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Log on to what/where? You obviously managed to log on to FixYa.

Posted on Dec 25, 2013

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Clean iron?

Hello tcant....
  • 1 Fill the iron's steam receptacle with white vinegar or CLR, a product used to clean coffee pots. CLR is available in department stores.

  • 2 Plug in and set the iron to its steam setting.
  • 3 Operate as usual. When the vinegar or CLR begins to steam, operate the iron as you would normally. Press it over an old, clean towel as the vinegar or CLR loosens sediment and dirt from the appliance.
  • 4 Continue ironing until all of the cleaning solution has steamed out. Repeat the cleaning process if necessary until the iron no longer oozes discolored liquid and the ironing surface is clean.
  • 5 Fill the iron steamer receptacle with distilled water and set the appliance to steam.
  • 6 Continue steaming until the smell of vinegar or CLR is gone.
  • 7 Prevent future mineral buildup by using distilled water for steam in your iron, rather than tap water. Joe. Thanks for choosing Fixya!
  • Jan 12, 2011 | Black & Decker ICR250 Iron with Auto...


    The Log function!!

    I calculators you can't change or set the base of 'log' is default 10 so you need to know these:

    log x (base y) = log x / log y

    when log x it's automatic log x (base 10) here some examples:

    log 8 (base 2) = log 8 / log 2
    log 27 (base 3) = log 27 / log 3

    and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

    log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

    here so other stuff about 'log' :

    log (x*y) = log x + log y
    log (x/y) = log x - log y

    Hope it's helped

    on Jul 07, 2009 | Casio fx-300ES Calculator

    1 Answer

    2log(base4)x + log(base4)3=log(base4)x-log(base4)2

    It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.
    Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

    2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

    Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

    2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2)

    which is equivalent to log(4,x) +log(4,3) = -log(4,2)

    Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

    log(4,x) = -log(4,2) -log(4,3) = - { log(4,2)+log(4,3)} = -log(4,2*3)

    You get log(4,x)= -log(4,6).

    Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

    Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain
    log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

    There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

    Hope it helps.

    Nov 25, 2009 | Casio FX-300MS Calculator

    2 Answers

    I need help with a change of base formula problem.

    It's simple here some logs:

    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    you just need to know that the default base of log in calculators is 10, so log x mean
    log x base 10 = log x / log 10,
    so write log x / log y for log x base y example:
    log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

    Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

    2 Answers

    How do you input a logarithm base into the ti83 plus?

    You can't it's default 10 so learn this logs:
    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    so just divide the logs
    hope it helps

    Jun 28, 2009 | Texas Instruments TI-83 Plus Calculator

    1 Answer

    How to calculate

    It's very simple: the calculators have a default base 10 so that log x it's log x base 10 so here is some logs:
    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    Hope it's helped

    Apr 09, 2009 | Sharp EL-520WBBK Calculator

    1 Answer

    To solve the problem using log

    Look the calculators has a default base 10 and you can't change it but you may learn this:
    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    so instead input log 8 base 2 you need to input log 8 / log 2
    your example answer is about 0.919... if i get right what did you write.
    Glad to help :)

    Feb 21, 2009 | HP 33s Calculator

    1 Answer

    Find log(1-.2)

    I don't get it but here some help with logs:
    log x base y = log x / log y (when log x is default base 10 in calculators) and
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    the bases is default 10
    hope it's helped

    Feb 05, 2009 | Casio FX-300MS Calculator

    1 Answer

    Logarithmic functions

    All calculators it's the same:
    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y
    the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2
    Hope you understand :)

    Dec 16, 2008 | Casio FX-7400G Plus Calculator

    1 Answer

    Using logs

    Here something that would help you:

    log x base y = log x / log y
    log (x*y) = log x + log y
    log (x/y) = log x - log y

    so log 24 base 2 it's log 24 / log 2 etc.
    and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

    Oct 23, 2008 | Casio FX-260 Calculator

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