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Posted on Jan 02, 2017

SOURCE: find three consecutive even integers if five times

try this website:

http://www.homeworkspot.com/

Posted on Sep 15, 2010

SOURCE: the smallest of 3 consecutive odd integers is

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24

=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Posted on Jan 17, 2011

SOURCE: Two consecutive even integers such that the

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Posted on Sep 15, 2011

SOURCE: find three consecutive odd integers whose sum is

if the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers

Posted on Sep 21, 2011

Let x be the smallest number.

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

129

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Jan 16, 2015 | Mathematical Technologies Inc. MTI Tristan...

Let x be first (smaller) integer and y second (larger) integer.

These two numbers are 20 and 22.

- They are consecutive (and even) : y=x+2
- Twice the smaller exceeds the larger by 18: 2*x=y+18
- Substitute first equation into second: 2x=x+2+18
- 2x-x=2+18
- x=20
- y=x+2=22

These two numbers are 20 and 22.

Oct 03, 2011 | Office Equipment & Supplies

Of course it is 3 and 4! Are you testing our knowledge friend? ; )

Sep 18, 2011 | Casio FX82MS Scientific Calculator

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

X + ( X + 2 ) + ( X + 4 ) = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

try this website:

http://www.homeworkspot.com/

http://www.homeworkspot.com/

Sep 15, 2010 | Lufkin C213C 600" x 38" Long Consecutive...

2n = 1st even integer

2n + 2 = 2nd even integer

Product = 2n(2n + 2) = 4n^2 + 4n = 4(n^2 + n)

1520 = 4(n^2 + n)

1520/4 = 4(n^2 + n)/4

380 = n^2 + n

0 = n^2 + n - 380

0 = (n + 20)(n - 19)

n = -20, +19

Answer can not be negative so n = +19

2n = 2(19) = 38

2n + 2 = 2(19) + 2 = 40

ANSWER: the integers are 38 and 40

2n + 2 = 2nd even integer

Product = 2n(2n + 2) = 4n^2 + 4n = 4(n^2 + n)

1520 = 4(n^2 + n)

1520/4 = 4(n^2 + n)/4

380 = n^2 + n

0 = n^2 + n - 380

0 = (n + 20)(n - 19)

n = -20, +19

Answer can not be negative so n = +19

2n = 2(19) = 38

2n + 2 = 2(19) + 2 = 40

ANSWER: the integers are 38 and 40

Nov 16, 2009 | RCA HD52W59 HDTV Projection Television

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