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Quadratic functions whatis the equation of te quadratic function if the vertex is 8,-4 and a= -2

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Y=aX^2+bX+c

The x-coordinate of the vertex is given by
X_v=-b/2a
With a=-2, and X_v=8 you have b=-2a*X_v=-2(-2)*8=32
The equation can now be written as y=-2X^2+32X+c
To get c you substitute the value of X_v in the equation above and you set the result equal to Y_v=-4
-2(8)^2+32(8)+c=-4
Solve for c
c=-4+128-256=-132
y=-2X^2+32X-132

Posted on Nov 21, 2013

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Posted on Apr 04, 2009

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