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The product of two consecutive integers is less than the square of the smaller integer. Find the larger of the two integers.

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Posted on Jan 02, 2017

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SOURCE: what is the answer of this math problem:

5 & 7

Posted on Oct 11, 2009

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SOURCE: find three consecutive even integers if five times

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Posted on Sep 15, 2010

  • 457 Answers

SOURCE: the smallest of 3 consecutive odd integers is

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24
=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Posted on Jan 17, 2011

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SOURCE: Two consecutive even integers such that the

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:
x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Posted on Sep 15, 2011

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SOURCE: find three consecutive odd integers whose sum is

if the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers

Posted on Sep 21, 2011

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1 Answer

Find the smallest two consecutive even integers such that three times the smaller is at least 19 more than the sum of the two integers


Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44






Feb 19, 2015 | Office Equipment & Supplies

1 Answer

Find two consecutive even integers such that twice the smaller exceeds the larger by 18.


Let x be first (smaller) integer and y second (larger) integer.
  1. They are consecutive (and even) : y=x+2
  2. Twice the smaller exceeds the larger by 18: 2*x=y+18
  3. Substitute first equation into second: 2x=x+2+18
  4. 2x-x=2+18
  5. x=20
  6. y=x+2=22

These two numbers are 20 and 22.

Oct 03, 2011 | Office Equipment & Supplies

1 Answer

Two consecutive even integers such that the smaller added to three times the larger gives a sum of 22


We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:
x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

2 Answers

Find three consecutive odd integers whose sum is 105


X + ( X + 2 ) + ( X + 4 ) = 105
3X + 6 = 105
3X = 105 - 6
3X = 99
X = 99/3
X = 33
So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

1 Answer

Find two consecutive even integers whose product is 1,520


2n = 1st even integer
2n + 2 = 2nd even integer

Product = 2n(2n + 2) = 4n^2 + 4n = 4(n^2 + n)
1520 = 4(n^2 + n)
1520/4 = 4(n^2 + n)/4
380 = n^2 + n
0 = n^2 + n - 380
0 = (n + 20)(n - 19)
n = -20, +19

Answer can not be negative so n = +19

2n = 2(19) = 38
2n + 2 = 2(19) + 2 = 40

ANSWER: the integers are 38 and 40


Nov 16, 2009 | RCA HD52W59 HDTV Projection Television

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