Question about Broderbund PrintMaster Homework Helpers for PC (385015)

# Words with palindrome - Broderbund PrintMaster Homework Helpers for PC (385015)

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## Related Questions:

### What is the palindrome of 49

palindromic numbers are simply ones that are the same if you right them normally or backwards 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, ...

A number is a palindrome or not, 49 is not one.

Sep 14, 2014 | Cars & Trucks

### What are palindromes? (words for kids)

Words of groups of words which, if spelled in reverse (with optional punctuation changes), are unchanged. Examples: "madam" or "racecar", or the old famous quote "Madam, I'm Adam".

Jul 10, 2014 | Games

### What's a palindrome

A word or phrase that reads the same backwards as forwards. See http://en.wikipedia.org/wiki/Palindrome

May 25, 2014 | Computers & Internet

### I am also a palindrome.I am greater than the number of days in a year and less than the product of 19 and 20.What number am I?

the answer is between 356 and 380. a palindrome is a word or phrase that reads the same backward as forward. my guess would be 363.

Aug 10, 2010 | Capcom Zack and Wiki Quest for Barbaros'...

### 18. A palindrome is a string that reads the same

here is a little vbscript sample str=InputBox("Type String To check For palindrome","")
strR=StrReverse(str)
half=Int(Len(str)/2)
If Left(str,half)=Left(strR,half) Then
MsgBox ("It's a palindrome string")
Else
MsgBox ("It's not a palindrome string")
End If

Jun 05, 2010 | Computers & Internet

### To find palindrome

// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
break;
if (i==halflen)
palindrome=true;

Mar 21, 2009 | Sun Java Desktop System

### To print palindrome

// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
break;
if (i==halflen)
palindrome=true;

Mar 21, 2009 | Intel Computers & Internet

### Help me javascript just mail me at ramzy_213@yahoo.com thanx

hello there!!!
First things First !
1) download the ultimate JAVA APL. run again.
O S

Feb 19, 2008 | Audio Players & Recorders

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