(x-h)^2+(y-k)^2=r^2

where (h,k) is the centre of the circle and r is the radius of the circle.

Good luck.

Paul

Posted on Apr 04, 2015

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Posted on Jan 02, 2017

B. Equation of a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the centre of the circle and r is the radius.

May 01, 2015 | Miscellaneous

A. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, with (a,b) being the centre of the circle and r being the radius.

Good luck,

Paul

Good luck,

Paul

May 01, 2015 | Office Equipment & Supplies

Use the conics utility

Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

Jul 24, 2014 | Casio Office Equipment & Supplies

Use the conics utility

Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

Jul 24, 2014 | Casio Office Equipment & Supplies

The equation of a circle is (x-h)^2 + (y-k)^2 = r^, where h and k are the x and y coordinates of the centre of the circle. However the centre is the origin, so we have x^2 + y^2 = r^2.

Now, we need to figure out r. However, we can calculate r because it is the distance from the origin to (-6,2). We can use Pythagorean Theorum, a^2 + b^2 = c^2, were a is -6 and b is 2. We get 6^2 + 2^2 =c^2. c^2= 40.

Thus, the formula of the circle is x^2 + y^2 = 40.

Good luck.

Paul

Now, we need to figure out r. However, we can calculate r because it is the distance from the origin to (-6,2). We can use Pythagorean Theorum, a^2 + b^2 = c^2, were a is -6 and b is 2. We get 6^2 + 2^2 =c^2. c^2= 40.

Thus, the formula of the circle is x^2 + y^2 = 40.

Good luck.

Paul

Apr 14, 2014 | ixl.com

A circle is not a function and cannot be graphed in the regular y=screen. You can graph a circle in parametric mode.

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

Aug 01, 2009 | Texas Instruments TI-83 Plus Calculator

assuming the question is what is the circle equation?

and if (-2,2) is the center of the circle

the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5

from that we can see that the slope of the line is 2/5

And from the fact of perpendicular line we can say that the slope

of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2

radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:

-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following

Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=

SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25

and if (-2,2) is the center of the circle

the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5

from that we can see that the slope of the line is 2/5

And from the fact of perpendicular line we can say that the slope

of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2

radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:

-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following

Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=

SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25

Oct 26, 2008 | Casio FX-115ES Scientific Calculator

There is a circle on the door. When you have loaded the dishes, pour the detergent on the door to fill the circle and close the door.

Oct 18, 2008 | Equator 20 in. PLS600 Free-Standing...

You have two methods for drawing a circle on the FX-9750GPlus.

- Use the Conics graphing: The general equation of a circle is aX^2 + aY^2 + bX+cY+d=0
- Use the function graphing. But before you can do that you must transform the general equation (above) in such a way that you can write it as Y^2= X^2+EX+F. From this you can find the two branches Y1=SQRT(X^2+EX+F) and Y2=-SQRT(X^2+EX+F)

Oct 09, 2007 | Casio FX-9750GPlus Calculator

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