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Posted on Jan 02, 2017

I would say that the answer would be 11!/2

Feb 13, 2017 | Homework

this is covered in the theory of probability formula

to get the answer go google and type in theory of probability and the formula and explanation are on the pages

to get the answer go google and type in theory of probability and the formula and explanation are on the pages

Aug 31, 2015 | Kitchen Ranges

I assume that repetition of numbers can't happen, and the order of numbers does not matter

So it is n! / (r! (n-r)!)

= 15! / (5! (15-5)!)

= 1307674368000 / (120 (3628800)

= 3003 combinations

So it is n! / (r! (n-r)!)

= 15! / (5! (15-5)!)

= 1307674368000 / (120 (3628800)

= 3003 combinations

Feb 13, 2015 | Computers & Internet

Too many to list (3,125). It would take you forever to get it unlocked. I would suggest bolt cutters and just spend the 20-30 bucks to buy a new one.

Aug 22, 2014 | Kensington Black Portable Combination Loc

On any SHARP scientific calculator the combination button is always above the 5 (except the financial calculator). To get a combination type in the n value (the total number of items) press 2nd F and the 5 button and then type in the number of selected items and press =.

May 29, 2014 | Sharp EL-531VB Calculator

That depends on how many of those six numbers you take.

If you only take one number, there are six combinations: {1}, {2}, {3}, {4}, {5}, and {6}.

If you take two numbers, there are fifteen combinations: {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,3}, {2,4}, {2,5}, {2,6}, {3,4}, {3,5}, {3,6}, {4,5}, {4,6}, and {5,6}.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination: {1,2,3,4,5,6}.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

If you only take one number, there are six combinations: {1}, {2}, {3}, {4}, {5}, and {6}.

If you take two numbers, there are fifteen combinations: {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,3}, {2,4}, {2,5}, {2,6}, {3,4}, {3,5}, {3,6}, {4,5}, {4,6}, and {5,6}.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination: {1,2,3,4,5,6}.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

Apr 30, 2013 | Mathsoft Computers & Internet

That depends on how many of those six numbers you take.

If you only take one number, there are six combinations.

If you take two numbers, there are fifteen combinations.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

If you only take one number, there are six combinations.

If you take two numbers, there are fifteen combinations.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

Apr 30, 2013 | Home Security

How to calculate 8!/(5!3!)?

For small numbers (8,5,3) you can use the factorial function key (I will tell you later how to access it) and enter 8! divided by 5!, divided by 3! For numbers greater than or equal to 70 you cannot calculate the factorial: the result is too large for the calculator's memory.

However the formula you wrote is an instance of a combination 8C5 or 8C3 (they have the same value.

Most scientific calculator have three functions: the n Factorial n!, the Combination function nCr and the permutation function nPr.

**That is the factorial.**

The tab (F2) is marked nPr is for the**permutations**

The tab (F3) is marked nCr and it corresponds to the**combinations**.

To use**nPr or nCr** you enter the larger number n, you press the F key under nPr or nCr. If you press F2 you see a fat P, if you press F3 you see a fat C. Complete by entering the value of r (the smaller number)

If your problem corresponds to Select 8 objects, 5 at a time regardless or order (combinations) you type 8 F3 5 and EXE Result is 56.

For small numbers (8,5,3) you can use the factorial function key (I will tell you later how to access it) and enter 8! divided by 5!, divided by 3! For numbers greater than or equal to 70 you cannot calculate the factorial: the result is too large for the calculator's memory.

However the formula you wrote is an instance of a combination 8C5 or 8C3 (they have the same value.

Most scientific calculator have three functions: the n Factorial n!, the Combination function nCr and the permutation function nPr.

- Turn Calculator ON
- Select the Run icon and press EXE.
- In Run Screen Press the OPTN key
- Press F6> to pan to the other tabs
- Press F3:Prob

The tab (F2) is marked nPr is for the

The tab (F3) is marked nCr and it corresponds to the

To use

If your problem corresponds to Select 8 objects, 5 at a time regardless or order (combinations) you type 8 F3 5 and EXE Result is 56.

Aug 31, 2012 | Casio CFX 9850GA Plus Calculator

You can't make the alternate characters like °, ®, ♂, σ etc with a combination number pad. You need to have a seperate number pad. I use a $20 plug in keyboard.

Oct 29, 2009 | Dell Latitude D505 Notebook

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