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I don't know if the problem you are having is with one web site or several but if just one web site is affected then you should be able to find your way to the section of the login screen that helps with logging in ... it usually says something like "I can't log in" or "I forgot my password".

Try going through their process for resetting your password. If that doesn't work (the web site itself might be experiencing problems) then your next step is to contact the company support department either through email, chat or phone. They may be able to provide additional insight about current system problems or simply handle the password reset for you.

A few other things to consider ...

A virus might cause a problem with accessing or logging in to a web site. Run a complete system scan if you haven't done so in a while.

If you are running Microsoft Windows, your Hosts file could have been compromised. You'll need to do some research to learn more about the Hosts file. There are plenty of online resources that will teach you everything you need to know ... it is too complex of a subject to cover here.

Try switching temporarily to a different DNS. OpenDNS and Google are two good alternatives to your ISP's DNS.

Did you recently install new software? This could be especially important if it is anti-virus or anti-malware software as they sometimes conflict with network operation. If so try uninstalling the software or doing a Windows Restore to a restore point created at a time before the software was installed.

Temporarily disable your firewall - especially if it is not the default Windows firewall.

Reset your router. I don't mean just power off/on - push the reset button if there is one. Keep in mind that this will also reset the wireless password and the router control menu password so make sure you know how to access the router configuration menu to set those things back up if you do a reset.

Posted on Oct 20, 2013

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Hi,

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Posted on Jan 02, 2017

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1 EE 14 LOG / 2 +<>- =

Jun 25, 2010 | Texas Instruments TI-30XA Calculator

Hi,

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

**2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2) **

which is equivalent to**log(4,x) +log(4,3) = -log(4,2)**

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =**- { log(4,2)+log(4,3)}** = -log(4,2*3)

You get**log(4,x)= -log(4,6)**.

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

which is equivalent to

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =

You get

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

Nov 25, 2009 | Casio FX-300MS Calculator

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

You can't it's default 10 so learn this logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so just divide the logs

hope it helps

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so just divide the logs

hope it helps

Jun 28, 2009 | Texas Instruments TI-83 Plus Calculator

It's very simple: the calculators have a default base 10 so that log x it's log x base 10 so here is some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped

Apr 09, 2009 | Sharp EL-520WBBK Calculator

Look the calculators has a default base 10 and you can't change it but you may learn this:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

Feb 21, 2009 | HP 33s Calculator

I don't get it but here some help with logs:

log x base y = log x / log y (when log x is default base 10 in calculators) and

log (x*y) = log x + log y

log (x/y) = log x - log y

the bases is default 10

hope it's helped

log x base y = log x / log y (when log x is default base 10 in calculators) and

log (x*y) = log x + log y

log (x/y) = log x - log y

the bases is default 10

hope it's helped

Feb 05, 2009 | Casio FX-300MS Calculator

All calculators it's the same:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2

Hope you understand :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2

Hope you understand :)

Dec 16, 2008 | Casio FX-7400G Plus Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

Feb 25, 2018 | Computers & Internet

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Feb 25, 2018 | Computers & Internet

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