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Circle equation - Office Equipment & Supplies

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(x-h)^2+(y-k)^2=r^2
where (h,k) is the centre of the circle and r is the radius of the circle.

Good luck.

Paul

Posted on Apr 04, 2015

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Which equation is it a,b,c, or d?


B. Equation of a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the centre of the circle and r is the radius.

May 01, 2015 | Miscellaneous

1 Answer

An equation of the circle whose center is at(2,-3) and whose radius measures4 is it A, B, C or D?


A. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, with (a,b) being the centre of the circle and r being the radius.

Good luck,

Paul

May 01, 2015 | Office Equipment & Supplies

1 Answer

How do i graph a circle


Use the conics utility
Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.
51b277d6-95dd-4ee0-b9ac-d70af9f67831.png dcd3cce5-60f6-460e-9b7e-d4b3389f6f2d.png ab93170e-7199-417e-aa0d-4247d4482839.png 9881d30b-e071-4404-910f-13d4e8b13b8c.png

Jul 24, 2014 | Casio Office Equipment & Supplies

1 Answer

Graph a circle


Use the conics utility
Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.
51b277d6-95dd-4ee0-b9ac-d70af9f67831.png dcd3cce5-60f6-460e-9b7e-d4b3389f6f2d.png ab93170e-7199-417e-aa0d-4247d4482839.png 9881d30b-e071-4404-910f-13d4e8b13b8c.png

Jul 24, 2014 | Casio Office Equipment & Supplies

1 Answer

Write the equation in standard form for the circle passing through ( - 6,2) centered at the origin


The equation of a circle is (x-h)^2 + (y-k)^2 = r^, where h and k are the x and y coordinates of the centre of the circle. However the centre is the origin, so we have x^2 + y^2 = r^2.

Now, we need to figure out r. However, we can calculate r because it is the distance from the origin to (-6,2). We can use Pythagorean Theorum, a^2 + b^2 = c^2, were a is -6 and b is 2. We get 6^2 + 2^2 =c^2. c^2= 40.

Thus, the formula of the circle is x^2 + y^2 = 40.

Good luck.
Paul

Apr 14, 2014 | ixl.com

1 Answer

The calculator is only graphing a half circle when it should be a full circle, specifically not in the negative y-values of the plane.


A circle is not a function and cannot be graphed in the regular y=screen. You can graph a circle in parametric mode.

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

Aug 01, 2009 | Texas Instruments TI-83 Plus Calculator

1 Answer

Analytic geometry


assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2
radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25



Oct 26, 2008 | Casio FX-115ES Scientific Calculator

1 Answer

Where does the detergent go?


There is a circle on the door. When you have loaded the dishes, pour the detergent on the door to fill the circle and close the door.

Oct 18, 2008 | Equator 20 in. PLS600 Free-Standing...

1 Answer

Graphing circles


You have two methods for drawing a circle on the FX-9750GPlus.
  1. Use the Conics graphing: The general equation of a circle is aX^2 + aY^2 + bX+cY+d=0
  2. Use the function graphing. But before you can do that you must transform the general equation (above) in such a way that you can write it as Y^2= X^2+EX+F. From this you can find the two branches Y1=SQRT(X^2+EX+F) and Y2=-SQRT(X^2+EX+F)

Oct 09, 2007 | Casio FX-9750GPlus Calculator

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