by Anonymous on
Tips for a great answer:
Nov 19, 2017 | Omron Health & Beauty
Jul 12, 2017 | The Health & Beauty
Oct 10, 2014 | Invacare Supply Group Central Line...
Jul 24, 2014 | Garcinia Cambogia Burn 2 Bottles -...
Mar 24, 2014 | Computers & Internet
Dec 02, 2013 | Miscellaneous
Every associate leaves 4/5(n-1) molecules of a pile of n molecule. This result in an awful formula for the complete process (because every time one molecule must be taken away to make the pile divisible by 5):
4/5(4/5(4/5(4/5(4/5(4/5(p-1)-1)-1)-1)-1)-1), where p is the number of molecule in the original pile, must be a whole number.
The trick is to make the number of molecule in the pile divisible by 5, by adding 4 molecules. This is possible because you can take away those 4 molecules again after taking away one fifth part of the pile: normally, 4/5(n-1) molecules are left of a pile of n molecules; now 4/5(n+4) =4/5(n-1) +4 molecules are left of a pile of n+4 molecules. And because of this, the number of molecule in the pile stays divisible by 5 during the whole process. So we are now looking for a p for which the following holds:
4/5×4/5×4/5×4/5×4/5×4/5× (p+4) = (46/56) × (p+4), where p is the number of molecule in the original pile, must be a whole number.
Therefore, the smallest (p+4) for which the above holds, is 56.
So there were p=5 power 6 - 4 = 15621 molecule in the original pile.
Dec 16, 2010 | Cell Phones
Jun 14, 2010 | Computers & Internet
Oct 09, 2008 | 2002 Mercedes-Benz C-Class
Sep 17, 2008 | Kodak EASYSHARE 5300 All-In-One InkJet...
71 people viewed this question
Usually answered in minutes!
Step 2: Please assign your manual to a product: