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Posted on Jan 02, 2017

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Sep 24, 2016 | PayPal Accounts

I calculators __you can't__ change or set the base of 'log' is __default 10__ so you need to know these:

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped**☺**

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped

on Jul 07, 2009 | Casio fx-300ES Calculator

you would need to in paypal go to mypaypal and select bank account and cards then add bank account and fill in your checking account details

Mar 03, 2015 | PayPal Computers & Internet

This is a question for PayPal itself, not for a forum like this. No one here has any way of knowing why PayPal made a charge. Log in to https://www.paypal.com/home and then click on the MyPayPal button. This should show you your PayPal transactions (if necessary, click the View All link below your list of recent transactions.

Mar 02, 2015 | PayPal Computers & Internet

Please don't just post questions which have already been answered.

Alright, here's how:

Alright, here's how:

Dec 22, 2013 | Facebook Social Network

Hi,

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

**2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2) **

which is equivalent to**log(4,x) +log(4,3) = -log(4,2)**

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =**- { log(4,2)+log(4,3)}** = -log(4,2*3)

You get**log(4,x)= -log(4,6)**.

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

which is equivalent to

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =

You get

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

Nov 25, 2009 | Casio FX-300MS Calculator

There is no need for developement Vista will support many users. You will want to get a list ready of users then you have some work to do in order to administer them.

Login as Administrator

Go to Control Panel

Click on User Accounts and start adding users. Becareful here make sure that you make all the user accounts private so that nobody else can access each others information.You will also want to make sure that all user accouonts are at the User level not Administrator. You can assigne each user the same generic password as the Administrator giving the option to the user to create their own on first login.

The method of doing so will be as follows:

Once you have completed creating all the users accounts you will want to go back to Control Panel then select Administrative tools

Then Double Click on Computer Management on the left you will see a catagory called Users and Groups expand the list and select users. Now you will need to go through each of the users that where created and double click on them one at a time on the General tab you will take the check mark out of Account never expires then you will add a check mark to User must change password at next logon. This way your users can select a password that they will remember.

Ther is some work in administering this however as people will forget their password and such. Good Luck!

Login as Administrator

Go to Control Panel

Click on User Accounts and start adding users. Becareful here make sure that you make all the user accounts private so that nobody else can access each others information.You will also want to make sure that all user accouonts are at the User level not Administrator. You can assigne each user the same generic password as the Administrator giving the option to the user to create their own on first login.

The method of doing so will be as follows:

Once you have completed creating all the users accounts you will want to go back to Control Panel then select Administrative tools

Then Double Click on Computer Management on the left you will see a catagory called Users and Groups expand the list and select users. Now you will need to go through each of the users that where created and double click on them one at a time on the General tab you will take the check mark out of Account never expires then you will add a check mark to User must change password at next logon. This way your users can select a password that they will remember.

Ther is some work in administering this however as people will forget their password and such. Good Luck!

Sep 21, 2009 | Computers & Internet

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

I don't get it but here some help with logs:

log x base y = log x / log y (when log x is default base 10 in calculators) and

log (x*y) = log x + log y

log (x/y) = log x - log y

the bases is default 10

hope it's helped

log x base y = log x / log y (when log x is default base 10 in calculators) and

log (x*y) = log x + log y

log (x/y) = log x - log y

the bases is default 10

hope it's helped

Feb 05, 2009 | Casio FX-300MS Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

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