Question about Sharp EL-531VB Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Callit disc.**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and **x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3. **If disc is negative, there are no real solutions.**

To find the solutions you **replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

Posted on Sep 17, 2009

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Posted on Jan 02, 2017

Hi there,

You cannot solve linear equations on a SHARP EL531. If you would like a calculator that solves equations, you need to get a SHARP EL W506

You cannot solve linear equations on a SHARP EL531. If you would like a calculator that solves equations, you need to get a SHARP EL W506

Apr 08, 2014 | Sharp el-531x scientific calculator

There is some confusion here.

In stat mode [Quad] the calculator tries to fit a quadratic function to your (already entered) data. It gives you the coefficients a, b, and c of the 2nd degree polynomial that best describes the data.

To solve an equation you need to use the**solver **not statistics.

In stat mode [Quad] the calculator tries to fit a quadratic function to your (already entered) data. It gives you the coefficients a, b, and c of the 2nd degree polynomial that best describes the data.

To solve an equation you need to use the

Jun 11, 2013 | Sharp el-531x scientific calculator

The quadratic equation is (-b(+or-)sqrt(b^2-4ac))/2a

Sep 11, 2011 | Sharp ELW535 Calculator

This calculator does not have an Equation solver, so it cannot solve any equation.

Feb 02, 2011 | Sharp ELW535 Calculator

Sorry, it does not solve equations, quadratic or otherwise.

Jan 26, 2011 | Sharp ELW535 Calculator

This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation **5x^2+15x+3 =0**

This calculator cannot solve equations because it does not have an equation solver.

This calculator cannot solve equations because it does not have an equation solver.

Dec 15, 2010 | Sharp ELW535 Calculator

No solution, but I have the exact same problem with a Sharp EL-531W calculator. Doesn't matter whether mode is degrees, radians, etc., and resetting with button in back has no effect.

Feb 26, 2010 | Sharp EL-501WBBL Calculator

Hello,

In your manual, Appendix Program Library, (Page A1) you have the listing of the problem to solve the quadratic equation. Type it in your calculator and execute it.

Hope it helps.

In your manual, Appendix Program Library, (Page A1) you have the listing of the problem to solve the quadratic equation. Type it in your calculator and execute it.

Hope it helps.

Aug 13, 2009 | Casio FX-9750GPlus Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and**x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3.**If disc is negative, there are no real solutions.**

To find the solutions you**replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then

and

2.

3.

To find the solutions you

Hope it helps.

Jun 26, 2009 | Sharp EL-531VB Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and**x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3.**If disc is negative, there are no real solutions.**

To find the solutions you**replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then

and

2.

3.

To find the solutions you

Hope it helps.

May 05, 2009 | Sharp EL-531VB Calculator

Apr 24, 2014 | Sharp EL-531VB Calculator

Apr 24, 2014 | Sharp EL-531VB Calculator

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