Question about Computers & Internet

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Hi,

please don't ever ask this question again. The solution is below the further written text :).

Deadline - 01.01.14. Until that time I will answer questions regarding Outlook.com, Google( Gmail), Facebook login problems. The solutions can be found on my FixYa profile page or using search.

*Solution:*

Posted on Nov 22, 2013

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Posted on Jan 02, 2017

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Point your web browser at Welcome to Facebook Log In Sign Up or Learn More

If another account comes up, log out of it by clicking the down-pointing triangle in the upper-right then clicking "Log Out."

If you then still can't log in to your account, click the "Forgot your password?" link located just below the password box on the login page.

If you're getting an error message, what does it say?

If another account comes up, log out of it by clicking the down-pointing triangle in the upper-right then clicking "Log Out."

If you then still can't log in to your account, click the "Forgot your password?" link located just below the password box on the login page.

If you're getting an error message, what does it say?

Feb 04, 2015 | Facebook Computers & Internet

I calculators __you can't__ change or set the base of 'log' is __default 10__ so you need to know these:

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped**☺**

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped

on Jul 07, 2009 | Casio fx-300ES Calculator

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id:minato722

email:minato7222yahoo.com

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email:minato7222yahoo.com

Dec 16, 2013 | Computers & Internet

Offer you the following link:

http://www.facebook.com/help/136465059824353/

http://www.facebook.com/help/136465059824353/

Nov 11, 2013 | Computers & Internet

http://www.filebuzz.com/fileinfo/87599/Facebook_Login.html

Facebook Login software is freeware specially designed for Facebook browsing.

This simple application has many features for you. Application is more speeder and secures Facebook browsing than your normal...

If your Facebook profile is still unavailable after many days, then send an email to

info@facebook.com,

appeals@facebook.com

or

disabled@facebook.com

and explain them the issue.

http://www.facebook.com/help/?page=121467344601554

Once you send them an email, your account will be available again soon.

Facebook Login software is freeware specially designed for Facebook browsing.

This simple application has many features for you. Application is more speeder and secures Facebook browsing than your normal...

If your Facebook profile is still unavailable after many days, then send an email to

info@facebook.com,

appeals@facebook.com

or

disabled@facebook.com

and explain them the issue.

http://www.facebook.com/help/?page=121467344601554

Once you send them an email, your account will be available again soon.

May 04, 2013 | Computers & Internet

You may have a virus. Try cleaning your computer with anti-virus software. Avast or AVG are free.
Hope this helps

Apr 07, 2011 | Computers & Internet

Hi,

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

**2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2) **

which is equivalent to**log(4,x) +log(4,3) = -log(4,2)**

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =**- { log(4,2)+log(4,3)}** = -log(4,2*3)

You get**log(4,x)= -log(4,6)**.

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

which is equivalent to

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =

You get

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

Nov 25, 2009 | Casio FX-300MS Calculator

You may be behind a network or firewall that is blocking access to facebook. You should try accessing the site through a Facebook Proxy Server. I know of two really good ones, Facebook Login Proxy and Facebook Proxy Sever.

If this dosn't help you can find more Facebook login help at www.facebooklogin.net .

If this dosn't help you can find more Facebook login help at www.facebooklogin.net .

Sep 28, 2009 | Facebook Social Network

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

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