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Let just wait a minute. You have an inverter that is rated at 4500 watts.
This spooky. The inverter has a three phase input/three phase output? What is
the inverter going to be used for?
Next question. What type of batteries are you using and what is the
voltage/current in series or parallel? What will be the total voltage you will
producing with the batteries? What is the total current of the batteries.
Another question? What is the voltage of the 28 amps? If it going to dump 28
amps across some batteries that rated at 12 volts and 1400 amp/hrs. For 12 volt batteries with a total of 1400 amps. What you will
need approx 14 to 14 1/2 DC and with 28 amps across the batteries for charging
these batteries. The batteries will be gone in about 1 hour. Boil all the water
out of them. When a battery starts to boil it release water with hydrogen gas
(the gas is very explosive and dangerous).
You also don't have a regulation circuit to limit the amount of current
depending on the needs of the batteries. Also, you don't have a trickle charger
to keep the batteries fully charge when the batteries are idle.
You will also need DC regulated charger that will keep the voltage 2-4 volts
above you battery voltage. Without this voltage above the batteries voltage it
will not charge those batters. Batteries need to forced to except a charge
that why voltage above the source voltage. If you can check the voltage on your
car/truck with a 12 volt system. While engine is running the voltage across the battery
will be 13.8 to 14.1 volts. Now, the current limiter is the alternator it has a
regulator built into it for stabiizing voltage and current went the batteries
require more current but it limited by alternator regulator
Now, to get more current out of the alternator the regulator will supply dc
voltage to the stator of the alternator generator more current. More dc voltage
is supplied by the regulator but the dc voltages is limit to about 24 volts.
Another limiting factor is the alternator copper windings diameter---larger
diameter more current, small diameter less current. Utilities systems use big
mega watts generators. The maxi um dc voltage for these three phase generator
would like 500 to 800dc volts for peak to peak output. There is a simpler way of
You need to rethink everything here. Also, I can help you if you supply the
I truly wish you luck in your electrical endeavors. GB you. stewbison
Ohm's law tells us that: volts = amps x resistance and watts =volts x amps. Watts (300) = volts (240) x Amps (?); or 300 / 240 = 1.25 Amps That means the inverter can supply up to 1.25 Amps to a 240 volt load.
The primary is 12 volts, this is just 1/20th of the secondary 240 volt output. Since the best you can ever get is 100% efficiency -this means you'll need to supply 20 times the current. 1.25 Amps (at 240V) x 20 = 25 Amps (at 12V). As a check, from above Ohm's law that states Watts=Volts X Amps we get: 12VDC x 25Amps = 300Watts. Check!
Some side notes. The Ohms law used above is for DC circuits and purely resistive loads on AC circuits. I do not know what your 1.25 A @ 240VAC load is - but I suspect it won't be purely resistive. Also, since we're working with an electronic inverter as opposed to a transformer and DC rectifier there are some things that push losses higher. You might need to provide a 30 Amp 12 VDC source voltage in order to provide the 1.25A @ 240VAC output. Lastly, I wouldn't not run the output at maximum for long periods of time - or at all. 1 Amp @ 240VAC would be much better.
I hope this answered your question & good luck! Please rate my reply - thank you.
Your inverter has a peak of 3000 watts rating and should power that hair dryer. Make sure your batteries are in good shape. The inverter can only put out what it takes in. 1800 watt demand on the inverter requires 1800 watts from the batteries.
400 watts delivered to 300 watt speakers the only way to do this would be to wire two subwoofers in series so that the power needed to drive them will be 600 watts to max, however this will increase your impedance on the speaker (8 ohms) load so what you can do to compensate is get an 8 ohm 600 watt resistor and put it in parallel with the speakers you will then have 4 ohms of impedance at a total capacity of 600 watts of power
In other words the amplifier won't blow these out now.